Honestly who needs college professors when u got Charles Estabrooks
@bbh9179
7 жыл бұрын
I tried other tutorials but this is the only one that makes sense to me. Thank you!
@jeremiahfourtwenty
10 ай бұрын
Thank you for this decade old video it's exactly what I needed.
@jeffiscool1805
8 жыл бұрын
Thank you for simplifying this in language I can understand. When I was young I hated electrical and wiring and focused on mechanical repairs. Now the two are so heavily intertwined that I either learn this, or quit trying. I'm not a quitter. People like you that take the time to make these videos are amazing. You have no idea how important what you do is to some of us. The way you break things down into simple terms, and back it up with example formulas as you go,is awesome. Between videos like yours, and some of the affordable micro processor type kits, this is easier, more interesting and more fun than I ever dreamed. All those years being scared of something so simple........... wow.... hindsight. Many, many thanks.
@ddunndada77
7 жыл бұрын
Thank you for this video. Its amazing how some instructors can't explain this as simple as you can.
@calvinkrist5672
8 жыл бұрын
man... I wish my teacher would actually TEACH, like you do... Thank goodness you put your lessons on youtube! Thank you!
@CharlesEstabrooks
8 жыл бұрын
+Calvin Krist Thank you for the kind words!
@phantomtoast5747
8 жыл бұрын
I'm not long away from a Physics prelim. This really helped! Thanks :)
@faffaflunkie
8 жыл бұрын
I've been doing this stuff for years and I didn't even know that there were _two_ methods for calculating _voltage drop._ Well I learned something.
@CharlesEstabrooks
8 жыл бұрын
I'm glad to hear that.
@soyboi3988
8 жыл бұрын
Charles Estabrook
@anitkithra
7 жыл бұрын
This was a very helpful video. I'm studying for my physics midterm. Thank you.
@jamessperry5896
6 ай бұрын
My teacher explained this so poorly with zero context lol... so thank you
@williamstaib4623
10 жыл бұрын
you sound like tom hanks, good lesson, thanks
@CharlesEstabrooks
5 жыл бұрын
you're a funny guy, but thank you.
@rumchaser1able
9 жыл бұрын
Nice I like the double check method at the bottom ...easy !
@brobvision
10 жыл бұрын
Great, can you do one in Parallel too? Also a combination of both?
@chelsea3827
9 жыл бұрын
Thank you for this video, you do not know how much I was struggling with this!! but now I'm good :)
@gregorydorsey7649
10 жыл бұрын
this helped me soooooooooooo much, I was struggleing.
@sw3581
7 жыл бұрын
I appreciate how straight forward your video instruction is. It would be helpful if your videos were better organized or contained more key words pertaining to each topic listed in the description.
@CharlesEstabrooks
7 жыл бұрын
Thank you for your suggestions. I will look into those improvements.
@RaulGuadarrama
8 жыл бұрын
Thanks for this great video. It helped me to understand it in a very easy way. Plus I learned the "other way" too. :) Do you have a video for parallel circuits?
@namanwadhwa5734
6 жыл бұрын
thank u it really helped especially the second method to cross check
@RhemsonKende
5 ай бұрын
Thank you so much for the explanation
@Diganta_Khati
7 жыл бұрын
thanks for a calm lesson....
@the-beneficiary1809
2 жыл бұрын
great man big help THANK YOU!
@rishabhbirla3448
7 жыл бұрын
Nothing to say.... love you bro... 😊😊😉
@sandipbajare4157
6 жыл бұрын
Sir , it's the best video ever
@RosssRoyce
7 жыл бұрын
I put a voltmeter across all kinds of resistors and the voltage never drops, even with megaohm values! I want to reduce 9 volts to 3 volts to feed an electret mike from a plane's comm system. I've put resistors in parallel, in series, 10k, 50k, 500k potentiometers, voltage stays high. Thanks for vid!!
@ROYRDX
10 жыл бұрын
thank u this really help in my hw thank :)
@YourBoiiAnt
10 жыл бұрын
Great video, really helpful.
@ShaDoWxGFX
8 жыл бұрын
Thank you, I finally understand.
@rameshkumarnatesan8568
5 жыл бұрын
explanation is easy to understand.....keep up
@CharlesEstabrooks
5 жыл бұрын
Thank you.
@Freakorr
9 жыл бұрын
Great video.
