I love the balance between being straight to the point and giving enough explanation so that the concept sticks. Very few math educators are able to walk that tight rope as good as you sir.
@S25J9
3 ай бұрын
Amazing video. You presented the Hessian Matrix in a way that was easy to understand and visualize. Thank you so much David.
@dagmarski4133
3 жыл бұрын
Clear and straight to the point, thank you!
@vitorsousa5390
Жыл бұрын
Very good ! Thanks!
@PHOENIX-mv3uc
2 жыл бұрын
I'm a student from Morocco Thanks a LOT !!!
@EggZu_
2 жыл бұрын
swear i was looking through my notes for like an hour and a half before just googling it haha
@sohanjangid1207
3 жыл бұрын
Thanx for video
@segundobenito5541
Жыл бұрын
THANK YOU
@charlescains2091
3 жыл бұрын
Maths student from the UK, thanks for this video
@davidfriday7498
3 жыл бұрын
I'm glad you took something positive from this!
@sohanjangid1207
3 жыл бұрын
Hey buddy
@justinchey2281
Жыл бұрын
Thank you! I couldn’t find online what D=0 means
@henryblauth9823
3 жыл бұрын
This is also known simply as..... the D
@davidfriday7498
3 жыл бұрын
My personal favorite way to refer to it :-)
@malkavian6275
2 жыл бұрын
slashy slashy
@sirig03
8 ай бұрын
trauma inducing indeed when D=0 !
@AverageAlaya
2 жыл бұрын
I got a case where my determinant is zero... help :')
@davidfriday7498
2 жыл бұрын
If you provide more information, I can certainly help. What was the original function?
@AverageAlaya
2 жыл бұрын
@@davidfriday7498 Thank you! The function is f(x,y)=x^2+y^2+x^2y; I got the roots but the root -sqrt(2),1 seems to have a determinant of 0. Thank you!
@davidfriday7498
2 жыл бұрын
@@AverageAlaya I took a look at the graph using Geogebra: www.geogebra.org/3d?lang=en I see what looks like a local minimum at (0,0) and saddle points at the other two critical points, including the one you sent. I'll try the problem and see if I get the same result as you.
@davidfriday7498
2 жыл бұрын
@@AverageAlaya I have completed the problem. I believe I see the issue. When I set the partial derivative with respect to x equal to zero, two cases arose: x=0 or y=-1. I believe you plugged in y=1 rather than y=-1 to the Hessian determinant. This would result in a D value of 0 rather than a D value of -8, which is what I got for both (sqrt(2),-1) and (-sqrt(2),-1). I hope this has helped you in your interpretation of your problem :-)
@tangpiseth8416
2 жыл бұрын
@@davidfriday7498 Hi I also encounter the same problem. May I ask for your help?, the function is: f(x,y,z)=x^4+x^2y+y^2+z^2+xz+1. There are 3 critical points, one of them is at (0,0,0) and the first principal minor(the bordered Hessian determinant) evaluated at that point is 0. Since the graph of the function is in the 4 dimensions... so I can't use any graphing utilities to help me see the behavior of the graph at that point. Maybe plotting its level surface and with inspection help?
@cocomatef
Жыл бұрын
oh ,why nobody actualy showes a solution of problem with actual numbers???
@davidfriday7498
Жыл бұрын
Then I believe you should probably watch this video: kzitem.info/news/bejne/02p3t6tniZZ1haA
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