Quote of the day - Write it in a Complex way, not complicated way, but Complex way!
@SyberMath
7 күн бұрын
😁😍
@robertholder
9 күн бұрын
For those wondering about the 0^0 "controversy": The value of 0^0 is a contextual definition, not a philosophical one - as is much of math. That is, some fields need it to be 1 and define it as such. Other cases treat as undefined, as needed. Good summary here: en.wikipedia.org/wiki/Zero_to_the_power_of_zero
@scottleung9587
9 күн бұрын
I knew x=0 was the only real solution. I just forgot to complexify 2^x=1.
@RichardHoffman-j9l
9 күн бұрын
(4 to the xth power) + (6 to the xth power) + (10 to the xth power) = ([ 2 ° 2] to the xth power) + ([ 2 ° 3] to the xth power) + ([ 2 ° 5] to the xth power) = (2 to the xth power) (2 to the xth power) + (2 to the xth power) (3 to the xth power) + (2 to the xth power) (5 to the xth power)= (2 to the xth power) [(2 to the xth power) + (3 to the xth power) + (5 to the xth power)] Dividing both sides by [(2 to the xth power) + (3 to the xth power) + (5 to the xth power)] we get 2 to the xth power = 1 log to the base 2 of [2 to the xth power] = log to the base 2 of 1 × = 0
@ghstmn7320
9 күн бұрын
Assume f(x)= 2^x + 3^x + 5^x where it's differentiable across all reals with a derivative f'(x)= (2^x)*ln2 + (3^x)*ln3 + (5^x)*ln5. Notice f'(x)>0 for all x, meaning that f is injective. The given equation is f(x)=f(2x). Since f is injective we have f(x)=f(2x) => x=2x => x=0
@dan-florinchereches4892
9 күн бұрын
Nice approach. However isn't it quicker to just factor 2^x from left side bring everything together and have a product of a sum of exponentials (always>0) and 2^x-1 equal 0.
@ghstmn7320
9 күн бұрын
@@dan-florinchereches4892 yes of course. I'm just stating a different solution! The one presented in the video is much more efficient
@dan-florinchereches4892
9 күн бұрын
@@ghstmn7320 I thought the problem was a bit more interesting but then I clicked and saw the thumbnail properly. I was expecting something like 2^x+8^x=3^x+7^x for which you would use calculus indeed. Theorem of Laplace
@SweetSorrow777
9 күн бұрын
Wrong channel. This isn't aplusbi.😅
@achiyederi3622
8 күн бұрын
Same channel owner
@SweetSorrow777
8 күн бұрын
@achiyederi3622 I know; tis was a joke.
@rakenzarnsworld2
9 күн бұрын
x = 0
@trojanleo123
7 күн бұрын
Such a heretic that you belive 0⁰ = 1. Lol. Just kidding! 😆
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