1:31 A small correction, when you're explaining the calculation for the molecular weight of air, it's actually not right here cause we end up with 137.33 as the molecular weight. It's supposed to be : 21% of O2 + 79% N2 = (21/100)*2*15.99 + (79/100)*2*14.007 = 28.85 g/mol
@justanotherinstrumentguy8066
20 күн бұрын
Hi. Your calculation of AFR (mass) is incorrect. Too long to comment here. If you go to any AFR table on the net, the mass AFR for methane is approx 17.2:1. In term of volume AFR it’s 9.7:1. (en.wikipedia.org/wiki/Stoichiometry). In short, consider main equation CH4 + 2O2 -> CO2 + 2H2O 2 volume of O2 is required for 1 volume of methane (in terms of mass ratio, it’s 64/16=4:1). We know that, 21%vol of O2 in air. To combust 1m3 of methane, we need 2/0.21=9.52m3 of air for complete combustion. In term of mass, 23%wt is O2 in air. Hence, to combust 1kg of methane, you need 4/0.23=17.4kg of air.
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