@MrBillingtonK
3 жыл бұрын
How do you do it with only one resistor for example supply voltage goes through a 100K resistor to the collector of a transistor how would I work out how much voltage I drop through the resistor
@MrTrollBeast
6 жыл бұрын
Absolute legend!!!!!!!!!
@shadowreaper5413
6 жыл бұрын
Thanks a lot!
@joshuablanchard6789
9 жыл бұрын
great video, it helped a lot.
@daveosullivan580
9 жыл бұрын
Thanks Charles, much appreciated. I know your calculations are correct but... The reason I ask is I got a question that confused me, e.g. using your circuit for example, if you replaced R3 with a 'fuse' what is the voltage drop across the fuse if the fuse blows? Trick question? not sure!
@CharlesEstabrooks
9 жыл бұрын
First ask yourself two questions. 1) What is the resistance of a good fuse? 2) What is the resistance of a blown fuse? To answer these questions, you must understand that a fuse is simply a thin conductor which is designed to overheat and burn up if the current through it exceeds a certain amount. A good fuse has nearly zero resistance. A blown fuse is simply an air gap with essentially infinite resistance (Many megohms). Since voltage is proportional to resistance, the voltage across the blown fuse would equal the supply voltage.
@daveosullivan580
9 жыл бұрын
Charles Estabrooks Thanks Charles
@daveosullivan580
9 жыл бұрын
Thanks Charles I reason I ask is I got a question that confused me, in your example, if you replace R3 with a fuse, what is the voltage drop across the fuse if the fuse blows?
@susanagodinho1909
8 жыл бұрын
+Dave O'Sullivan 12V across the fuse.
@VenkatesanS
5 жыл бұрын
Well explained.
@jaysehara425
6 жыл бұрын
thanks this helped a lot!
@daveosullivan580
9 жыл бұрын
If the is a voltage drop after R1 of 1.32V, why would you not use 10.68V for the calculation of the voltage drop across R2?
@CharlesEstabrooks
9 жыл бұрын
Voltage drop ACROSS R1 is 1.32V, not AFTER R1. This means if you measure the voltage from one side to the other side of R1 you would measure 1.32V. The Remaining voltage drop (12V-1.32V=10.68V) is across BOTH R2 & R3. In other words, the SUM of the voltage drop across R2 plus the votlage drop across R3 equals 10.68V (Vr2+Vr3=10.68V). As you can see by my calculations, this works out to be the case (3.96V + 6.72V = 10.68V). When added to Vr1, you get the total voltage which equals 12V. This is basically the definition of Kirchhoff's Voltage Law.
@andreslara3693
8 жыл бұрын
Hi Mr. Estabrooks, I just wanted to know if you had a video on how to calculate voltage drops across a parallel circuit? I found your series circuit video very helpful.
@thoseguys5224
8 жыл бұрын
+Andres Lara Voltage in a parallel circuit is always the same no matter what, similar to how current (amperage) is always the same in a series circuit :)
@abdelaziz7298
10 жыл бұрын
nice videos thanks -morroco
@ArchAngelofGod32
10 жыл бұрын
In Physics class we worked a question where the total voltage supplied was 10V, but the amps came out to 2A (The professor did this part). But then in the circuit there was an 8ohm resistor on top, resulting in a 16V drop. What am I doing wrong?
@CharlesEstabrooks
10 жыл бұрын
I would have to see a schematic of your circuit to help you understand what is going on. Was it a simple series circuit, parallel circuit, or more complex circuit?
@camhart3217
9 жыл бұрын
Are you sure your its an 8ohm resistor, not an 8kohm resistor?
@CharlesEstabrooks
9 жыл бұрын
In a circuit with a supply voltage of 10V and a current of 2A, the total resistance would have to be R=V/I = 10/2 = 5 ohms, so clearly there is something more going on here. I refer back to my original reply. I would have to see a schematic of the circuit to understand what is happening. In any case, you CANNOT have a voltage drop higher than the supply voltage. That is one implication of Kirchhoff's voltage law.
@Michael-fs8zm
8 жыл бұрын
so all the voltage drop across each resistor must add up to the total voltage of the power supply?
@CharlesEstabrooks
8 жыл бұрын
+Michael Wang Exactly. This is the definition of Kirchhoff's Voltage Law.
@georgeiiicalendar4532
8 жыл бұрын
thank you very much
@roberth7559
5 жыл бұрын
Do you have a video for parallel circuits? And a mixture of the two? Thank you!
