Sir in case 3.. If Ta1 is very large Tco=max((max(Tx1, Tci) +Ta2), Ta1) +Tor
@himanidangi2213
4 жыл бұрын
This is more generalized expression.
@somlaeducations3308
4 жыл бұрын
bro if you have pdf note plese send me to bhukyasomla11@gmail.com
@parthahluwalia6018
4 жыл бұрын
Yes correct one
@aayushiprakash167
3 жыл бұрын
@@utkarshpandey6508 its OR gate which doesn't depends on other input if its one input is 1,and not the AND gate.
@KaranKumar-og2vk
2 жыл бұрын
Thank you sir
@JainBhawna26
4 жыл бұрын
In 38:03 seconds let say A2 has delay of TA2=5 sec and A1 has delay of TA1=2 sec then firstly OR gate will get 0 from A1 and then it will wait for A2 ,so Tc1 should be TA2+TOR ???? then Tc1 should be max(Tx1+TA2),TA1)+TOR????? please clear it out,Sir
@abhijeetpradhan143
4 жыл бұрын
Nice question
@SunilSingh-nv1yh
3 жыл бұрын
If u r discussing about initial addition then, initially carry in would be zero with no delay,so when it comes to and2 gate,then according to property of and gate if any one of the input would be zero then it will not wait for another input to come and immediately decides it's result,so according to me Tc1 would be equal to "max(Ta1,Ta2)+Tor",if wrong pls try to correct
@ashutoshsrivastava9864
3 жыл бұрын
@@SunilSingh-nv1yh haan bhai yhi mai bhi soch rha ki agar carry zero h to koi delay nii hoga mgr jb output a2 se aayega tb to uska delay lenge na to max(ta2,ta1)+tor hona chahiye
@princekushwaha3210
2 жыл бұрын
7:01
@himanidangi2213
4 жыл бұрын
Sir, In the example you gave for full adder, how will the adder know there is no carry from previous adder untill unless previous adder performs addition and sends Cout. Thus it should require delay till previous adder preforms it's addition.
@niteshnaruka8927
4 жыл бұрын
Same doubt here
@JainBhawna26
4 жыл бұрын
Delay is considered only when the state is changed or transition from one state to other state occur. If the carry is already zero(meaning signal low) and cout is also zero meaning no state change so no delay:))..hope this clear your doubt.
@thankyouforwatching-o7g
3 жыл бұрын
thankyou sir
@padamjaitpuria2530
2 жыл бұрын
Garda udaa diye sir!
@Familyserialdrama
3 жыл бұрын
17:56 half adder to full adder 21:45 propagation delay
@anamikapathak42
4 жыл бұрын
Even if the carry is not generated from the previous stage but the next adder will still have to for its value(even if it is zero) that will cause delay right??? Then why we are not considering that delay sir??? Confused🤔
@RealSatyamPriyadarshi
4 жыл бұрын
if one i/p is already 1 why would it wait for another input(either 1 or 0).
@JainBhawna26
4 жыл бұрын
Delay is considered only when the state is changed or transition from one state to other state occurs. If the carry is already zero(meaning signal low) and cout is also zero meaning no state change so no delay:))..hope this clear your doubt.
@ShivamSingh-vh6rj
3 жыл бұрын
Sir you have told that 9 NOR gate required for Full adder but in book of P.Raja. there is 12 gate . And also by 9 gate the expression of carry is wrong .... Please tell us sir and see at - 55:00 Thank you sir
@gamewallah6605
Жыл бұрын
sir in case 3, Tc0=min(Tx1,Tci)+Ta2+Tor
@SachinGupta-co1sb
3 жыл бұрын
22:55 pe aapne bola sir ki OR ka ek bhi 1 aata hain toh delay nhi krta. Lekin disabled gate main gate ka delay count nhi krte hain phir aapne carry ke output main and + Or kyu kiya?
@mahnaazmansoori1005
4 жыл бұрын
Very very nice
@RealSatyamPriyadarshi
4 жыл бұрын
if we using extra 2 inverter in full sub then we also need 2 extra NAND gate?
@ashishsaxena7906
4 жыл бұрын
Thanks sir for this awesome class
@sumanjena9711
3 жыл бұрын
21:55
@pravendra_pratap_singh
3 жыл бұрын
Thanku
@deepachapi1153
4 жыл бұрын
Thanku sir......
@dileshsahu859
4 жыл бұрын
super
@vkichinni4015
4 жыл бұрын
33:05 IF xor1 output (or) And1 output comes first as 0 the otuput of And2 will get fixed to 0 so output of And2 should be min(Tx1,TA1).
Пікірлер: 37