It's not incorrect because of C that should be replaced by another constant C - 1 and then you get y - ln(x + y + 1) = C2 type equation. That is how he got a Wolfram Alpha type result at the end like he did.
@lawrencejelsma8118
6 ай бұрын
Ohhps ... Your correct. I was thinking outside the ln() part.
@shmuelzehavi4940
6 ай бұрын
That's right. I've also noticed.
@JoeHarpo
6 ай бұрын
At 6:13, what happened to the "+1" in the ln()?
@shmuelzehavi4940
6 ай бұрын
@@JoeHarpo if z = x + y + 1 then z + 1 = x + y + 2
@FisicTrapella
6 ай бұрын
6:10 ln(z+1) = ln (x+y+2) 6:45 the derivative of your expresion should be y' = ( 1 / (x+y+2) ) (1+y') [chain rule]
@lawrencejelsma8118
6 ай бұрын
Well then ... He can't do that tricky Wolfram Alpha end result now! 😂👍
@lawrencejelsma8118
6 ай бұрын
By the way looking at his Wolfram Alpha result it was make mistakes in z = x + y + 1 stuff and then at 7:45 mark forget about z = x + y + 1 stuff and work with z again to luckily correct those mistakes by not back substitutions. 😂 That is how the end Wolfram Alpha result looked correct somehow!! 🤣
@bernarddoherty4014
6 ай бұрын
Dear algebra, please stop asking me to find your X! She's never coming back! And don't ask Y!! 😔😔😂😂
@SyberMath
6 ай бұрын
😁😜
@yoav613
6 ай бұрын
Nice and interesting DE,from the masrer of lambert function😊💯
@SyberMath
6 ай бұрын
Thank you!
@scottleung9587
6 ай бұрын
Nice!
@viktor-kolyadenko
6 ай бұрын
Sulution z+1 = 0?
@Sh0d3wEditz
6 ай бұрын
Hey! Im grade 8th and i really wish to ask this.can u upload equations with power like 4 5 6 and etc? Thanks❤
@giuseppemalaguti435
6 ай бұрын
y-ln(x+y+2)=c...but y'=...at 7.08????
@sunildhuri8421
6 ай бұрын
Very easy
@rob876
6 ай бұрын
let u = x + y + 1 u' = y' + 1 y' = u' - 1 = 1/u u' = 1/u + 1 ∫du/(1/u + 1) = ∫dx ∫udu/(u + 1) = ∫dx ∫(u + 1 - 1)du/(u + 1) = ∫dx ∫du - ∫du/(1+u) = ∫dx u - ln(1 + u) = x + const u + 1 - ln(u + 1) = x + const ln(exp(u + 1) - ln(u + 1) = x + const exp(u + 1)/(u + 1) = const.exp(x) (u + 1)exp(-(u + 1)) = const.exp(-x) -(u + 1)exp(-(u + 1)) = C.exp(-x) -(u + 1) = W(C.exp(-x)) x + y + 2 = -W(C.exp(-x)) y = -x - W(C.exp(-x)) - 2
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