@CharlesEstabrooks
5 жыл бұрын
Yes. Just search my channel for the word "parallel"
@chalamkunda874
4 жыл бұрын
Thank you sir
@aravinds6698
6 жыл бұрын
Sir I have small doubt if the R1 resistor is only connected in the circuit. How to find the voltage drop
@CharlesEstabrooks
6 жыл бұрын
I'm not sure if I understand you, but if you're asking about if there is only one resistor in the circuit, then the voltage drop across that resistor equals the source voltage.
@hydroman1976
6 жыл бұрын
Trying to calculate with 120v circuit. Seems no matter what ohm resisters I use it always comes out to 40v drop. I stink at this. I=120/60(3 20ohm)=2 2X20=40v drop. If I start over and make each r 30 I come up with the same answer 40. What am I doing wrong? aaaah!
@CharlesEstabrooks
6 жыл бұрын
Just because the value of the resistors changes, doesn't mean the voltage drop across each resistor changes. If you're using 120V and three 20 Ohm resistors, your total current is 120/60 or 2Amps. Your voltage drop across each resistor using V=IR is 2 * 20, or 40V. Checking it with Kirchoff's Voltage Law, 40+40+40=120. If you're using three 30 ohm resistors, then your total resistance is 90 Ohms, so it becomes I=120/90 = 1.33Amps, and V=IR becomes 1.333 * 30 = 40V, so you're correct, your voltage drop across each resistor is STILL 40V.
@isaacleweni7169
Жыл бұрын
Thanks....✌
@WilliamLDeRieuxIV
7 жыл бұрын
The title of this video says: 'Voltage Drop' I'm sorry but I can't see anywhere in the video where the voltage drop is calculated...
@CharlesEstabrooks
7 жыл бұрын
Perhaps the difficulty is in your understanding of the term "Voltage Drop". This term simply means the voltage you would measure across a resistor or load in a powered circuit.
@WilliamLDeRieuxIV
7 жыл бұрын
What I was talking in terms of voltage drop was the drop in voltage after R1. The voltage across R1 is 0.12Ax110ohms = 1.32V (as shown in the video) To me the voltage drop is VCC - VR1 = 12V - 1.32V = 10.68V (this is how much R1 dropped the voltage or the voltage used by a load) -- it's just a matter of semantics. if you add up these voltage drops: 1.32V + 3.96V + 6.72V = 12V then the voltage drop should be 0V at ground since 12V-12V=0V. It's that part of the calculation that I did not see ....
@CharlesEstabrooks
7 жыл бұрын
What you call VR1 is what I call the "Voltage drop across Resistor 1". The same can be said for the voltage drop across each of the three resistors. As you said, it's a matter of semantics. Also as you mentioned, The "Voltage drop" across all three reisistors (or loads) is equal to the total or supply voltage. So I'm still not sure where the confusion is since you appear to understand it quite well.
@WilliamLDeRieuxIV
7 жыл бұрын
I guess what am I talking about is how to calculate the value of R to achieve a specific voltage drop. Now, that would just be algebraic math using ohm's law. Let's say the following: VCC=12V VDROP=10.68V VR1= VCC-VDROP = 12V-10.68V = 1.32V I=100ma R=VR1/I = 1.32V/0.1A = 13.2 ohms In other words calculating the value of R if you are given VCC, VDROP, and a specific current. What I was looking for -- when seeing the title of the video -- was how to calculate these things algebraically in order to confirm that the math -- that I was using -- was correct. For instance this site: www.pcboard.ca/led-dropping-resistor-calculator.html One single led Battery or Supply Voltage: 12V Voltage Drop Across LED: 10.68V Desired LED Current: 100ma Calculated Limiting Resistor: 13.2 ohms Nearest standard resistor value: 15 ohms Calculated Resistor Wattage: 0.132 watts (132mW) Safe power rating of: 0.22 watts (220 mW) This calculator is for calling the resistance that you need to drop the voltage to a specific value in order to limit it for use with an led (but could be any load) In this case all the information that you have is VCC, VDROP across Led, and the current -- and you need to calculate the resistance to achieve it.
