1:06:03. But Correct options are (a) and (d) Only.
@mcbc01
8 ай бұрын
This is series will be very help full for upcoming csir net
@kritikagrover4980
8 ай бұрын
Thank you so much sir for all your efforts🙏🏻🙏🏻
@hajeeranasreenqueenofscience
6 ай бұрын
A²=A idempotant sir and A²=I is involuntary.
@suniltiwari9215
4 ай бұрын
True
@mystory5438
4 ай бұрын
Thank you so much for your lecture sir, . It is very useful for us.
@masterkapil6214
8 ай бұрын
Thnku sir aap hmare liye bhut acha content tyar krte ho
@nidhiyadav1577
8 ай бұрын
Good evening sir, Thank you so much sir for making helpful lectures. THANK YOU SIR.
@906mukesh8
8 ай бұрын
Thank you so much
@yogeshjadhavpatil4120
7 ай бұрын
Aafke video se bahut help milati hai
@shrawankumarpatel2148
8 ай бұрын
Thank you so much sir
@sureshm92
8 ай бұрын
Thank you sir...
@ummehabeeba9026
8 ай бұрын
Thank you sir
@anitakaushik-be8mo
7 ай бұрын
In que june 2017 ..option b is not correct sir ..for idempotent matrix it is not necessary to be an diagonal matrix ..it can be all entries with (1/n) type ..so how it is correct by your side
@shrutik5302
3 ай бұрын
Thanks sir 🌼
@jittaboinaramu1537
8 ай бұрын
Sir , in some problems at A²=I is involuntary matrix but you told that it is idempotent matrix ..
@amitgupta-sk4hw
8 ай бұрын
Correct buddy
@hajeeranasreenqueenofscience
6 ай бұрын
In hurry sir has said like that...
@super40educationalinstitut29
6 ай бұрын
Very good sir.. mja aa gaya
@Manish-uq5le
5 ай бұрын
Thanks you sir ❤
@mak511
6 ай бұрын
Sir in this video many mistakes in the solution... overall most helpful thanks for this .
@ronneysaini7763
8 ай бұрын
Thanks Sir ji❤
@shwetarathi304
8 ай бұрын
Thankyou sir
@pranavninghot3777
3 ай бұрын
A^2 = A is idempotent matrix A^2 = I is involuntary matrix
@DrHarishGarg
3 ай бұрын
Thanks
@sat4maths
3 ай бұрын
Hi sir, All your short trick are very nice and useful to solve the problems quickly. But few problems ,there some mistakes that rank of Matrix is we count no.if non zero rows right..... In some problems you took no of zero rows.....
@roshaningale5907
24 күн бұрын
10:57 dec 2014 questions AM(1)= 2,GM=1
@Achukutty25
23 күн бұрын
Yes, rank is 1, so GM is 2
@HeWhoKnows-
8 ай бұрын
Sir can you please do a short video on Rate of convergence of Müller's method. I've searched in my library and non of the books has detailed proofs and just a statement that it convergence to 1.84
@hajeeranasreenqueenofscience
6 ай бұрын
Sir 1:10 dec18 ...A=I ev's (1,1,1) not distinct so not diagonalizable Right
@indhui1911
8 ай бұрын
A^2 =A matrix is Idempotent **
@maharaja8085
8 ай бұрын
Both
@ummehabeeba9026
8 ай бұрын
Sir can you solve modern algebra pyq?
@physicsmagic786
2 ай бұрын
11 : 25 e. Values are 1,1,2 which are not distinct so how it can be diagonalisable.
@amitgupta-sk4hw
8 ай бұрын
❤
@SADDAMHUSSAIN-mw3cv
6 ай бұрын
59:33 sir here you taken an example of a matrix of zero eigen values.
@mathematical2508
8 ай бұрын
Sir aapne diagonalizable ka jo first point likhvaya h vo iff nahi h Diagonalizable ke liye jaruri nahi h ki eigen value distinct aayengi Distinct imply krta h diagonalizable honga
@anupamsamanta6690
8 ай бұрын
Sir Identify matrix always diagonalizable
@mirshabir3672
6 ай бұрын
Net Dec. 2018 A is a real matrix and Characteristic polynomial (X-1)^3......Sir, can you explain the question again ............
@hajeeranasreenqueenofscience
6 ай бұрын
A=I ,evs( 1,1,1) not distinct so not diagonalizable.
@GameFeverHQ
6 ай бұрын
There are so many mistakes sir,like you said identity matrix is not diagonalisable . overall helpful
@archanakumarimeena3058
Ай бұрын
24:42 par A2=0 to A^3=0 hi.hoga zero matrix se A ka.multipliy karenge to zero honhoga A^3=A^2.A
@saikatmalla7390
21 күн бұрын
sir please upload ring theory previous year question lecture
@ishitaagrawal987
6 ай бұрын
sir identity matrix is always diagonalizable then how are you discarding options saying it is not.
@bantumath3527
6 ай бұрын
Im also thinking that I is not diagonalizable,but it is not true But how sir prove AM(a=1) is not same as GM(a=1)
@ishitaagrawal987
6 ай бұрын
Am is always equal to Gm for identity matrix
@bantumath3527
6 ай бұрын
@@ishitaagrawal987 no Am(1)=3 and gm(1)= nullity(A-0.I) Which is 3 but sir take rank of A ,that why it is not equal Now i know it is equal
@rintumondal5658
Ай бұрын
1:02:07
@mathmadeeasy2601
18 күн бұрын
54:00 can't be use matrix [1/2 1/2 1/2 1/2]
@shubhambarman7288
6 күн бұрын
Why ?? Although it satisfy A^2= A
@SADDAMHUSSAIN-mw3cv
6 ай бұрын
54:48 only options (a) ,(c), and (d). are correct.
@waseemayoub6227
6 ай бұрын
We can take nilpotent matrix to discard option (a). Why is b not true...if eigen values are distinct then it is necessarily diagonalisable. Correct me if I am wrong sir.
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