Very interesting video! Would you be able to share with me the geometric and trigonometric equations you used to derive the design in this video? Also, do you know of any websites or documents that I can find which detail the mathematical design of similar Aperture Iris Diaphragms? I have scoured the internet for any information on the geometric/math equations used for such a design and have found nothing. Thanks!
@patrickazonzo
5 жыл бұрын
It's so strange that informations about this topic are so obscure and impossible to find. I'm happy to find another person that is interested in this stuff, have you found any other informations in regard of this topic, like formulas or some kind of way to calculate it?
@RickHoefer89
5 жыл бұрын
Hello Patrick, I’m happy to find someone else interested in aperture design as well! Your right, I’ve scoured the internet and patents for any equations relating to the design of similar diaphragms. After I came up with nothing, I decided to derive some of my own. I used screenshots of this video and some others I found in conjunction with an image editing program to figure out the process used to create the designs. I have the list on my MacBook, as soon as I get home I’ll copy and paste it as a reply. Cheers!
@patrickazonzo
5 жыл бұрын
Wow, i've been searching for information for months now and i've found just useless patents, hints to the process of realization or mostly models made without any real description. I though about trying to formulate something by myself but i really can't figure out a solid relation with values. Thank you in advance, you really could be the answer to this so strangely difficult problem.
@RickHoefer89
5 жыл бұрын
Hello @@patrickazonzo , sorry for the wait, I just got home. Im going to copy and paste the procedure I created based on the design process in the video. Its a bit messy, and Im working on finishing up a different approach which I think will be a bit easier. n-Bladed Iris Aperture Design Process: n = number of blades r = Smaller Circle Radius R = Larger Circle Radius Center pt of r/R circle = p0 Cr = r circle CR = R circle Example based on video: (n=7, r=3 cm, R=5 cm) The use of parenthesis in each step indicates the name of the element created during that step. Each element is composed of two parts; -> prefix=letter, represents type of element: p=point, L=line, C=circle, -> suffix= number, order in which element is made; can also be hyphenated for related points examples: create point on x axis (p1), duplicate point p1 (p1-2), create line from p1-2 to p1 (L1) Steps: 1 => Create point on CR circle at 0 degrees relative to center (p1) 2 => Create a point on Cr circle (p2) , draw line from p1 to p2 (L1) Angle from p1 to p2 = 26.81 Angle From p0 to p1 = 104.4 (approx 2*(360/n)) 3 => Create Circle (C1) originating @ p1 to p0 w/ radius equal to R 4 => Create Circle (C2) Originating @ p1 intersecting p2 5 => Make pt (p3) at lower intersection of Cr and C1 6 => Measure Angle based on p1 between p0 and p3 Use above angle originating at p1 downwards from p2 along C2 and make p4 7 => Make line from p4 to p1 (L2) and make a pt (p5) where L2 intersects Cr 8 => Measure clockwise angle (360/n) between p0 originating at p5 Make pt (p6) on Cr where above angle intersects Cr 9 => Measure counter c-wise angle between p3 and p0 originating at p1 duplicate pt6 and rotate it c-wise by above angle based on p1 (p6-2) 10 => Create arbitrary pt (p7) on C2 below p2 (about 12 counter c-wise from p2 measured from p1) 11 => Create pt (p8) where L1 and Cr Intersect (close to p1) 12 => Measure counter c-wise angle between p2 and p7 based on p1 duplicate p8 (p8-2) and p6-2 (p6-3) and rotate both counter c-wise by above angle based on p1 13 => Draw line (L3) from p7 to p8-2, and create pt (p9) @ midpoint of L3 14 => Create Line (L4) perpendicular to L3 based on p9 15 => Create pt (p10) where C1 and L4 intersect 16 => Create circle (C3) based on pt10 intersecting p7 Should create arc between p7 and p8-2 Delete Parts of circle C3 aside from the arc 17 => Delete L4, L3, and p9 (midpoint pt) 18 => Create circle C4 with center pt based on intersection between arc and C1 intersecting p6-3 19 => Make Line (L5) from p1 to p8-2; create pt (p11) where C4 and L5 intersect 20 => Delete circle C4 except for arc between p11 and p6-3 21 => Create Line (L6) between blade tip and p6-3, create midpoint (p12) on line L6 22 => Create Line (L7) perpendicular to line L6 at midpoint of L6 23 => Create pt (p13) along L7 above midpoint: distance from mid point to p13 = 0.374 * (length of L6) = Sagitta 24 => Create Arc from blade tip to p6-3, intersecting p13 Radius of final arc = approx 1.18*r, center of arc circle is along L7 located (0.755*Arc’s radius) below midpoint. Then Delete midpoint (p13), L6 , and L7 Sorry its a bit long and complex; the creator in the video uses some arbitrary values which I could not quite reconcile. Its much easier to understand if you follow along with the video. Anyway, Im in the process of finishing up a derivation based on a different video, where I measured the center points and tangents of the circles representing the radii of the various elements (outer blade radius, inner blade radius, etc) and then plotted the positions of these points as the iris dilated in order to interpolate the equations of their movement. I started it a few months ago but never finished it; Im going to try to wrap it up in a few days and send it to you. Cheers!
@patrickazonzo
5 жыл бұрын
Thanks @Rick Hoefer !!! As soon as i read your comment i started drawing, and after 1 hour i succeded. It has been quite rough to understand each step, but with the help of the video and your guide i've drawn working blades! I'll wait with excitement your new instructions, i guessed it had something to do with the other circles like the curved part of the blades or their motion but i never really understood how to find the right correlations. Good luck with your studies!!! On the internet i've found different kinds of Iris Diaphragms, not just the version like this in the video with overlapping blades. What can you say about the version where the blades fully close and do not intersect (an example bit.ly/2InPaTZ ). Do you know any other metods to design such type of diaphragm? (i'm asking because this variant seems easier to draw)
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