@CharlesEstabrooks
7 жыл бұрын
OK, now I see what you're trying to do, but you've got things a bit confused. First of all, you're not likely to have a voltage drop of 10.68V across a single LED. Most LED's will exhibit a voltage drop (based on color & power consumption) of between 1-3V. Let's call it 2V. That leaves 12V - 2V = 10V for your resistor. You typically want to limit the current through an LED to about 30-50ma Maximum, much less than your 100mA value. Let's use 40mA. So applying Ohm's law, you get R=V/I = 10/.04 = 250 Ohms. In practice, I tell my students it's safe to use anything over 150 Ohm's, but it really depends on the specific LED you're using. You also need to be sure that your resistor can handle the power dissipation required. In my previous example, since P=IV, we would get P = 10 * .04 = .4 W. This could be a problem if you're using the tiny 1/4 Watt resistors. To be safe you'd need at LEAST a half-watt resistor. What may be a bit deceiving about that web site you referenced is that you can't just "pick" a voltage drop for an LED. Every LED has it's unique properties which determine what the voltage drop across that LED will be when it's wired into a circuit. Hope that helps. Mr. Estabrooks
@onenewworldmonkey
5 жыл бұрын
How can there be any voltage drop????? You said that resistors lower current (amps). Why didn't you say resistors lower current and voltage???
@CharlesEstabrooks
5 жыл бұрын
Perhaps your difficulty lies in the terminology. When we use the term "voltage drop", we mean the voltage you would measure across a resistor in a circuit. Resistors oppose the flow of current, they don't "lower current". Current will flow through a resistor when voltage is applied. The amount of current that flows is proportional to the voltage and inversely proportional to the amount of resistance. These relationships are expressed mathematically by Ohm's law: V=IR, I=V/R, R=V/I. Given any two values, you can solve for the third. Hope that helps.
@onenewworldmonkey
5 жыл бұрын
@@CharlesEstabrooks Thanks you. I believe much of my problem is in the terminology. Even when you say "across" or "through" the resistor. When you "measure" I imagine a probe touching a particular part. The verbiage is too loosy goosy to me. Any field that give v for volts, r for resistance, then i(?) for amps seems to not follow standards. I just watched another video when he calculated resistors in series and parallel, which helped me-although his terms were everywhere, too. Thanks again for the help.
@deepanshugajbhiye
9 жыл бұрын
can we solve V across capacitor by the same way using the formula CV=Q
@CharlesEstabrooks
9 жыл бұрын
Deepanshu Gajbhiye CV=q is a valid equation which expresses the relationship between Capacitance, Voltage (across the dielectric), and charge (q) stored on the plates, but it's not the same thing as voltage drop across a resistor since capacitors don't consume power in the same way as resistive loads. Assuming the voltage rating of the cap is higher than the source voltage, a capacitor in a DC circuit will "charge" until the voltage across the dielectric equals the source voltage (Vc=Vs), then current stops flowing. At this point in time, you can calculate the charge (Q) stored in the capacitor's dielectric using the formula q=C/V, but remember that at this point there is NO current flow.
@deepanshugajbhiye
9 жыл бұрын
then how will u solve the 1st on this question paper www.fiitjee.com/down/iit071.pdf
@JonNgwisha
6 жыл бұрын
thanks
@savannawalter2193
6 жыл бұрын
how do you find it when you have two electrical pathways?
@CharlesEstabrooks
6 жыл бұрын
Two pathways means you have a parallel circuit, and some of the rules are different. Search my my channel for Parallel circuits, Kirchhoff's current law or Ohm's law for more info.
@z3nkin
6 жыл бұрын
I just want a tutorial where there is a missing sum for resistor/voltage 1 or 2.
@CharlesEstabrooks
6 жыл бұрын
I'd like to help you, but I'm not sure what you mean by "missing sum". Are you referring to resistance, or voltage?
@carlusfournillier1156
6 жыл бұрын
hi which is your first video in this toturial
@CharlesEstabrooks
6 жыл бұрын
They're not in any particular order, just organized by topic.
@dinomir1719
5 жыл бұрын
can you please do a Series-parallel circuit
@CharlesEstabrooks
5 жыл бұрын
Series-parallel and parallel-series circuits are generally above the level I teach, but I will consider posting a video (or two) explaining how to solve them. I'm sure there are others already on KZitem.
@PJ-HT59South
8 жыл бұрын
can u explain how to calculate watts in a resistor in a series parallel...
@CharlesEstabrooks
8 жыл бұрын
+PJ Fuentes The Watt is the unit for power. Power can be calculated by multiplying current times voltage (P=IV), so if you know the voltage across the resistor, and you know the current flowing through the resistor, you can calculate the power in watts. If you have a single resistor in parallel with other resistors, you can ignore the other resistors, and calculate the current (I=V/R), then the Power (P=IV). You can also combine these into a single formula to calculate the power directly from the voltage and resistance (Power =V squared divided by R). Hope that helps.
