Excellent tutorial, very clear and concise. Thank you!
@thewyk
5 жыл бұрын
Amazing stuff, even though this is my first comment ever on the channel, I watch many of your videos and appreciate the effort you put into them. Keep making more!
@robojax
5 жыл бұрын
Thank you very much. I am glad you found them useful.
@mmuller3233
5 жыл бұрын
Great information and well explained illustration & commentary, satisfied me too!.
@robojax
4 жыл бұрын
Good to hear that.
@ShahidAfridi-cp1kq
4 жыл бұрын
Greeaaaaaaaaàaaaat, I have a question, Can we connect ACS712 and a relay with a same load, i.e to check if the current flowing from the load exceeds a certain limit, then the load can be disconnected or turned off automatically through the relay.?
@huzefaali9374
4 жыл бұрын
Very informative question
@robojax
4 жыл бұрын
with ACS712 the variable "current" is holding the current. if you watch both videos fully without skipping, it would very easy. if you don't want to learn then hire someone here www.upwork.com/ and pay someone to do it for you. Choice is yours. I have provided for free so you watch and learn. Good luck
@karimismail3734
3 жыл бұрын
Fine tutorial. Thanks الله يحفظك وشكرا
@robojax
3 жыл бұрын
You are welcome. Here is $200 Arduino course for free Arduino Step by Step Course (over 100 lectures) Starts here robojax.com/L/?id=338
@ismailaydinoglu3888
3 жыл бұрын
thanks alot for you information.also may you say that how many min. volt need for relay on working position.
@robojax
3 жыл бұрын
Just read what’s on the relay. For 5V it may hold up yo 3.7V. Unless you try, you will never know as not all relays are produced by the same manufacturer.
@MrKYT-gb8gs
2 ай бұрын
This bothers me somewhat. I need to power the arduino separately from the bulb? I already have a cable going into the wall. Is there a way to split the bulb wire into parallel and run it through a ace converter and power the arduino which controls the relay and the other branch of the wire? So there is a single source of power?
@robojax
2 ай бұрын
In this video it is assumed the that you know how to power your arduino board. It is very simple. Connect it to a usb. Now if you don’t know that either, the arduino board has a usb connector which you can program via computer or power it up.
@codygaudet9842
Жыл бұрын
Great info, wondering though if I can connect two relays to one Nano? I only see 1 5v pin on the Nano, Thanks!
@robojax
Жыл бұрын
you can do it. split the 5V for two relay or use breadboard kzitem.info/news/bejne/mamLz56mgJpprII
@nasimheidari3365
3 жыл бұрын
Great! Thanks
@robojax
3 жыл бұрын
You're welcome!
@amineatmane7592
3 ай бұрын
can we create create different level of intensity like a pwm signal with the relay
@robojax
3 ай бұрын
No we can’t.
@yubaloliveras9232
3 жыл бұрын
Do you need to electrically protect or isolate the Arduino from the load controlled by the relay, or from the relay itself? I've seen it done with optocouplers to isolate but you're not using it, so I'm confused. Maybe depends on the load? I want to control a 300 watt 120v AC fogger.
@robojax
3 жыл бұрын
the AC portion of the relay is already isolated. This relay module has driver that drivers the relay. In some instances people prefer to isolate the driver and power it up from separate source. If you look at the rating of relay and do the math, at 120V it can handle about 1200W . It is your decision. But I would use this relay if I respect the rating of of relay and not overload it.
@QuickMind
5 жыл бұрын
Pleaso do this video but also using a Nextion touch lcd to activate the arduino and relay :)
@robojax
5 жыл бұрын
Sure I will have to get the module first. Or may be I already have it in one my bins. I got so many items and never got time to make video . Life if tough.
@arnoldjr3136
13 күн бұрын
Hi! How do I know if what wire to cut? Amazing video btw!
@robojax
12 күн бұрын
For better safety cut the live wire. There are live wire tester .
@GamingGodCops
5 жыл бұрын
SIR UR Videos too much satisfied me 💯
@robojax
5 жыл бұрын
Good to hear that.
@kleinvosseven
9 ай бұрын
Hi, can I use 2 reedcontacts to put the light on ore off without the arduine
@robojax
9 ай бұрын
Hi, it is very simple. see this page shivkumardas.wordpress.com/tips-and-tricks/hand-switch-connection/
@kleinvosseven
8 ай бұрын
thank you, but I mean with out a switich, the relay must be the switch. what kind of relais do I need than. reedcontact must switch a relais one and an other reedcontact must switch the relay off. thank you regards Teuntje
@robojax
8 ай бұрын
this relay can be turned on with reed switch. yes.
@markuslemerise5812
2 жыл бұрын
thank you
@anggadamanik8506
5 жыл бұрын
You're using NO and COM on relay. So, the relay would be in "Closed" state if there's any signal from arduino. But why the bulb is ON when the signal is LOW in the program. LOW signal=0V means no signal, since you're using NO, the bulb shouldn't be ON. Please help:(
@robojax
5 жыл бұрын
I have explained it that the relay module is "low trigger" meaning it need LOW to turn ON and HIGH to turn OFF.
@jarafeyisa6913
4 жыл бұрын
hi, how i can write a code for current sensor to read only the maximum value ; and again how it can be interfaced with arduino?
