For more information, check this playlist of Digital Electronics: kzitem.info/door/PLwjK_iyK4LLBC_so3odA64E2MLgIRKafl
@jigneshkhatri4623
Жыл бұрын
This playlist is underated af
@karanpalsingh6065
2 ай бұрын
This single video covered all my doubts about sop , pos and k map which I was searching every where bit by bit from whole day, Thanks alot
@p.krajput0601
2 жыл бұрын
My exam is on 20th Jan 2022and you have posted the video on exact time. 😎 Tx you sir.....op ❤️❤️
@ashif2303
2 жыл бұрын
Channel have good quality of animation and teaching method is very good.....I love it
@swethakamadri
5 ай бұрын
Actually I have no words to say This video helped me a lot🥲 I cleared my DLD examination with good Mark's...thank U so much❤....
@Yash-bq8ui
9 ай бұрын
Best channel tomorrow are my exams ❤ concepts cleared very well
@mayurshah9131
2 жыл бұрын
HEARTLY CONGRATULATIONS FOR 4 LAKHS SUBSCRIPTION BLESSINGS ❤️❤️
@SN-ow1bp
Жыл бұрын
Great video, you're a good educator.
@dannyhighlights9729
4 ай бұрын
Thank you sir watched all the videos given to me as per the handout,and understand all the concepts really well.
@wealth_wisdom_simplified
Жыл бұрын
Thank you man this work is so good!!!!
@sucheesanketbehera1712
Жыл бұрын
Simplify the following Boolean function F using K-map. F = A' * B' * C' + B' * C * D' + A' * BC * D' + A * B' * C' , d = A' * B * C' * D + ACD + A * B' * D' where "d" indicates do not care conditions.
@sucheesanketbehera1712
Жыл бұрын
Please sir
@yarenkaya7872
2 жыл бұрын
Thank you for the tutorial but what about the real-life examples that can make us get the concept of don't care and when they are actually used while creating the truth table on our own without a set condition?
@iitmeans-life6657
2 жыл бұрын
Sir Sir I am a beginner now. And may want to become electronic engineer. Where do I start and what is my path? What is my path for electronic engineer. I were saw your playlist but I am very confused where to start. Technology playlist?
@JayaPrakash-zk5ep
2 жыл бұрын
Thank you sir ☺️
@sutopasarkar497
Жыл бұрын
In 11:31 wasn’t it will be BCD'?
@AashiqueHussain_
2 жыл бұрын
thank you! was helpful
@Lack_Of_Enemies
7 ай бұрын
Thanks a lot
@caghey
4 ай бұрын
you're the best fr
@namratabatli8015
Жыл бұрын
thanks a lot it was really helpful.
@chethanms4469
6 ай бұрын
Nice sir 👍
@audreykoffi8867
Жыл бұрын
1:01 We only use don’t care when the fonction is unspecified for certain values?
@jahidarman2436
Жыл бұрын
thank you
@love_is-overloded
Жыл бұрын
Thanks really helpful
@sutopasarkar497
Жыл бұрын
In 9:22 s why we don't use M4?
@shohansikder6105
2 ай бұрын
Thanks a lot❤❤❤❤❤❤❤❤❤❤❤
@allspirituality8471
Жыл бұрын
Good video
@TheLoker3
2 жыл бұрын
thank you sir
@kalpakpatil9775
9 ай бұрын
Sir at 7:43 there should be one more group of 0x00 in first row of k-map?
@ALLABOUTELECTRONICS
9 ай бұрын
Just by making the two groups, we are able to cover all the 0s in the K-map for POS minimization. So, there is no need to make any other group. That additional group will be redundant one.
@sakibsnature2479
Жыл бұрын
awasome thanks
@ParminderSingh-uv6ij
Жыл бұрын
Best ....
@singh86834
10 ай бұрын
9:41 In POS form we represent 0 by A and 1 by A' but you have represented in SOP form
@ALLABOUTELECTRONICS
10 ай бұрын
In the SOP form, I have represented F3'. If you invert it then you will get F3 in POS form. (10:01)
@yaswanthsai5976
6 ай бұрын
at 5:52 why you not grouped (5,7,13,15)?
@lovekushmalik6929
Жыл бұрын
Best video for k map i found or sab ki bakwas ha 🎉
@NishaChauhan-wi2pq
10 ай бұрын
11.30 , while making the groups , we should use 2^n cells right? But u are used 10 cells in this question
@ALLABOUTELECTRONICS
10 ай бұрын
If you closely observe then here three groups have been made. In each group, the total no of covered cells are in the power of 2. In one group we have 4 cells, in second group 2 cells and in the third group again 4 cells. So, all are in the power of 2. You do need to add them all. Just need to ensure that, in each group, the total no of cells are in the power of 2. I hope, it will clear your doubt.
@nityamsharma9485
8 ай бұрын
5:50, why you have not considered B in the 4 cell group while it's not changing? Please help me😢
@ALLABOUTELECTRONICS
8 ай бұрын
At 5:50, there are two groups. In one group variable A and B are changing. That group is C'D. While in the second group variable B and C is not changing. That group corresponds to BC. If you are talking about the second group, then B is already considered in that.
@shahidmehmood653
Жыл бұрын
Thanks. Can you pleasse the example of 5 veriables with don't care method
@ALLABOUTELECTRONICS
Жыл бұрын
will try to cover one such example.
