Studying for the FE and this helped me understand that current sources get opened, while voltage sources get shorted. Thanks for the video. Cheers
@mosesdanielshihepo63
4 жыл бұрын
great men you deserve two cold beer🍺🍺 .please share star delta and node voltage
@dsalex2859
3 жыл бұрын
kzitem.info/news/bejne/uqp_mG1qnJx8gJg
@giftjiana4583
4 жыл бұрын
Any reason for using 1/8.33, 1/8.33, & 1/2? Instead of inserting the exact values 8.33, 8.33, & 2 the when calculating I1? #confused.
@lpjtechno4612
2 жыл бұрын
that is how we calculate the total resistance in parallel. 1/R(p.total) =1/R1 + 1/R2. @ENGRTUTOR , may you please confirm if l am right.
@LFTRnow
Жыл бұрын
Technically the fraction IS the more exact value, but the main reason is to show how the math occurred. Recall that a resistor pair in parallel is R1*R2/(R1+R2), so for example if R1 is 10 and R2 is 3, you get: 30/13. 30/13 is an exact number, which you can approximate as 2.3077 but that is not the exact number, nor is it clear where 2.3077 comes from without showing the fraction first. You also could have done it using the 1/Rt = 1/R1 + 1/R2... formula, but that also gives you the same fraction, it just happens to work for more than 2 resistors at once. Tip - any parallel combination of resistors will always have LESS resistance than even the smallest resistor. In this case, 10 and 3 were combined to give roughly 2.3. If you get a number larger than the smallest resistor, you did it wrong, and your most likely error is you forgot to flip the number at the end, that is 1/x.
@thelord2017
8 жыл бұрын
Give that man a cookie! :D
@dsalex2859
3 жыл бұрын
kzitem.info/news/bejne/uqp_mG1qnJx8gJg
@john_smith_john
5 жыл бұрын
thank you for learning how to speak good english
@superkrystal98
6 жыл бұрын
something looks off with this guys current division. Am I the only one confused?
@wisanikhipa_vlogs742
6 жыл бұрын
NOP
@YouKnowMeDuh
5 жыл бұрын
Actually... He used a strange formula for it, but it's the correct answer.
@MusicGameFinatic999
5 жыл бұрын
Yeah, I was thrown off by that as well.
@nadeesharuwanga
5 жыл бұрын
yeah,....that's method is not eassy
@Nickaholic
5 жыл бұрын
2:50 “Lets use voltage divider.” Then places a huge ass equation without explaining any of it.
@leejohnson197733
Жыл бұрын
so if i have r1, r2, r3 in parallel and 2 power sources, if i want to find the current at just r1,do i only need to workout current for each source using this theorem, then add together ?
@AndromedaIX
6 жыл бұрын
Great video, thanks a lot! Superposition, Thevenin and Norton seemed kind of abstract to me, but you explained it very well :)
@deangelocesar5666
3 жыл бұрын
I know im randomly asking but does anybody know of a way to log back into an Instagram account..? I stupidly forgot the password. I love any help you can give me.
@jettchaim4098
3 жыл бұрын
@Deangelo Cesar instablaster =)
@deangelocesar5666
3 жыл бұрын
@Jett Chaim i really appreciate your reply. I got to the site thru google and I'm waiting for the hacking stuff atm. I see it takes quite some time so I will reply here later with my results.
@deangelocesar5666
3 жыл бұрын
@Jett Chaim it did the trick and I actually got access to my account again. I am so happy! Thank you so much you saved my ass!
@jettchaim4098
3 жыл бұрын
@Deangelo Cesar happy to help :)
@jaypeemillan6079
5 жыл бұрын
Hi why is that you open the 1A then you short the 10A?
@ENGRTUTOR
5 жыл бұрын
There is no 10A, it is a voltage source 10V. Current sources are opened to remove their influcence (ie. set current to 0A) and Voltage sources act as a short when their influcence is removed (ie. voltage between two pts is 0).
@Tranksmighty
6 жыл бұрын
better than my lecturer😂
@TitanXelon
10 жыл бұрын
Why are you doing !/R for you current divider?
