Very educative, thank you. Please do more this kind videos.
@andreipopov350
4 жыл бұрын
Thank you for all your hard work!! Please continue to do more!!!!
@vincei4252
4 жыл бұрын
Another great presentation. Thank you!
@electronicssciencebysherry5050
4 жыл бұрын
Thank u so much Sir 4 me I need more videos on amplifiers please make me more
@rayanrayan4737
4 жыл бұрын
Thank u so much MR 😊😊
@enriquevarela8616
4 жыл бұрын
great video ,thanks
@williamhazelwood8288
4 жыл бұрын
That schematic is triggering my OCD, otherwise good overview of operation. (although it is layout representative).
@davidluther3408
4 жыл бұрын
ITS TRIGGERING MY OCD EVEN WORSE!
@winsrrow8125
3 жыл бұрын
Why u draw the flow in the electrons direction instead of the more common conventional way? I mean, u draw from - to + but anyone else draw it from + to -
@TheOffsetVolt
3 жыл бұрын
It's the way many tech schools taught electronics, and many continue to do so. Universities teach conventional flow of course. Since the channel is for people new to the field like techs and hobbyists, I stuck with electron flow.
@winsrrow8125
3 жыл бұрын
@@TheOffsetVolt oh, ok, im learning the conventional at university, that's why I've asked, but really doesn't matter which one to use are essentially the same. I really appreciate ur videos, they are pretty well explained, more than my teacher's classes if i had to say.
@wojciechbartczak3109
4 жыл бұрын
I'm just wondering. Isn't that voltage-shunt feedback amplifier? Since I see here a feedback through R47. It would explain why the resistance is so high (470k). I would expect that the input is seeing around 2k input impedance. The whole schematic then is just a VAS (voltage amplification stage) and then current amplification stage (pull-push output). But, I might get this wrong, since feedback amplifiers is kind of Achilles' heel for me.
@davidluther3408
4 жыл бұрын
THE 26MV DROP INVOLVES USING DIFFERENTIAL CALCULUS ON THE SHOCKLEY DIODE EQUATION BY TAKING THE DERIVATIVE AND,PERFORMING ALGE BRIAC SUBSTUTIONS.FOR MOST OF US IT BETTER TO JUST ACCEPT THIS CONSTANT.
@MrGuano11
4 жыл бұрын
How can the NPN configuration conduct on the positive cycle? Wouldn't D5 just block the voltage from getting to Q11's base?
@davidluther3408
4 жыл бұрын
NO BECAUSE IT IS A CURRENT MIRROR.
@fantozzi30
Жыл бұрын
I just can't understand why resistors R50 and 51are in the path of the "100"uA current instead of "10"mA? When Transistors Q13 and Q14 overlap each other, there will be a direct unprotected short btw. Vdc and GND... Anyone??
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