What factor leads to the stability in voltage divider bias?
@ALLABOUTELECTRONICS
4 жыл бұрын
The timestamps for the different topics covered in the video: 0:23 Introduction to Voltage Divider Bias Configuration 1:43 Approximate DC Analysis of Voltage Divider Bias Configuration 4:30 Exact DC Analysis of Voltage Divider Bias Configuration 9:50 Solved Example on Voltage Divider Bias For more Solved Examples on the BJT, check out this playlist: kzitem.info/news/bejne/w6-GqI6jfJiklW0
@AhsanKhan-sj8yr
4 жыл бұрын
sir very informative video. can you please tell me which software you use for making these videos.
@vinaykumarkv5830
3 жыл бұрын
Superb👌👌🔥
@jstro-hobbytech
Жыл бұрын
Great video
@aalabalu674
Жыл бұрын
ic =0.7mA,vce=9.8v huge variation in operating point under approximate analysis
@technologyiskole9626
3 жыл бұрын
best vedio
@patrickmagombo4500
3 жыл бұрын
How does current stabilisation achieved this configuration
@quicktech7450
4 жыл бұрын
thank you sir
@user-ub5su9vj6d
7 ай бұрын
😇😇😇👍👍👍🙏🙏🙏Thanks a lot, great job!!!!!!!Please make a design bias circuit ( Design the value of resistors and capacitors).
@ALLABOUTELECTRONICS
7 ай бұрын
It’s already covered through solved problems. Please check BJT solved problem playlist on the channel page.
@user-ub5su9vj6d
7 ай бұрын
@@ALLABOUTELECTRONICS You always do a perfect job.👍👍👍😇😇😇🙏🙏🙏
@jbdlssnts7351
4 ай бұрын
Why is the equation for Vce, Vce=Vcc-Ic(Rc+Re) instead of Vce=Vcc-IcRc-IeRe? Is it because we assume that Ie=Ic? if so, is it still under exact method or approximation method? sorry for bad english
@abeyjoseph4727
4 жыл бұрын
thank you so much
@PreetiYadav-ng1kw
3 жыл бұрын
Thanks sir
@soujanyaas9074
4 жыл бұрын
Superb
@EmCeyyyyyyy
6 ай бұрын
How do you calculate parallel? The one giving 1.66k ohms in the example at the end?
@im_cpk
3 жыл бұрын
5:44 could you please explain,how vth comes?
@im_cpk
3 жыл бұрын
I mean to say, where's open circuit voltage...
@ALLABOUTELECTRONICS
3 жыл бұрын
In this case, the Thevenin's equivalent voltage is the voltage seen across the R2 and ground.
@teeggindarshannagappa8858
Жыл бұрын
Hello, at 9:45 it has been said that if Rth
@dasilvaleandro21
Жыл бұрын
Correct one is Rth
@033_rkpragyajitsingh6
4 жыл бұрын
Can we find the value of Ve using Vc-Vce instead of Vb-Vbe?
@ALLABOUTELECTRONICS
4 жыл бұрын
If Vc and Vce are known then yes, you can find Ve using that formula.
@taymoortariq6803
4 жыл бұрын
thanx
@lawrencemayfield9669
4 жыл бұрын
need a video having it in saturation and finding all things including beta
@NakulMandwal-gt5cd
9 ай бұрын
Iske notes ke pdf download kar sakte hai kya for fast revision Is there any link or website of this channel from where i can download this presentation ppt
@adreq3.05
4 жыл бұрын
If haves the transistor current amplification I CEO about fifty, this can to be amplicate als electronic key only.
@harshit9112
2 жыл бұрын
16:15 0.1 will come instead of 10
@MKTheBlackKid
4 ай бұрын
what if there are numbers on the capacitors🤔
@vijaysri4849
2 жыл бұрын
Is self baising and voltage divider baising same
@aashishgautam258
4 жыл бұрын
Sir pls make further videos in this series
@ALLABOUTELECTRONICS
4 жыл бұрын
Yes, very soon all the topics will be covered.
@Shibomdas411
3 ай бұрын
3:45 then why you addd VE
@ALLABOUTELECTRONICS
3 ай бұрын
Vce is the drop across the collector and emitter terminals of BJT, while VE is the drop across emitter terminal. To find Vce, first we need to find Vc and then Ve. The difference between them will give us the drop across those two terminals of BJT. Vc = Vcc - Ic Rc and Ve = Ie Re. And the difference between them will give us Vce. That’s what is shown at 3:50
@nikolaynetsov6529
4 жыл бұрын
I need a little help. I must find Re,R1 and R2. I have h213=80,Rc=2kΩ,Ic=1mA,Uce=2V,Vcc=4,5V,Id=10Ib and Ube=0.6V
@ALLABOUTELECTRONICS
4 жыл бұрын
Many such problems have been solved on BJT on the second channel. Here I am giving the link for the playlist on the solved problems on BJT. Ypu will find such example as well. Here is the link: kzitem.info/news/bejne/mZibtod_kGuTbHo Still if you find any difficulty, let me know here.