@yoyo510
9 жыл бұрын
Yeah, at 6:30 I think it's supposed to be ((1/2)/((1/2)+(1/8.33)))*1 since it's current division (which is I1 = (R2/(R1+R2))*Isource)
@zaid_marridi
9 жыл бұрын
Yes that's correct but why did he use 1/R instead of just R --> 1/2 instead of 2 and 1/8.33 instead of 8.33 ??
@badhombre4683
9 жыл бұрын
+Titan Xelon Idk why he's doing that but if you just follow the formula you'll get the answer he got. Just remember that according to the formula the numerator is the OPPOSITE resistor from the resistor we are interested in. I1 = [r2/(r1+r2)] * Is. There's no reason to do reciprocals like him. The formula works
@dude_adm
8 жыл бұрын
Good question, that's because they're in parallel and he didn't wanna get the voltage then divide by the resistor. Piece of cake
@1028nan1004nk0912hl
7 жыл бұрын
The RECIPROCAL always works. The simple formula you list is a special case where there are only 2 resistors.
@naomio8163
Жыл бұрын
the best to ever do it 🙏
@reubenwilliammpembe667
5 жыл бұрын
Thank you Sir - you are the best #RespectFromSouthAfrica
@gameadict119
5 жыл бұрын
In first can we take 2ohm restistor series with 10ohm resistor parrell to 5ohm resistor?
@KwasiDapaah-hh1kz
6 ай бұрын
Can you use nodal analysis in this question?
@emelymurillo8325
3 жыл бұрын
Some heroes don't wear capes...
@naimkhannikmal9630
4 жыл бұрын
superb excellent outstanding
@Creative_drawing55555
2 жыл бұрын
Here ,i have one doubt instead of voltage divider is there any other method..
@logeshg2471
4 жыл бұрын
why wounldn't you the mesh or nodal in between this analysis . or is this the only rule to solve this by superposition theorem
@trialshorts11
4 жыл бұрын
He is using nodal Pointing v1,V2 in junction
@emirjais7471
2 жыл бұрын
i found one method using current division.. Thank you
@joujoufox
2 жыл бұрын
definitely need more questions very nice method
@wirelessgcf3889
3 жыл бұрын
Thanks😀 Why not use kcl voltage node to slove it ? Find v2,v1 and then to find IR5 current
@ENGRTUTOR
3 жыл бұрын
There are plenty of ways to solve this problem. I am showing ONE.
@psedach
2 жыл бұрын
Some students for assignments/homework are forced to demonstrate the use of this method. Some problems are harder to solve without it.
@carultch
Жыл бұрын
You can use KCL and KVL and set up a system of equations, and solve through algebra. The superposition method allows you to solve more directly, so you don't have to do nearly as much algebra. It's a simple matter of drawing each version of the circuit with the other source nullified, combining resistors, and using voltage dividers and current dividers to isolate the either voltage or current that applies to the resistor of interest.
@zchosenyoutuber3675
7 жыл бұрын
Did he calculate the current i1 correctly? it's on the beginning of 6:30
@zchosenyoutuber3675
7 жыл бұрын
Help!
@1028nan1004nk0912hl
7 жыл бұрын
yes
@1028nan1004nk0912hl
7 жыл бұрын
Yes it is current division. That is why he does (1/8.33)/(1/2 + 1/8.33) * 1A. Notice that he does not do R1/(R1+R2). Instead he does (1/R1)/(1/R1 + 1/R2). Look at SLIDE 3 of this PDF note (tuttle.merc.iastate.edu/ee201/topics/analysis_techniques/dividers.pdf)
@Pimpinpark777
7 жыл бұрын
Yes, you can do it that way as well
@zneiko
6 жыл бұрын
Why did he put 1/2 in the resistors when he can just use the formula I1 = 2 / (8.33+2) * 1A ?????
@abcdefghij7256
3 жыл бұрын
Thank you for this☺️
@devandlapadmavathi2173
5 жыл бұрын
I want source transformation technique to the same problem
@mohithkankanala8336
2 жыл бұрын
Very Clean!
@elliotstrickland5004
8 жыл бұрын
Very helpful, thanks a lot :)
@carmeloalmaiz6756
5 жыл бұрын
Much more understandable.