@Sameer-rg9tx
6 жыл бұрын
sir new video resistance use only 440 voltage input resistance drop to out 220 voltage ac
@xmenxwk
8 жыл бұрын
But how do you calculate if there is only one resistor ?
@CharlesEstabrooks
8 жыл бұрын
+xmenxwk It's easy. The voltage drop across a single resistor in a series circuit equals the source voltage.
@xmenxwk
8 жыл бұрын
Charles Estabrooks so if 12v is source voltage, the voltage drop will be 12v ?
@CharlesEstabrooks
8 жыл бұрын
+xmenxwk Yes.That is the essence of Kirchhoff's Voltage Law. The sum of the voltage drops across all resistors in a series circuit equals the source voltage. So if there is only one resistor, the voltage drop across that resistor must equal the source voltage. 12v=12v.
@hazirahadnan3411
7 жыл бұрын
is that same voltage drop formula between series and paralel ?
@CharlesEstabrooks
7 жыл бұрын
No.
@hazirahadnan3411
7 жыл бұрын
so what the formula voltage drop for series circuit and parallel circuit
@CharlesEstabrooks
7 жыл бұрын
Please refer to my videos for a detailed explanation.
@rishabhbirla3448
7 жыл бұрын
bro come to my school.......
@danliusmonsales4054
7 жыл бұрын
do i need to round of the result of the IT?
@CharlesEstabrooks
7 жыл бұрын
Generally speaking, since resistor values are typically plus or minus 5% of the nominal, you can round your final answer. Be careful, however, of rounding intermediate calculations, then using the rounded value for further calculations. This will result in what I call "rounding error".
@camhart3217
9 жыл бұрын
??? If this is right then surely ohms law would dictate that at least 2 resistors are required to cause a voltage drop??
@CharlesEstabrooks
9 жыл бұрын
Not so. Obviously you can have one resistor in series with a voltage source. If this is the case, then ALL the voltage will be dropped across the one resistor. In other words, Vr1 = Vt. The voltage drop across the single resistor equals the total voltage of the source. Two or more resistors in series with a voltage source creates a voltage divider. Two resistors of equal value will create a symmetric voltage divider where the voltage at the point between the two resistors equals the voltage across each resistor which will be half the total voltage. In other words, if R1 = R2, then Vr1 = Vr2 = Vt/2. This is the essence of Kirchhoff's Voltage Law.
@camhart3217
9 жыл бұрын
I don't understand, if there is only one resistor are you saying then that will stop all the current?
@camhart3217
9 жыл бұрын
Charles Estabrooks you say that's not the case, but then you say Vr1=Vt which means there is no voltage drop.
@CharlesEstabrooks
9 жыл бұрын
Cam Hart You're misunderstanding the meaning of the term "voltage drop". The term "voltage drop" simply means the voltage you would measure from one side of the resistor to the other.
@camhart3217
9 жыл бұрын
So what would happen to 12v with a 1kohm resistor in a circuit?
@whitehairedbadass3475
5 жыл бұрын
so the second method doesnt need current.....seems easier
@CharlesEstabrooks
5 жыл бұрын
I'm not sure what you mean by the question, but calculating total resistance in a circuit, assuming you know the values of all resistors or loads, never requires current. You need to know total resistance to determine current flow, however.
@whitehairedbadass3475
5 жыл бұрын
@@CharlesEstabrooks oh thanks....already finished school tho just waiting for the results. Hope I passed, ur vids were helpful.
@headphonecup
9 жыл бұрын
how/why does I(T)=I(R1)?
@CharlesEstabrooks
9 жыл бұрын
In a series circuit, current is the same everywhere, regardless of where you measure it. That's what is meant by It=Ir1=Ir2=Ir3
@lhmsilva011
9 жыл бұрын
+headphonecup think about it like the current is always at the same point. Like a straight line. That's why current is not constant at parallel circuits.
@CharlesEstabrooks
9 жыл бұрын
Yes, resistors reduce current, but they do it in a combined manner, and the current is based on the total resistance. Think about a series of water pipes, each of a smaller size than the previous. Since they are in series, the water can only flow as fast as the smallest pipe allows. The water cannot flow faster in the larger pipe since it is connected to smaller pipes down the line. The flow (current) is constant throughout the series. This is a fundamental principle of series circuits. HTH.
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