@nikolaynetsov6529
4 жыл бұрын
@@ALLABOUTELECTRONICS Thank you a lot for the support
@pandurangaiahshetty4064
4 жыл бұрын
Please do videos on tranistor amplifiers
@ALLABOUTELECTRONICS
4 жыл бұрын
Yes, that too will be covered soon.
@jacquelineurena5860
3 жыл бұрын
On min 15:15 did you mean Rth
@ALLABOUTELECTRONICS
3 жыл бұрын
Yes, that's right
@niharikagoulikar2921
3 жыл бұрын
Why is capacitor connected at input and output side?Could someone explain me?
@ALLABOUTELECTRONICS
3 жыл бұрын
They are used to block the DC biasing voltage. Typically these amplifiers are using in cascade configurations where more than one such amplifiers are cascaded. The DC biasing voltage of one amplifier should not affect the next amplifier or any other circuitry after the amplifier. The capacitor blocks the DC voltage and passes only AC signal.
@abhilashasaini8758
4 жыл бұрын
Vbe=0.7V how? Is it given? Pls reply fast
@ALLABOUTELECTRONICS
4 жыл бұрын
If you see, the base emitter junction is forward biased. So, it acts like a diode and the voltage drop across it can be assumed to be around 0.7V during the analysis. I hope it will clear your doubt.
@abhilashasaini8758
4 жыл бұрын
@@ALLABOUTELECTRONICS ok thanku thanks a lot
@abhijitkumarmanna2031
2 жыл бұрын
How you have done {Rth/(beta+1)}+Re in place of {Rth+Re(beta+1)} ? 8:35
@ALLABOUTELECTRONICS
2 жыл бұрын
Its emitter current. Just multiply the base current with ( beta + 1). Taht means, i nthe numerator you will have ( beta + 1) term. Now, multiply and divide the numerator and denominator by (beta + 1). So, finally, you will get {Rth/(beta+1)}+Re } in the denominator. I hope, it will clear your doubt.
@abhijitkumarmanna2031
2 жыл бұрын
@@ALLABOUTELECTRONICS got it I have also worked it in my copy 😅 forgot to delete this query 😅
@angelorison6455
2 жыл бұрын
15:15 I think Vce is equal to 6.204 V right???? I got this value from my calculator if it is wrong check it and plz correct it.
@ALLABOUTELECTRONICS
2 жыл бұрын
The collector current is 1.266 mA. During the calculation, if you take the value of collector current up to 3rd decimal place, then Vce will come out as 6.174 V. If you consider the value of Ic up to 2 decimal places, then Vce = 6.204 V.
@angelorison6455
2 жыл бұрын
@@ALLABOUTELECTRONICS oh got it thank you
@creativearyaninnovative1846
3 жыл бұрын
Actually imagine nahi ho pata h Apke lectures
@blisstheprodigy
5 ай бұрын
How can one find VB in this type of configuration? Is VB = VTH?
@ALLABOUTELECTRONICS
5 ай бұрын
As I mentioned in the video, you can check the condition for the approximation. That means if Rth is much less than (B + 1) RE, then you can do the approximate analysis. And as per the approximate analysis, you can find the Vb, just using the voltage divider rule. If condition mentioned above does not get satisfied, then you need to do the complete analysis by finding Vth and Rth.
@blisstheprodigy
5 ай бұрын
@@ALLABOUTELECTRONICS Yes, I realised that after commenting. Thank you. Your videos are so helpful
@shuvbhowmickbestin
4 жыл бұрын
What about the DC stabilisation?
@niladrimallik3172
4 жыл бұрын
We have assumed base current almost equal to 0. So, at 7:21, won't we take base current=0?
@ALLABOUTELECTRONICS
4 жыл бұрын
Yes, that was considered for the approximate analysis. And it can be assumed when (B+1) Re >> Rth. At 7:21 the expression of the base current gives the exact value of the base current. I hope it will clear your doubt.
