Hi. Sorry, what happened? It got cold 2 minutes in?
@Namo_Amitabha2024
5 ай бұрын
@@owl3math I mean I'd shiver if I'm asked to solve this within 2 minutes.
@owl3math
5 ай бұрын
@@Namo_Amitabha2024 ah yes me too! Too much going on here! :)
@VenusianJungles
4 ай бұрын
Why @1:35 does the exponential in the integral of -inf to 0 become exp(-π(-x))? Isn' t the absolute value around the x and so even if its the negative half of the domain it should be positive x? Thanks
@owl3math
4 ай бұрын
Hi Tom. This is because of the property |x| = -x when x < 0. So for example when x = -3 then |x| = 3. So yes it will still always return a positive value.
@theupson
4 ай бұрын
im sorry, you handled this pretty clumsily. from 3:14 (and for petes sake the evenness symmetry doesn't take so much explanation), you should partition it along the integers. THEN you use the sub u = pi (x-n). that gets you to a better place than 9:39 in the video in 2 easy steps, given that |sin(x)| has period pi that recurring crappy integral e^x*sin(x)... never fricking humor your math prof by using integration by parts. e^x*sin(x) = im e^((i+i)*x), fast clean and painless.
@renesperb
20 күн бұрын
MATHEMATICA gives the answer Coth[π/2]/π , numerical value 0.347 ...,whereas your answer gives 0.904... There might be a little error in your caculation.
@owl3math
20 күн бұрын
Hello. Both answers are equivalent and approximately 0.347. Where does the 0.904 come from?
@renesperb
20 күн бұрын
@@owl3math You wrote the final answer not very clearly : I read Exp[π+1] instead of Exp[π] +1.
@owl3math
19 күн бұрын
@@renesperb ah i see. Sorry, My bad. Yes the "+ 1" is kind of drifting north and looks like it could be in the exponent. Woops!
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