EaSy IIT Advanced Question 2009 paper 1 | Permutations and Combinations Class 11 | JEE Advanced PYQ
About this Video -
In this video we have discussed an EASY LEVEL CONCEPT Question of IIT JEE Advanced 2009 Permutation and Combination Chapter. Asked in IIT Advanced 2009 Paper-1 having +3 marks and -1 negative marking. It is a fundamental concept based question based on Arrangement of Alike Objects, where we have covered theoretical part of the concept as well. After seeing the video you will able to solve limits questions of jee advanced and such problems very easily......
Question:
The number of seven digit integers, with sum of the digits equal to 10 and formed by using the digits 1, 2 and 3 only, is
(A) 55 (B) 66 (C) 77 (D) 88
Answer:
C [IIT Adv. 2009 Paper-1, Marks (+3, -1)]
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These videos are the very informative for all competitive examinations such as IIT JEE Advance, IIT JEE Mains, KVPY, Mathematics Olympiads and many more. You will be able to solve problems of IIT Advance and Mains by using the concept covered in the video.
Hi,
I am your Maths Guru. Welcome to my channel Aryabhata IIT Maths.
About this Channel -
Friends this channel is managed by very experienced IIT faculty and IITian. Friends here you will learn fundamental concepts and problem solving skills. Our moto is to provide coaching to all the students of class 11, class 12, IIT Aspirants, Olympiad, NDA and various other competitive examinations free of cost. Our aim is to provide basic and Advance level concepts to all those students who are willing to learn and not able to pay fee of reputed coaching institutes. Please watch the videos till the end to learn basic and Advance concepts. For doubt related to any topic in Mathematics, please write in the comment box.
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