@niladrimallik3172
4 жыл бұрын
@@ALLABOUTELECTRONICS Yeah got it. Thank you for the answer.😊
@im_cpk
3 жыл бұрын
8:23 how you got the value of ie??how rth/beta+1 came?? plez reply 🙏🙏🙏
@im_cpk
3 жыл бұрын
I know you got the value from i/p kvl equation...but how this rth/beta+1 came...
@ALLABOUTELECTRONICS
3 жыл бұрын
I hope, you got the expression of Ib. Now, Ie = (beta + 1) Ib. Just put the value of Ib from the expression. And then divide the entire expression by (beta + 1). You will get that expression. If you still have any doubt then let me know here.
@ankitashirali9362
4 жыл бұрын
Sir please make a video on ce amplifier
@ALLABOUTELECTRONICS
4 жыл бұрын
Yes, once I will cover the different biasing configuration, I will cover the CE amplifier and the AC analysis.
@jenadolfo9358
4 жыл бұрын
what if the R1 and beta is unknown? what is the formula for it plss help
@ALLABOUTELECTRONICS
4 жыл бұрын
If there are few unknown, then must have been given other parameters. One such example is covered on the channel. kzitem.info/news/bejne/05iZqpiKiJ5erGU Please go through it.
@user-tv6gx1ct1s
Жыл бұрын
i have a small doubt is self bias and voltage divider bias same or different
@ALLABOUTELECTRONICS
Жыл бұрын
They are same. In the self biasing, we do not require another power supply for biasing the base of the transistor. Using external resistors, it is derived from the existing power supply. The same is done in the voltage divider bias.
@user-tv6gx1ct1s
Жыл бұрын
Thank you very much for your reply got clarified
@bhaveshchaudhari3406
4 жыл бұрын
Sir plz make video on IGBT..
@ALLABOUTELECTRONICS
4 жыл бұрын
Soon I will try to cover IGBT also.
@bhaveshchaudhari3406
4 жыл бұрын
@@ALLABOUTELECTRONICS thank you.....
@deepanjalimishraa
Жыл бұрын
Want an answrr asap please
@southcurseone1579
3 жыл бұрын
I wanna ask, what if the value of beta is not given and only Ib is known, how can you solve value of beta?
@ALLABOUTELECTRONICS
3 жыл бұрын
If beta is not given in the example, then you must be given some other parameter instead of that.
@southcurseone1579
3 жыл бұрын
@@ALLABOUTELECTRONICS oh i see. So it is impossible to solve without beta. Thank u.
@lawofselfcontrol
3 жыл бұрын
which app are you using?
@veenagovekar3653
4 жыл бұрын
Sir how to get voltage gain of this circuit?
@ALLABOUTELECTRONICS
4 жыл бұрын
I have already covered it. Please go through the BJT playlist. If you go through the video, small signal analysis of CE configuration, you will get it.
@yee-haa
2 жыл бұрын
I am sorry. I still don''t understand how to choose R1 and R2 values in practice when designing a circuit. There must be a more practical way...
@malik-fl1yl
3 жыл бұрын
4:15 1 8:35 2
@kamleshchavan7451
3 жыл бұрын
Please can it be possible for u to remove the subtitles of ur videos. Secondly can this video will be available in Hindi
@ALLABOUTELECTRONICS
3 жыл бұрын
You can turn off the subtitles in the KZitem video settings.
@kamleshchavan7451
3 жыл бұрын
@@ALLABOUTELECTRONICS thanks sir
@realmccoy813
4 жыл бұрын
🙏🏾🙏🏾🙌🏾🙌🏾
@i.mandeepgoyal
3 жыл бұрын
16:00 pe relation galat likh diya
@a.keerthikiran7970
3 жыл бұрын
ic=1.3mA,,,,,,,,,vce=6.02v
@sankhadeepdatta9374
2 жыл бұрын
Sir...i have a query.... could you please provide your mail id...
@ALLABOUTELECTRONICS
2 жыл бұрын
It has been already mentioned in the about section of the channel. You will find the details of all social handles and email id.
@rakeshkundu
3 жыл бұрын
Thode acche se explain krdo sirf here here na bolke
@sutapasaha5615
3 жыл бұрын
Informative but way of explaining should be improved... this could be more interesting if u would not speak like a robot .
@priyajitmondal6661
8 ай бұрын
Thank you sir❤🙏👍
@deepanjalimishraa
Жыл бұрын
Is Ib is equal to Ie
@ALLABOUTELECTRONICS
Жыл бұрын
No, Ie is emitter current while Ib is base current. Ie = ( β +1) Ib. The Ic (collector current) and Ie (emitter current) are almost comparable.
Пікірлер: 107