Keep coming back to this as I refresh the basics. Many thanks for making it so simple and easy to follow
@p.s.645
Жыл бұрын
God bless you man! It’s so much easier and finally clear now, thank you a lot! Safe flights
@nixonmendeed
2 жыл бұрын
Awesome bud this is so much easier than other methods that I have looked at. Thanks for the upload!
@vallanmccarthy4003
11 ай бұрын
Just going through my Nav PPL (H) and this truly brilliant example and Method has just made the penny drop! Brilliant…… Thanks so much.
@cheekcj
3 жыл бұрын
I’m going to watch your videos from now on. Your much easier to understand.
@darrenobrien6253
Жыл бұрын
Hi you are a great teacher the best examples I have ever seen thank you.
@iHopz1995
Жыл бұрын
straight forward and simple to understand, cheers mate!
@Jrkxx
2 жыл бұрын
you have made my GNAV revision so much easier! thank you!
@MrJpbmusic2005
Жыл бұрын
Started my Nav Training today this was really helpful thank you
@6b6tom55
3 жыл бұрын
Best explanation I've seen. Thank you!
@patrickshea-simonds5827
2 жыл бұрын
Just what I needed as a refresher - many thanks!!
@ghamari2001
3 жыл бұрын
very well explained. the other ones I have seen sofar made med confused. this one was systematic and clear! thanks for sharing
@atplmadeeasy2495
3 жыл бұрын
Thanks, glad it helped!
@jonathanMramirez
Жыл бұрын
This meathod is GOLD, cheers!
@voiceluckan
3 жыл бұрын
Nice and easy, this was really helpful. Thank you
@IBRAHIM-ub5xv
2 жыл бұрын
Straight forward explanation thank you so much!!!!
@CirrusGraham
2 жыл бұрын
very useful and well explained, thanks for uploading this
@PICOTTSportsEnt
3 жыл бұрын
Excellent explanation! Thanks so very much for your help!
@atplmadeeasy2495
3 жыл бұрын
Glad it helped!
@Dogfight2000
3 жыл бұрын
Awesome man! Well explained
@rodneymcqueen1706
3 жыл бұрын
thanx for taking the time, good instructional...
@kamsingh7245
3 жыл бұрын
Thankyou struggling since yesterday...first time using and now feels like it's easy...thanks again.
@atplmadeeasy2495
3 жыл бұрын
I'm happy this has helped, thanks for feedback!
@mariowurm3660
3 жыл бұрын
Great explanation. Thanks!
@hachichamehdi9265
Жыл бұрын
God bless you man ! Thank you
@martinsatherley8399
3 жыл бұрын
Best explanation video I've seen, thanks.
@atplmadeeasy2495
3 жыл бұрын
Appreciate the feedback!
@qqq_Peace
Жыл бұрын
Awesome! Sounds very handy!
@roberthatcher2773
2 жыл бұрын
That is a better method, thanks a lot for the explanation and vid upload!
@B2CS
Жыл бұрын
Really clear and concise - thankyou
@zanehussain7670
3 жыл бұрын
Thank you for that explanation 👍👍👍
@marksedin4909
3 жыл бұрын
thanks for the video, you made it really easy!
@atplmadeeasy2495
3 жыл бұрын
Thanks for the feedback!
@yamidgaray9074
Жыл бұрын
Thank you so much
@alimogharbel2663
10 ай бұрын
Well explained thanks
@miketaylor3947
4 ай бұрын
As much as folks appear to like this content, the content is incorrect. Drift does not equal Wind Correction, usually. Drift angle for this case is 9 degrees left so it's 1 degree off the wind correction angle which is what is calculated in this video. The reason people are taught to mark the wind speed down, instead of up, for drift is because the drift triangle is different from the wind correction triangle. For drift, set index=wind angle, set grommet=TAS, mark windspeed down from grommet, rotate and set index=course; read both groundspeed and drift angle from mark (111kts and -9 degrees in this example).
@atplmadeeasy2495
4 ай бұрын
Hi, thanks for the feedback. I am not entirely sure what you are referring to, however the answers in the example are correct. Having used this method myself in ATPL exams it has been designed to follow the layout a student can expect during either ATPL or PPL exams. Please feel free to use the official e6B calculator online or another reputable source using the example and you will reach the answers I have provided if you do not agree. The method I have demonstrated is a quicker and easier way than the marking down method, this is aimed to speed up students in exam conditions.
@miketaylor3947
3 ай бұрын
@@atplmadeeasy2495 I've tried three times to reply including a web reference but looks like youtube doesn't allow this? WCA=negative DA if the aircraft heading = WCA. If aircraft heading is not WCA, then drift angle is almost always different. I'd point you to my writeup on this but, as I said, youtube seems to not allow it.
@lindaclark6558
2 жыл бұрын
EXCELLENT!!
@robertmakwarimba2665
2 жыл бұрын
Thanks a lot!
@patterson47
2 жыл бұрын
Excellent
@alexandrustatie9855
8 ай бұрын
Veryy gooooooood
@addictedtopussy69
2 жыл бұрын
Thanks for the helpful video. Were you able to wipe the marks away made with the permanent marker or did you have to throw it away.
@UKI1
2 жыл бұрын
Cheers, easy.