@bahaatamer1245
5 жыл бұрын
at 6:15 I still dont understand why the Resistances all had a 1/R in the Current divider equation!
@shukishan
4 жыл бұрын
I had the same doubt, I just plugged in some numbers in the calc and realized that (1/r1)/(1/r1+1/r2) = (r2/r1+r2)
@dsalex2859
3 жыл бұрын
kzitem.info/news/bejne/uqp_mG1qnJx8gJg
@ooiyaosheng6863
7 жыл бұрын
6:10 can i bypass all and only left 2 ohm
@jawadulkabir9120
6 жыл бұрын
no . because the equivalent resistance is even less than 2 ohms and we all know how the current likes the path of least resistance
@stafenburg__3891
4 жыл бұрын
Got the same answer using mesh analysis.
@jianyanchoong5762
4 жыл бұрын
how did he get 15/50 ohm 5:24
@stafenburg__3891
4 жыл бұрын
@@jianyanchoong5762 He added the two resistor using parallel addition.
@sorayaadjabi6093
4 жыл бұрын
Thanks a bunch ❤️
@jswnt5
5 жыл бұрын
How to find current by spt? broooo
@shampoophrt
5 жыл бұрын
WHY DIDNT YOU REMOVE THE WIRE IN THE VOLTMETER CASE BUT REMOVED IT IN THE AMMMETER CASE THIS MAKES THINGS DIFFERENT PLS EXPLAIN
@ENGRTUTOR
5 жыл бұрын
It is not a Voltmeter or Ammeter -- the problem shows a VOLTAGE SOURCE and a CURRENT SOURCE. Setting Current source to 0 means no current (aka broken wire)... Setting Voltage source to 0 means your are measuring voltage across the same node (aka same wire).
@freemankodjoafedo5974
7 жыл бұрын
i have a problem solving complex numbers, I need some one to help me over come this situation.
@Shafixy
5 жыл бұрын
looks like the problem is very complex
@flyinglack
4 жыл бұрын
@@Shafixy nice
@kapiladhikari517
3 жыл бұрын
THANKS MYAN
@letsentertain6439
8 жыл бұрын
good... thanks alot
@CXT300
7 жыл бұрын
Thanks a lot
@kcampbell9248
9 жыл бұрын
kinda confusing bc it seemed like you were using nodal analysis with superposition
@nikzzi0511
9 жыл бұрын
pretty helpful.
@mbs5014
7 жыл бұрын
Ridiculous explanation
@moazelsawaf2000
4 жыл бұрын
Thanks sir
@dsalex2859
3 жыл бұрын
kzitem.info/news/bejne/uqp_mG1qnJx8gJg
@zacharydelgado2279
5 жыл бұрын
I1 at 6:30 should equal 0.1936 Amps not 0.1935, not that it matters during rounding.
@groundcontrol-x8701
7 жыл бұрын
This is way to Heavy...Man...)...Got a piping sound in my Left ear,trying to follow-Had to give it Up...)... X ...)
@nathaniallarkin6060
Жыл бұрын
Noice
@kassandrablood7852
9 жыл бұрын
Hi nice job, Im IC layout designer and I would like to talk to you sometime, I love the way you work in Mentor tools. Let me know of you interested talking sometime. thanks
@dsalex2859
3 жыл бұрын
kzitem.info/news/bejne/uqp_mG1qnJx8gJg
@Suppboio
7 жыл бұрын
I find this method stupid
@denvercharlebois699
3 жыл бұрын
What an awful way of explaining superposition
@jumahezron6881
6 жыл бұрын
i regret the time i have spent watching this video
@user-hj3gl1uk7w
7 жыл бұрын
노무현
@2012javad
6 жыл бұрын
just awful explanation.
@shreeyasingh2361
5 жыл бұрын
Above all, can you please use your ORIGINAL accent to explain rather than comparing it with foreigners..i couldn't understand any of your twisted and rolled tongue words. It is not necessary to show off your language or vocabulary while you are teaching. Besides this spoils your teaching lessons... Thankyou.
@judy-chan4536
4 жыл бұрын
this means you're just dumb to begin with. if foreigners can understand heavily accented english; in this case non-indians understanding indian accented english, then why can't you?
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