That feeling when you only need one more line is such a horrible feeling.
@SerpentHashiraObanaiIguro
Ай бұрын
And this is why I always had extended testing time accommodations in school.
@f.p1758
Ай бұрын
Well... As youve already watched, usually if you write so much, your understanding is probably correct but your missing at an simple answer
@gagana1085
Жыл бұрын
It is a very simple problem, for those in confusion go through this : Look, there are 8 vertices for a cube. He was asked to find a domain of area. He says that there is a world outside of the cube. From this, he meant to visualize each dot to have its own sphere. Each spheres 1/8th portion was inside the cube. There are 8 such dots. If u simply multiply 8 × 1/8, u get 1. So, the ratio of the domain around the dot and to that of those 8 vertices is 1:1. The required area is half the total volume of sphere.
@straypaper
Ай бұрын
You're right, and wrong at the same time. The domain of the atoms are not spherical, but in fact, a complex polyhedron. Karma's sphere visualization confused you. Spheres inside a cube would either overlap or leave out a certain area. The domains can only be a regularly shaped complex polyhedron. Gakushuu had the right idea, but not the correct understanding. Gakushuu wasted his time trying to identify the dimensions of the polyhedrons, when in fact it is not necessary. All you need to know is that the cube is filled with 8 eighth parts of an identical polyhedron and one whole polyhedron. Hence why the volume of each polyhedron can only be half of the cube.
@Sofia-qr6rg
Ай бұрын
You don’t actually need to worry about the domain as such. Since the relative sizes of the atoms are not in question, you can break down each bcc lattice into 4 smaller cubes with 2 atoms on opposing ends. Since roughly half the volume of each of these smaller cubes is going to be for the central atom, you can extrapolate that half of the total volume of the 4 small cubes together will also be the domain of the central atom, giving you your answer of a^3/2. While the polyhedron approach is correct, the question doesn’t require that approach
@holysinnerxxx
2 жыл бұрын
Man I loved all the visuals associated with the test problems. Awesome anime!
Fun fact. The author himself said it took him 3 days to give a proper answer to the question, that he asked a teacher friend to make. Actually anyway, even if not the same way karma did, it was still very simple(even it takes your good 5 minutes to understand it, while most ot the problems could be solved in auto mode).
Crystaline structures: They are conformed by the same "piece", those pieces share the same shape and size, hence the volume. Knowing that, you can reach the answer easily. My head canon is that Karma knew that thanks to Okuda www
@insomniacdemon
Ай бұрын
one piece??
@rebecamendez5456
Жыл бұрын
Este detalle que algunas veces los problemas más "dificiles" simplemente les ponen muchos distractores es muy real , por eso es importante tener conocimiento flexible y variado, para llegar a soluciones mas cortas y sencillas.
Dont beat yourself up. alot of things taught in school are building skills meaning you learn layer by layer. When you miss or are never taught a layer the whole thing falls apart. Also those in Class E basically have the most advanced IEP which helped them ace tests designed for one of the most advanced schools ever. . . that is ironicly only a middle school but its anime whatcha expect
@rakwalking7243
2 жыл бұрын
I realised that for a student studying in kota Allen,this question is actually a child,s play
@ponnamadithyasai6645
2 жыл бұрын
yep , direct formula based question from solid state lmao
@rakwalking7243
2 жыл бұрын
@@ponnamadithyasai6645 you are right,but then I realized that they are junior high students whereas it is actually a high school question😅😅
@badribishaldas9627
Жыл бұрын
This question is for 15 year olds.
@Mr.Mirage21
10 ай бұрын
I had a question like this on college a few months ago, instantly I remembered this scene.
@maxxsbrother2
Ай бұрын
Lol, did it help?
@Someone-zn4dh
Жыл бұрын
...the fact I can understand Karma's explaination...
Es una red bcc una red cubica de cuerpo centrado se estudia mas a fondo en el curso se materiales de metales, en dicha red existe 2 atomos y asumiendo que en el problema no se considera los espacios intersticiales se podria decir que el volumen de la esfera es la mitad del cubo ya que el volumen de dos esferas es igual a un cubo de arista A, otra forma de hacerlo es usando de radio a/2 y bueno saldria el volumen de una esfera (3.1416 /3) ×a^3/2 ybueno esto sale 1.046 aprox 1 saldria lo mismo a^3/2 este problema , si lo leen tiene mas distractores :v karma lo deducio de la forma mas sencilla en cambio asano busco la forma supuestamente mas segura y larga
@user-fp5bg5vb6p
2 жыл бұрын
2:32 あれ?高校生なのにわかんないじゃん
@Rstar320
10 ай бұрын
I just realized this a material science question lol
I've studied a bit of chemistry, physics and maths but this question seems incredibly odd to me and I'm blown away by the fact that Middle Schoolers were suppose to solve something like this. The question seems to imply having some sort of knowledge within chemistry given the fact that they out right give you the elements they're using, but they're talking about their atoms specifically which would then require physics when dealing with atoms, it almost makes me wonder if they're talking about electric fields of some sort because it almost seems like its trying to describe its relationship to the other atoms nearby. The math portion I'm beyond confused because some of it looks like its using a branch of mathematics that realistically should have nothing to do when it comes to chemistry and physics. The use of set theory here, which describes a collection of objects, unless I'm simply reading too much into this and that's just suppose to be fluff for the students to just ignore, but the question literally says the set of all points, I'm going to assume that its only talking about the points shown in the problem because if its talking about every point in the universe it'd just be an infinite set. Since Karma and Asano were heavily focused on the geometry of this problem I'm going to have to assume that perhaps this question is just purely a geometry question as suppose to a question involving high level mathematics, as well as knowledge of chemistry and physics.
