Mam what is the application of current mirror circuit
@gautamsonpitale9999
Жыл бұрын
really appreciate you mam , my all doubts about current mirror circuit is clear now , only because of you mam ✌️
@LEARNANDGROW
Жыл бұрын
Glad to hear that
@SAYANMANNABEC
7 жыл бұрын
mam, you assumed ic1=ic2 and derived the equation, why this assumption.
@LEARNANDGROW
7 жыл бұрын
Because it is current metros Q1 =Q2 and as in mirror qualities same so ic1 = ic2 THANK YOU With regards LEARN AND GROW
@snnwstt
6 жыл бұрын
Well, I can't follow the supplied explanation (is that English?), but here is one: VB1 = VB2 ( linked by a cable without resistance, and no capacitance ) VB1= VB2 = VBE, so IB1 = IB2. Next we know that Q1 is similar to Q2, their beta value is similar. Given that IE= beta * IB, for the same Ib and the same beta, that gives the same Ic. For large beta, IRef = IC1 + IB1 + IB2 = IC1 + 2 IB = IC1 + 2 IC1/beta =.= IC1 ( since beta is large) = beta* IB1 (transistor Is in active region) = beta * IB2 = IC2 So IC1 = IC2 (because IB1 = IB2 and same beta). A more rigorous proof can be made using the exponential behavior for the "diode" B-E of each transistor., but it involves more math.
@pallavisingh2265
3 жыл бұрын
I really like ur all lecture 🎉🎉❤️❤️
@LEARNANDGROW
3 жыл бұрын
Thanks for your words
@engahmedomar5807
6 жыл бұрын
thank you .. can u give us pdf with some problem and their solution
@mahendrasinghkaswan9169
7 жыл бұрын
nice mam, u did very straight forward
@LEARNANDGROW
7 жыл бұрын
THANK YOU SO MUCH WITH REGARDS LEARN AND GROW
@vivekkumarsingh7402
7 жыл бұрын
mam in this bita value is high and if its high we can neglect base current .. ??
@LEARNANDGROW
7 жыл бұрын
No we can't neglect base current because base emitter junction of Q1 established it apply base emitter junction to Q2 and Q2 on and generate the output current. Thank you With regards Learn and grow
@shrutimukherjee8378
Жыл бұрын
Thnks
@LEARNANDGROW
Жыл бұрын
Glad to help you
@dipamsaha8275
5 жыл бұрын
Ma'am thank you
@brianvalenzuela3918
6 жыл бұрын
add subtitle and ill subscribe...
@balledachandrahas8326
7 жыл бұрын
Excellent
@LEARNANDGROW
7 жыл бұрын
Thanks for your precious words With regards LEARN AND GROW TEAM
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