@robojax
4 жыл бұрын
Hi, here is my video on Current Sensor: kzitem.info/news/bejne/lHlpmXimnIWofKw this is for 5-30A but I have other videos on current see them here kzitem.infosearch?query=current
@DeViLsCrEaTiOn
5 жыл бұрын
Hi, i am from india. I have a question. can i power up a 5 volt 4 channel relay module with a 5 volt 0.7-0.8 mAh wall type charger, which is basically use for charge the simple mobiles. If yes, then how i connect, i mean what will be the circuit diagram. which wire will be connect with the vcc and which wire connect with the ground and which wire is connect with the ESP8286. i am try to built a home automation project. Thank you very much. Please help me.
@robojax
5 жыл бұрын
Hi, Here is the video on 4 channel relay. kzitem.info/news/bejne/uJijmYF5hpl-kqg Ahmad from Canada
@alimz4891
4 жыл бұрын
سلام،خوشحالم که اموزش فارسی شما رو دیدم.🌹👏 سوالی دارم اگر به طور مداوم و شبانه روزی با استفاده از رله دو کانال و اردینو دستگاهی را خاموش و روشن کنم بنظر شما ایا آردینو آسیب میبیند یا خیر؟ ممنون
@robojax
4 жыл бұрын
وعلیکم السلام. سلامت باشد. خوشحالم که زیرنویس فارسی مفید واقع میشود. بلی میشود که ماه ها روشن باشد.
@robojax
Жыл бұрын
سلام علیکم. مجرا (کانال) فارسی علم و فن را راه اندازی کردم: لطفا به دوستان تان خبردهید و حمایتم کنید. www.youtube.com/@ilmofan
@user-cb4vv4yw4q
2 жыл бұрын
شكرا الاساذ احمد
@robojax
2 жыл бұрын
عفوا
@jarafeyisa6913
4 жыл бұрын
thank you, when i use the following the relay is continuoesly animated-ON-OFF, what could you help me if (current >= 25.69 ) { float voltage_raw = (5.0 / 1023.0) * analogRead(VIN); // Read the voltage from sensor voltage = voltage_raw - QOV + 0.012 ;// 0.000 is a value to make voltage zero when there is no current float current = voltage / sensitivity[model]; if (current >= 25.69 ) { lcd.setCursor (0, 1); lcd.print("I: "); lcd.print(current, 2); // print the current with 2 decimal places lcd.println("A"); digitalWrite(relayPin, LOW); delay(500); } else { digitalWrite(relayPin, HIGH); lcd.setCursor (0, 1); // set to line 1, char 0 lcd.print("Normal Current"); delay(500); }
@robojax
4 жыл бұрын
am I reading is correctly? this video is not about current. It is about relay. Also there is no LCD here. Please post it under the relevant video so I know what are you talking about.
@jarafeyisa6913
4 жыл бұрын
sorry it is as below,#include LiquidCrystal lcd(12, 11, 6, 5, 4, 3); #define VIN A0 // define the Arduino pin A0 as voltage input (V in) const float VCC = 5.0;// supply voltage is from 4.5 to 5.5V. Normally 5V. const int model = 2; // enter the model number (see below) float cutOffLimit = 1.01;// set the current which below that value, doesn't matter. Or set 0.5 float sensitivity[] ={ 0.185,// for ACS712ELCTR-05B-T 0.100,// for ACS712ELCTR-20A-T 0.066// for ACS712ELCTR-30A-T }; const float QOV = 0.5 * VCC;// set quiescent Output voltage of 0.5V float voltage;// internal variable for voltage // start of settings for LCD1602 with I2C #include // Set the LCD address to 0x27 for a 16 chars and 2 line display // end of settings for LCD1602 with I2C int relayPin = 1; void setup() { //Robojax.com ACS758 Current Sensor lcd.begin(16,2); pinMode(A0, INPUT); pinMode(relayPin, OUTPUT); // Turn on the blacklight and print a message. lcd.setCursor (0,0); // go to start of 2nd line lcd.print("Current Sensor"); delay(200); } void loop() { float voltage_raw = (5.0 / 1023.0)* analogRead(VIN);// Read the voltage from sensor voltage = voltage_raw - QOV + 0.012 ;// 0.000 is a value to make voltage zero when there is no current float current = voltage / sensitivity[model]; if(current >= 15.69 ){ lcd.setCursor (0,1); lcd.print("I: "); lcd.print(current,2); // print the current with 2 decimal places lcd.println("A"); delay(500); digitalWrite(relayPin, LOW); delay(500); } else { lcd.setCursor (0,1); // set to line 1, char 0 lcd.print("Normal Current"); delay(500); digitalWrite(relayPin, HIGH); delay(500); } delay(500); }
@mohamedarthil6249
3 жыл бұрын
i want to trigger relay when access card is read by PN532 and turn off relay when same card is scanned again. can anyone help with coding ?
@robojax
3 жыл бұрын
awal Salam. you can learn Arduino from this 30 minuets video kzitem.info/news/bejne/rpiYmKyXaomUhYI once you know how to read switch or voltage, you can take action and do anything.
@sriram8609
2 жыл бұрын
relay is low trigger or high trigger
@robojax
2 жыл бұрын
I made the video to answer these types of questions
@sriram8609
2 жыл бұрын
@@robojax can you please tell me which is used in this video
@trr8526
4 жыл бұрын
can i use this relay for RPI
@robojax
4 жыл бұрын
Hi, yes you can.
@trr8526
4 жыл бұрын
Tnq
@abdullahsiddiqawan9100
5 жыл бұрын
Plz include lcd and kaypad
@robojax
5 жыл бұрын
include it where?
@mmuller3233
5 жыл бұрын
Great information and well explained illustration & commentary, satisfied me too!.
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