This has been the most crystal-clear material I found on the subject after countless site documents just lost me. Thanks, Jim Pytel and CGCC!
@TheOptimusAngel
10 жыл бұрын
Thank you for this presentation. I had an assignment to explain how the R2R or the so called ladder DAC works. It helped me realize that there is no bigger diference between the binary weighed DAC and this one. Thank you once again :)
@ayaeltokhy2022
7 жыл бұрын
Best expiation ever of r2r thank you very much
@HitAndMissLab
9 жыл бұрын
Can anybody suggest currently available DAC IC, in DIP format, that would work with R2R Ladder. I looked on Farnell and all the DACs they have are SPI input and single pin analogue output. Maybe this method is out of date.
@LauriPirttiaho
8 жыл бұрын
Analog Devices DAC10 is an example of currently available parallel input linear R-2R network DAC with all relevant points of the circuit accessible. There used to be many more, like the DAC0800 and DAC1000 classic series from National Semiconductor (now part of TI) and Motorola (Now ON Semiconductor). You may find those in surplus component stores. Usually the SPI and I2C input DACs also contain an R-2R network, as do SAR ADCs as a part of the digitizing circuit, so it is definitely not obsolete. You can also get R-2R resistor networks. At least Bourns still has those in catalog and both Mouser and Digi-Key seem to have those in stock.
@user-se3lo2ql1f
8 жыл бұрын
Thank you, that was helpful :)
@arunibasu5738
10 жыл бұрын
op amp positive grounded...is it ok...
@erochieng
9 жыл бұрын
yes. It's a summing amplifier
@suhadhadad5842
8 жыл бұрын
Many thanks for you
@ndrsg3013
7 жыл бұрын
If it is so simple why are the explanations too complicated... pls, plug some values on the resistors and show some calculations.... I will learn this 2R ladder and show it myself...
@ArgonCandelabra
7 жыл бұрын
Ack, don't you get it! Thevenizing the circuit makes the values superfluous. He does it like crossing out the all the algebraic numerators and denominators that recur, except that he simplifies by using standard regard for current being divided through the parallel branches of a circuit but not through series branches. So, with 2R in a parallel branch, you really got a Thevenin equivalent of 1R. So if each of two resistors in a parallel segment reference were 200 Ohms, it would be equivalent to 100 Ohms as if it were in-series. Thevenin equivalence usually goes like summing all parallel resistive branches with one single equation. But since we have four bits, he breaks it down one bit at a time just to show reducing occurring in identical portions.
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