After Finding so many Music for refresh mind Last i found my childhood favorite song This song °= Mood change
@mr.allrounder0968
2 жыл бұрын
2:04 next level vibe 😍🔥
@creativevibes5708
Жыл бұрын
Glass tutne ki ... voice 👍
@JonJon-qz1gp
2 жыл бұрын
Ye song sun k muj nind agai 😂😂😂😂
@udairaj1571
2 жыл бұрын
Mri udd gi 🤣🤦
@sheetaljadhav108
2 жыл бұрын
So ja
@magicalgirl5559
2 жыл бұрын
So ja
@RohitKumar-rv2rf
Жыл бұрын
Kya Meri to nind ud gyi
@poojadas3606
Жыл бұрын
🤣🤣🤣🤣🤣😂😂😂😂
@biswajitbehera5870
Жыл бұрын
Formula: Surface area of a sphere (SA) = 4πr2 (i) Radius of the sphere, r = 10.5 cm SA = 4×(22/7)×10.52 = 1386 Surface area of the sphere is 1386 cm2 (ii) Radius of the sphere, r = 5.6cm Using formula, SA = 4×(22/ 7)×5.62 = 394.24 Surface area of a sphere is 394.24 cm2 (iii) Radius of the sphere, r = 14cm SA = 4πr2 = 4×(22/7)×(14)2 = 2464 Surface area of the sphere is 2464 cm2 2. Find the surface area of a sphere of diameter: (i) 14cm (ii) 21cm (iii) 3.5cm (Assume π = 22/7) Solution: (i) Radius of sphere, r = diameter/2 = 14/2 cm = 7 cm Formula for Surface area of sphere = 4πr2 = 4×(22/7)×72 = 616 Surface area of the sphere is 616 cm2 (ii) Radius (r) of the sphere = 21/2 = 10.5 cm Surface area of a sphere = 4πr2 = 4×(22/7)×10.52 = 1386 Surface area of the sphere is 1386 cm2 Therefore, the surface area of a sphere having diameter 21cm is 1386 cm2 (iii) Radius(r) of sphere = 3.5/2 = 1.75 cm Surface area of a sphere = 4πr2 = 4×(22/7)×1.752 = 38.5 Surface area of the sphere is 38.5 cm2 3. Find the total surface area of a hemisphere of radius 10 cm. [Use π=3.14] Solution: Radius of the hemisphere, r = 10cm Formula: Total surface area of hemisphere = 3πr2 = 3×3.14×102 = 942 The total surface area of the given hemisphere is 942 cm2. 4. The radius of a spherical balloon increases from 7cm to 14cm as air is being pumped into it. Find the ratio of surface areas of the balloon in the two cases. Solution: Let r1 and r2 be the radii of the spherical balloon and spherical balloon when air is pumped into it, respectively. So, r1 = 7cm r2 = 14 cm Now, required ratio = (initial surface area)/(Surface area after pumping air into balloon) = 4πr12/4πr22 = (r1/r2)2 = (7/14)2 = (1/2)2 = ¼ Therefore, the ratio between the surface areas is 1:4. 5. A hemispherical bowl made of brass has inner diameter 10.5cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm2. (Assume π = 22/7) Solution: Inner radius of hemispherical bowl, say r = diameter/2 = (10.5)/2 cm = 5.25 cm Formula for Surface area of hemispherical bowl = 2πr2 = 2×(22/7)×(5.25)2 = 173.25 Surface area of hemispherical bowl is 173.25 cm2 Cost of tin-plating 100 cm2 area = Rs 16 Cost of tin-plating 1 cm2 area = Rs 16 /100 Cost of tin-plating 173.25 cm2 area = Rs. (16×173.25)/100 = Rs 27.72 Therefore, the cost of tin-plating the inner side of the hemispherical bowl at the rate of Rs 16 per 100 cm2 is Rs 27.72. 6. Find the radius of a sphere whose surface area is 154 cm2. (Assume π = 22/7) Solution: Let the radius of the sphere be r. Surface area of sphere = 154 (given) Now, 4πr2 = 154 r2 = (154×7)/(4×22) = (49/4) r = (7/2) = 3.5 The radius of the sphere is 3.5 cm. 7. The diameter of the moon is approximately one fourth of the diameter of the earth. Find the ratio of their surface areas. Solution: If the diameter of the earth is d, then the diameter of the moon will be d/4 (as per the given statement) Radius of earth = d/2 Radius of moon = ½×d/4 = d/8 Surface area of moon = 4π(d/8)2 Surface area of earth = 4π(d/2)2  The ratio between their surface areas is 1:16. 8. A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5cm. Find the outer curved surface of the bowl. (Assume π =22/7) Solution: Given: Inner radius of hemispherical bowl = 5cm Thickness of the bowl = 0.25 cm Outer radius of hemispherical bowl = (5+0.25) cm = 5.25 cm Formula for outer CSA of hemispherical bowl = 2πr2, where r is the radius of the hemisphere = 2×(22/7)×(5.25)2 = 173.25 cm2 Therefore, the outer curved surface area of the bowl is 173.25 cm2. 9. A right circular cylinder just encloses a sphere of radius r (see fig. 13.22). Find (i) surface area of the sphere, (ii) curved surface area of the cylinder,
@kingsproduction7127
Жыл бұрын
Well done 👍🏻👍🏻🌵🌵
@vedwati2874
Жыл бұрын
❤️❤️Chamka chamka beliya mai cham cham krke chamka Lama jhandhu bam ye ......❤️❤️
Imagine your drinking glass of wine at your wedding and suddenly you throw the glass and start singing this song and a group at the wedding joins you by breaking a glass and people break the glasses at the beats to cheer you😂😂🫣❤️
@kashikabansal9006
Жыл бұрын
Or esa sirf imagination me hi ho sakta h😂
@saimaali8280
Жыл бұрын
Glass thore ziada hi ni turwa diye?😂
@77pranjalsingh46
Жыл бұрын
Imagine getting beat up by guests at your wedding 🥶
@rishusingh9641
Жыл бұрын
Correct bro
@vijendrachoudhary9643
Жыл бұрын
Best imagination bruh!!
@tiwarijimboy7490
2 жыл бұрын
Wow 😲
@JALLER_MS
2 жыл бұрын
❣️💯
@user-uc3eh1ow4w
21 күн бұрын
im from Bangladesh 🇧🇩🇧🇩😎
@user-qj1kn1qo1s
6 ай бұрын
Amazing song sunke Maja ajata hay
@latamondal3302
Жыл бұрын
I love this 😘😘 song
@sunitatiwari3819
Жыл бұрын
Mja aa gya 😄😄
@UsmanKhan-dt6xt
2 ай бұрын
My Fvrt Song❤
@skamranali5584
Ай бұрын
Ya song sunkar mujha mera bachpan ki shadiiyan yaad again😢
@blogmaster1k
2 жыл бұрын
❤️❤️
@AliYWajid
Ай бұрын
My best song 😍
@ramaghanta3698
Жыл бұрын
I like this song 🔥❤️💞
@aniketgehlot07
6 ай бұрын
Koun koun reel dekh kar aaya hai 😊😊
@manishambekar4252
2 жыл бұрын
👌👌👍👍 niche sound
@veertalyan315
2 жыл бұрын
💓💓💓
@user-zz2ri3wn1n
2 жыл бұрын
😍
@user-fs3jv3hs1f
16 күн бұрын
আগে থেকে কার কার কানে হেডফোন ছিল শুধু তাড়াই সুনে মজা পাইছে 😎😎😎😎😎😎🤙🤙🤘🤘🤟
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