I'm a bit confused. At the start of the video it says both transistors are off with no current flowing through them. Where does the D.C. emitter voltage of vcc/2 come from? Wouldn't the emitter voltage be open. Thanks Scott.
@kindjupiter
7 жыл бұрын
thank you for your helpful videos. It is way more helpful than books especially for students who study on their own. again thank you very much Mr. Williams
@miloroyce2797
3 жыл бұрын
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@benedicturiah7037
3 жыл бұрын
@Milo Royce instablaster =)
@miloroyce2797
3 жыл бұрын
@Benedict Uriah i really appreciate your reply. I got to the site on google and I'm trying it out atm. Seems to take a while so I will reply here later when my account password hopefully is recovered.
@miloroyce2797
3 жыл бұрын
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@benedicturiah7037
3 жыл бұрын
@Milo Royce you are welcome xD
@curtpiazza1688
10 ай бұрын
The calculations are very convincing! 😂
@ElectronXLab
10 ай бұрын
Power of Persuasion...applied to circuits lol
@ozien3476
5 жыл бұрын
Thank you for this video sir ! ı have one question about Ic . Why Icq is equal to zero ?
@21thTek
5 жыл бұрын
I enjoyed the explanation, thanks a bunch !
@kolinevans9127
4 жыл бұрын
Correct me if I’m incorrect but if you have a very small R bias the gate then you have a direct ‘shot’ from VCC and ‘ground’ Also the P valve is on the bottom isn’t that the wrong way around ? When the P valve is open the N valve is closed how is there an equalization of polarity through the N if it’s closed to the P ? Or am I just very mistaken ? Edit I see with regards to the P and N disregard
@therealmrsketch
6 ай бұрын
The Hexbug goes hard
@lawstonpettymore
4 жыл бұрын
Wait. If Q1 is shut off, nothing is going to be flowing through Q2.
@omarvazquez9958
3 жыл бұрын
I noticed that too. I think this circuit requires a negative supply on the PNP transistor instead of being connected to GND
@merkletree2510
2 жыл бұрын
I thought so too. But it is working if you don't omit the input and output capacitor. Simulation in LTSpice concurs. When Q1 is shut off, the energy flowing through Q2 is probably delivered by the output capacitor. Both capacitors ensure that just the AC Part is "flowing" through the B-Class Amplifier.
@oneinabillion654
3 жыл бұрын
Why is Icc consisting of a sinusoidal wave? Isn't it DC?
@youpattube1
7 жыл бұрын
at about 4 min you show the red output curve 0.7v less than Vin. How is this an amplifier ?
@ElectronXLab
7 жыл бұрын
That's a good question. This type of amplifier is a power amplifier, not a voltage amplifier. typically there would be a previous voltage amplifier stage and then this power amplifier would be used to drive a lower impedance load.
@edwardfanboy
7 жыл бұрын
It amplifies the current. You can draw more current from the output of the amplifier than from the signal feeding the amplifier.
@hamidhashemi616
4 жыл бұрын
hi how to determine values of capacitor and base resistors???
@doktordzwonek9306
4 жыл бұрын
How can Ve be Vcc/2 if this is an emitter follower so it can be no more than Vin, usually Vin - 0.7V? AB amp doesnt have any voltage gain, does it?
@ElectronXLab
4 жыл бұрын
That's the DC bias voltage
@doktordzwonek9306
4 жыл бұрын
@@ElectronXLab Of course, I'm an idiot. Thanks David, appreciate!
@ananda6686
6 жыл бұрын
here you have taken Ic avg but on taking that only Q1 is considered.So what about Q2.The path of Ic avg you indicated is from the collector of Q1 to load.
@ano_ny_mous
5 жыл бұрын
@david williams, I also have the same question. Also why taking the average, why not rms?
@MarkTillotson
6 жыл бұрын
Without proper biasing its not really class-B, class-B has each transistor conducting 180 degrees of the cycle, not less than 180 as in the simple push-pull described - that's actually somewhere between B and C. Simple push-pull without biasing has severe cross-over distortion.
@rich1051414
6 жыл бұрын
Biasing isn't even required if you stick an opamp on the input and feedback the output of the transistors though, right?
@tefamilyadventures
4 жыл бұрын
Enjoying your video! Keep up the good work. If you have a second you could take a look at my account 😊🤘
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