very good i have to design a project for college and we are using a bunch of these. thanks for explanation
@FoolishEngineer
Жыл бұрын
You are welcome!
@1986ah
2 жыл бұрын
Very simple explanation! Thank you
@merabharat-l7c
2 жыл бұрын
Emitter current is equal to base current plus collector current. So here question is arises that 122ohs resistance branch current is equal to emitter current.pls explain
@WistrelChianti
2 жыл бұрын
That was very helpful (I think). Would I be right in thinking at that input voltage it's super inefficient? i.e. there's more power dissipation over the other components than from the LED?
@FoolishEngineer
2 жыл бұрын
Yes, you are correct. But it is cost effective & easy to use
@WistrelChianti
2 жыл бұрын
@@FoolishEngineer thanks for confirming. I really wasn't sure!
@user-pw7xc2ml7e
6 ай бұрын
Hi if we using voltage 3.7 with constant current of 10mA or 20mA or 30mA and than we want to voltage should be less than 3.5 . so what components should be use?
@brunoaugier
Жыл бұрын
First, I am very far to be an expert but maybe this can help understanding efficiency of this circuit and why in some cases it can be usefull and give a good efficiency while in other cases it will give poor efficiency and should be avoided: IMHO, I think this circuit is suitable and very usefull when the load is well know and components are adjusted to average load and do not change too much, it is not really made to be versatile and used with uncontrolled loads. As the base & zener diode currents are very small they may be ignored in total power consumption, so powering a single 2.2Vx50mA LED (110mW) with a 14V battery ouputting at least 50mA will always result in a bad efficiency as the total consumption with this circuit will always be at least 700mW for 50mA (14*50), wich give an efficiency of 15% for A SINGLE LED (590mW lost). But : 1 - with a lower voltage V+, efficiency can increase a lot, using lower voltage zener (or maybe rather one or two regular diodes) but it would become less versatile and wont allow a big change in loads, ex: with V+=3V and one or two regular diode in place of the zener diode, it would give an efficiency of ≃ 75% as PT = 3V*50mW = 150mW 2 - efficiency can also be a lot better in case this circuit is used for more than one LED, with a maximum of 3 LED in this specific case (V+ = 14V and zener = 6.8V) wich give 2.2*3=6.6v (330mW), then the efficiency become 15%*3 ≃ 45% (or 330mW/700mW), efficiency can be even higher with more LED using a lower voltage zener. PS: in case it is necessary to deal with a wide range of unpredictable loads there are probably a lot of better and more versatile ways, but more complicated and costly (like DC-DC Buck converter).
@rushikeshkumawat1361
2 ай бұрын
Can we use it as Laser Driver Circuit ?
@umesh.kumar.naik278
7 ай бұрын
5:19 sir.. one double.. where is written 10mA on datasheet.. a am confused.. please reply... thanks
@raymondng9112
Жыл бұрын
How did you get 10mA for Iz? not 37mA?
@shivakumart2106
3 жыл бұрын
Very good....thank you...
@FoolishEngineer
3 жыл бұрын
Thank you so much for watching!! Please subscribe to our channel
@kabandajamir9844
2 жыл бұрын
So nice
@FoolishEngineer
2 жыл бұрын
Thank you so much for watching!! Please don't forget to subscribe to our channel
@ankushathawale3473
5 ай бұрын
What if we need a 8V Across the load
@Maha-hp5wb
2 жыл бұрын
THANKYOU AMAZING
@enginstud8852
3 жыл бұрын
What do you think of’proteus for circuit simulation? it seems to me their are not very precise regarding some transistors’s specs, i Don’t know about LTspice
@FoolishEngineer
3 жыл бұрын
LTspice is used widely in industry. I don't know about Proteus! Thank you so much for watching!!
@jboy4real
Жыл бұрын
Why you selected 6.8v zener diode
@onkarkapale6085
3 жыл бұрын
Sir , i want to make a constant current power DC driver , for my LED strip .. The required constant current is around 300 mA , and Load is around 60v , plzz suggest something acoordingly ..
@FoolishEngineer
3 жыл бұрын
You can use the same circuit
@onkarkapale6085
3 жыл бұрын
300 mA current ?? Same circuit is able to power that much current ??
@sohambalakrishnan2260
2 жыл бұрын
Can you pls tell which simulator you are using?
@FoolishEngineer
2 жыл бұрын
LTspice
@vikrantmakar4597
3 жыл бұрын
Big fan
@FoolishEngineer
3 жыл бұрын
Bas kya Bhai!!!!
@tranluan9391
3 жыл бұрын
Can I know why the Vz and the Vre should be the same? I think Vre should be Vz - Vbe. Am I wrong?
@FoolishEngineer
3 жыл бұрын
Imagine Vz as a reference and Vre is the negative feedback which is given to the regulator, as mentioned in the working the voltage drop across both zener diode & Re takes care of the regulation process.
@tranluan9391
3 жыл бұрын
@@FoolishEngineer Thank you so much. It took me 3 weeks to understand the idea. Because the feedback path for this circuit is implicit. So it's so hard to understand.
@shazmiah
2 жыл бұрын
Foolish Engineer, that's a bullshit response. Vz and Vre are NOT the same!. Vre will always be ~0.7 volts lower than Vz. The base -emitter junction of the BJT acts like a diode. Build the circuit and see!
@shinzon0
Жыл бұрын
This can't be... if there is a voltage V_BE, then V_Z = V_BE + V_RE, and not V_Z = V_RE... V_BE should be around 0.7V if it is made of silicon, so V_RE is 0.7V smaller than V_Z. At 3:38, it is wrong... later you include V_BE = 0.7V and then it is right... XD
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