@DeadlyBlaze
28 күн бұрын
This is a standard introductory level competition math problem albeit formatted with far more sophisticated wording. The sentences about paragraph structure is just problem "lore" as it is called in olympiad math communities, and doesn't impact the problem.
@animeotaku-tt9ve
Жыл бұрын
In iit there was a question like this and it's similar to questions of packing fraction from solid states...
the comment section makes me realize i need to restudy physics chemistry and maths I'm a medical student and barely even understand their efforts in simplifying this problem I'm thankful though
@user-jk9fk8bj8m
7 күн бұрын
小学校の時カルマくんのやり方で点数取れたことあったw😂立方体のやつ形が一緒やったから覚えてたなー
@huntkarly0805
2 жыл бұрын
【彼らは定期試験を行っています】
@user-jd7tb5jw1j
2 жыл бұрын
小学生じゃ無理
@user-qe7tt1dr2t
2 жыл бұрын
大人でも無理
@TBomb15
5 ай бұрын
this...this an x-ray crystallography problem. I challenge any highschool student anywhere in the world to show me a question like this on a test. Also there is not enough information in the wording to solve this problem. you need to know the braggs distance and 2(theta) angle, also a calculated reference pattern to even begin to answer this question
So, BCC lattice, has Radius of an atom equals √3a/4. then Volume of any atom would be basically 4/3πr³ right? Why does it differ in this case? and on top of that, the Body-centered Atom contibutes a whole, ie, it has a whole 1 contribution to the Volume if lattice right? the corners have 1/8 and edge centers have 1/4, face centers have 1/2. So the atom at body center should be taken a whole, and its volume is my answer, right?. It is NOT a³/2 by this method
@vratha9740
Жыл бұрын
They aren't asking volume of atom
@virajmhetar7456
Жыл бұрын
@@vratha9740 without calculating volume of the atom, how can we substract it from volume of inside of cube..
@tbicedshot2819
Жыл бұрын
This is very late but Karma's visualization using spheres is wrong. I did this problem on my rewatch of the anime without knowing the answer and I found a much simpler method. I realized that, since the cubes extend out infinitely, each atom has the same volume. This means that the atoms on the corners of the cubes have 1/8th of their total volume inside one cube, while the atom in the middle has its entire volume in one cube. If the volume of an atom is x, that means that the total volume of the cube is x (center atom) + x/8 * 8 (corner atom, multiply them by 8 since there are 8 corner atoms). This just simplifies to 2x = a^3 (a^3 is the volume of the cube since a is the side length) and x = a^3/2
@virajmhetar7456
Жыл бұрын
@@tbicedshot2819 well, if you take 'atoms' which are spheres again, then you are left with something called as voids. There are 2 types of voids, namely: 1. Tetrahedral void, (T.V) 2. Octahedral void. (O.V) The number of these depend on the effective number of atoms in a lattice. For eg, in a 'simple cubic' arrangement, when we all 8 corners containing 1 atom each, what you said is correct, the effective number of atom inside is "1" But here, the Number of T.V is 2 times effective atoms, thus we have "2" of these tetrahedral voids. Similarly, Number of O.V is 1 times the effective number of atoms, which is "1" of this void. My point is, the total volume of the cube will be more than just adding total atoms at corners
@tbicedshot2819
Жыл бұрын
@@virajmhetar7456 I can see what you are saying but I think you misunderstood me. I was saying that using spheres to visualize the volume of the atoms doesn't work, then provided a way that does work. The way I did it was making the volume of the atom equal x. Then, since 1/8th of the corner atoms volume is in the cube, and there are 8 corner atoms, they make up 1x of the volume. The center atom has all of its volume inside the cube, so it also accounts for 1x. So the volume of the cube is 2x, and the equation 2x = a^3 leads to x, or the volume of an atom, being equal to a^3/2
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