@hugobordas8466
Жыл бұрын
never comment before but f*** yeahhh blocked on gnav since yesterday on computer use ... Thanksfull
@torrija76
5 ай бұрын
How can you determine wind direction and speed when you are airborne? (let's not consider ATIS or electronic help). And if you are in need of this analog computer while flying solo: how you handle it while also handling the yoke? (consider no autopilot). I always though you need a second person for this.
@Uncommon_Sense01
3 жыл бұрын
Do you know how to use this to calculate ETAS? Thanks
@flybobbie1449
Жыл бұрын
Would be clearer if you drew on the wind arrow. Nice to see easy methods, not some of the wacky one's and wrong answers seen over the years.
@flybobbie1449
Жыл бұрын
Also use pencil, pen will stain.
@johnhebert3855
2 жыл бұрын
When plotting the wind speed, what determines whether you go UP or DOWN from the grommet?
@flybobbie1449
Жыл бұрын
Two solutions need wind above, third type (rarely used) needs wind drawing down.
@stephenstead7270
Жыл бұрын
Can you please tell me what felt pen you are using pencil will not work as good as this felt pen you are using please let me know and thank you for this video mate thumps up from me mate
@atplmadeeasy2495
Жыл бұрын
Hi mate, it’s a regular sharpie permanent marker, use nail varnish remover or hairspray to clean it off 👍
@stephenstead7270
Жыл бұрын
@@atplmadeeasy2495 thank you for your reply mate now il buy one. thank you mate
@focusmicro
Ай бұрын
To determine your heading, drift angle, and ground speed, you can use the wind triangle method. Here are the steps and calculations: Track (T): 290 degrees True Airspeed (TAS): 100 knots Wind: 090 degrees at 30 knots Step 1: Calculate the Wind Correction Angle (WCA) The wind correction angle is the angle between the track and the heading necessary to counteract the wind effect. Using Trigonometry: WCA = arcsin ( W * sin(θ) / TAS ) Where: W = wind speed = 30 knots θ = difference between wind direction and track = 290 - 090 = 200 degrees Since sin(200°) = -sin(20°), we can find the WCA using the sine of 20 degrees and then taking the negative value: sin(20°) ≈ 0.342 WCA = arcsin ( 30 * (-0.342) / 100 ) = arcsin(-0.1026) ≈ -5.89° This means the WCA is approximately -5.89 degrees. Step 2: Calculate the Heading (H) The heading is the track corrected for the wind correction angle: H = T + WCA H = 290 + (-5.89) ≈ 284.11° Step 3: Calculate the Ground Speed (GS) The ground speed can be calculated using the cosine rule in the wind triangle: GS = sqrt( TAS^2 + W^2 - 2 * TAS * W * cos(θ) ) GS = sqrt( 100^2 + 30^2 - 2 * 100 * 30 * cos(200°) ) Since cos(200°) = -cos(20°): cos(20°) ≈ 0.94 GS = sqrt( 100^2 + 30^2 + 2 * 100 * 30 * 0.94 ) GS = sqrt( 10000 + 9000 + 5640 ) GS = sqrt( 24640 ) ≈ 157 knots Summary of Results: Heading (H): 284.11 degrees Drift Angle: -5.89 degrees (left) Ground Speed (GS): 157 knots These calculations show that with a true airspeed of 100 knots, wind from 090 degrees at 30 knots, and a track of 290 degrees, the required heading to maintain the track is approximately 284.11 degrees, the drift angle is approximately -5.89 degrees (indicating a correction to the left), and the ground speed is approximately 157 knots.
@focusmicro
Ай бұрын
I see there is a difference between my calculations and the results shown in your image using the Pooley's flight computer. Let's review the results provided in the image: - Heading (T): 296 degrees - Drift Angle: 6 degrees left (L) - Ground Speed (GS): 127 knots Let's verify these results step-by-step. Step 1: Calculate Wind Correction Angle (WCA) Given: - Track (T): 290 degrees - Wind: 090 degrees at 30 knots - True Airspeed (TAS): 100 knots The difference between the wind direction and track is 200 degrees, which we previously calculated. The sin(200 degrees) and cos(200 degrees) values remain the same as before. Step 2: Calculate the Heading (H) The heading should account for the Wind Correction Angle (WCA). Given a drift angle of 6 degrees left: H = T + WCA = 290 + 6 = 296 degrees This matches the heading given in the image. Step 3: Calculate the Ground Speed (GS) We can use the components of the wind and airspeed to find the ground speed: Wind component along the track = 30 * cos(20°) ≈ 30 * 0.94 = 28.2 knots Wind component perpendicular to the track = 30 * sin(20°) ≈ 30 * 0.342 = 10.26 knots Using the Pythagorean theorem to combine the airspeed and wind components: GS = sqrt((100 - 28.2)^2 + 10.26^2) GS = sqrt((71.8)^2 + 10.26^2) GS = sqrt(5159.24 + 105.31) GS = sqrt(5264.55) ≈ 72.54 knots This seems to be lower than the given ground speed of 127 knots. There appears to be a discrepancy in the calculations. Given that the flight computer gives a ground speed of 127 knots, it would be best to trust the flight computer's calculation as it is specifically designed for these types of navigational computations. Summary (Based on the Pooley's Flight Computer): - Heading (T): 296 degrees - Drift Angle: 6 degrees left (L) - Ground Speed (GS): 127 knots These values are more reliable for practical navigation as they are derived from a dedicated tool.
@focusmicro
Ай бұрын
Interesting to see flight computer vs CHatGPT!. Will go with yours! :)
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