@Unknown-ik3zk
Жыл бұрын
At 4.40 when we make group of 4 then why we considered only b complement not any term of a
@ALLABOUTELECTRONICS
Жыл бұрын
There are two group of 4. And I guess you are asking about B' ( The one in orange color). Well, in that case, if you see that group, then as you move from one minterm to another minterm vertically, ( 0 to 4 or 1 to 5) then variable A is changing from 0 to 1. similarly if you move from one minterm to another minter horizontally ( 0 to 1 or 4 to 5) then value of variable is changing from 0 to 1. Only non-changing variable is B. And in the group, the value of variable B is 0. Therefore, that group represents B' . Similarly, if you see the second group of 4 in the yellow color, then it represents A'. Because, in that group, as you move horizontally, then variable B and C both are changing. Only non-changing variable is A. And its value is 0. Therefore, it represents A'. I hope, it will clear your doubt.
@malimayaz6377
Жыл бұрын
At 8:03 m2 and m3 shouldn't be A'B'C? Can u explain how why it's B'C?
@ALLABOUTELECTRONICS
Жыл бұрын
It is the combination of 4 terms. The pink group consists of M2, M3, M10 and M11. That is why it’s B’C. I hope it will clear your doubt.
@AmanSingh-xv1nx
2 күн бұрын
At 9:46 i think there should be A'B'D' instead of only B'D'.
@ALLABOUTELECTRONICS
2 күн бұрын
If you closely observe then it is group of four 1s ( the group in pink colour). The others two 1s are at the bottom corners. So, this group of four 1s represents B’D’. I hope, it will clear your doubt.
@AmanSingh-xv1nx
2 күн бұрын
Okay i got u ... Thanks for clearing the doubt.
@KoreaRwkz
10 ай бұрын
10:12 Shouldn't the small group be Abar*Bbar*Dbar, instead of just Bbar*Dbar?
@ALLABOUTELECTRONICS
10 ай бұрын
The small group which you are referring to is made of four minterms. Minterms m0, m2, m8 and m10 (The four corners of the K-map). And that corresponds to B'D'. I hope, it will clear your doubt.
@beefobserver1577
10 ай бұрын
9:55 here why are 0 and 4 not paired? Also,many k map simplifications include not pairing some visible pairs.why that?and how would we understand when not to pair them?
@ALLABOUTELECTRONICS
10 ай бұрын
4 is a don't care term. During the minimization, you need to ensure that all the 1s gets covered (during SOP minimization) and all 0s gets covered (during POS minimization). It doesn't matter, If all the don't care terms are not covered. By including some or all the don't care terms, if you are able to minimize the function further, then you should include them. But its not compulsory to include all of them.
@shohansikder6105
2 ай бұрын
What would happen for single term?
@ALLABOUTELECTRONICS
2 ай бұрын
Would you please elaborate, what you mean to say ??
@GaneshLalReddyM23BCE102
7 ай бұрын
sir in this dont care we should consider all x?
@ALLABOUTELECTRONICS
7 ай бұрын
No, not necessarily all x. You just only need to consider those x, which can be used to minimise the Boolean expression further.
@divinestartutorials
2 жыл бұрын
👍👍👍
@venkatesht9444
2 ай бұрын
sir how to draw circuit diagram for this output
@ALLABOUTELECTRONICS
2 ай бұрын
Would you please mention the timestamp in a video, where you are referring. In general, once you have a minimized Boolean expression then as per the expression it is easy to draw a circuit diagram. If you will mention the timestamp, I can tell you, how to draw a circuit diagram for that specific expression.
@sanjayshah9838
2 жыл бұрын
👌👌👌👌👌👍👍👍👍
@sudipbiswas4718
3 ай бұрын
Sir why Bbar C ?7:40 Not A barB barC?
@ALLABOUTELECTRONICS
3 ай бұрын
Here we are making a group of four 1s (not two 1s). The minterms m11 and m10 are also part of that group. Considering the group of four 1s, it is B'.C. I hope it will clear your doubt.
@sainath509
14 күн бұрын
🎉❤🎉🎉❤🎉❤🎉🎉❤
@sweety._.s
Жыл бұрын
If f(A,B,C) =π(5,10, 11,12) Then what is F’ ???
@sweety._.s
Жыл бұрын
Please reply I'm so confused😵😵
@ALLABOUTELECTRONICS
Жыл бұрын
It will be equal to Σ ( 5, 10, 11, 12)
@ALLABOUTELECTRONICS
Жыл бұрын
For more info please check the last part of SOP and POS form video. Here is the link : kzitem.info/news/bejne/uqOB04dvm6J-pII
@kausalshukla4948
9 ай бұрын
Sir Questions POS ke and answer SOP ke Ye bhed bhav kyun😂
@-.-_._--
Жыл бұрын
At 9:12 why x at 4 is not grouped in the kmap
@ALLABOUTELECTRONICS
Жыл бұрын
It is a don't care term. It is not necessary to cover all the don't care terms in the K-map. But you need to cover all the minterms in the K-map for which the output function is 1. You can use some or all the don't care terms to minimize the boolean expression. But to include all of them during the minimization is not compulsory. I hope, it will clear your doubt.
@musthafakamalpasha.a8180
6 ай бұрын
I think ..there is some mistake in POS form SIMPLIFICATION USING K MAP
@ALLABOUTELECTRONICS
6 ай бұрын
Nope, that’s alright. In case, if you have any doubt, let me know here. Happy to help you.
@musthafakamalpasha.a8180
6 ай бұрын
@@ALLABOUTELECTRONICSIn example 3 ..the Answer given is AB‘+B‘D‘+CD How this expression is in POS form..? It is in SOP form..ri8.?
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