I love the way you are so enthusiastic about teaching!! thank you so much for the video :)
@isabellacrow8369
3 ай бұрын
This is it. Two hours of working on the same delta-epsilon problem, and this is the video that made it click for me. Thank you.
@VasilEPetkov
7 ай бұрын
My professor prooved the same thing to us. He skiped all the (un)necessary comments what's coming from where so I was so lost looking back at my notes. Your videos are for sure saving me :D
@tomtomspa
4 ай бұрын
The explanation is all wrong.
@CANALIMG
3 ай бұрын
Sir, could you recommend a better video? @@tomtomspa
@mohammedaminelm7836
10 күн бұрын
You are the best math teacher that exists!
@itsmemario1298
6 ай бұрын
9:18 I did the same expression and the meme appeared! Truly magnificient! YOU GOT ME! LOVE FROM INDIA
@mrhunterai...331
8 ай бұрын
You're really making our life much simpler and thanks a lot. You simplified the proofs very well.
@piousmazonde5979
Жыл бұрын
Mathematics becomes easier for me because of how you explained it in such simple ways....Thank you very much
@yohannesyebabe7923
9 ай бұрын
It was wrongly explained!
@tomtomspa
4 ай бұрын
@@yohannesyebabe7923 I cannot believe how someone so poorly knowledgeable on limits get to wrongly explain them on yb
@user-hp7of4wj1j
11 ай бұрын
You are One of the Great Teachers i have ever seen Thank a lot!!!!
@hriday8690
Ай бұрын
This is the best I have ever heard this concept explained. I was struggling with understanding how the proof worked for the past 2 days, and I finally understand now. Thank you!
@crunch_and_crunch
Ай бұрын
SO AM I FROM University of Namibia 👌👌👌👌👌👌
@user-mn4vc6nq5g
7 ай бұрын
Plus the way u smile doing some cracks, while solving, its just fantastic, u wont be left with any qsn
@MathTutor1
8 ай бұрын
First I need to tell you that you have great videos with excellent explanations. These definitely make math learning interesting, enjoyable and easy to understand. The point of this comment is to let you know about a very important notation matter. When we right limit at the beginning without a parenthesis, the limit only belongs to the first term. So, the correct way to write it is to use a parenthesis around all three terms as lim{ x → 1} (x²+5x+6) = 12. Keep doing what you are doing. Thank you.
@tomtomspa
4 ай бұрын
Unfortunately that's the least serious error of the video.
@znhait
Жыл бұрын
best video on the subject so far.
@kamrulhassan7157
4 ай бұрын
A very very brilliant lecture from a genius . Thank you sir for your contribution.
@emmanuelnhunde
3 ай бұрын
I actually appreciate you for the good work ,,,God bless you
@mkmathstutorials6645
Жыл бұрын
Like how you explain it my brother.much appreciated.
@user-yg6ih5rc9c
9 ай бұрын
Even i can miss up a class,, its okay with this handful of skills, i really appreciate you.
@user-mn4vc6nq5g
7 ай бұрын
Wooow Man u the best, i actually had a crisis in understanding this, but i just grasped it easily, The best of the Bestest
@solha5751
11 ай бұрын
Bro you are amazing , i mean you have the talent to be a teacher bc you try to understand the students❤❤
@PrimeNewtons
11 ай бұрын
Thank you
@user-kb8jp7oj7c
Ай бұрын
thank you very much i was really confused on this delta and epsilon proofs you just made my day,thank you sir
@user-wq4dx6ql9o
6 ай бұрын
Your enthusiam for maths makes me like it
@NeuCoupAlloi
10 ай бұрын
You my friend are an excellent tutor. Great job on Precise Definition of a Limit !!! Keep up the good work....sorry... Great Work.
@samaunislam7071
9 ай бұрын
It's Amazing. I watched many videos but after watching this video I understood the math well.
@arbenkellici3808
6 ай бұрын
You are really doing an excellent explanation and thus make our life easier in understanding maths even though it is not my proffesion. Awesome! Thank you!
@lusianelundu2702
Жыл бұрын
Your handwriting is dope sir and I love the way you have explained.
@PrimeNewtons
Жыл бұрын
Thank you!
@ayalktube5991
10 ай бұрын
your videos are very interesting keep going on !
@easylearing87
Жыл бұрын
Bro keep uploading...Love from Bangladesh 🇧🇩
@user-up4mk6jf7l
11 ай бұрын
Damn , that's some quality teaching .
@piousmazonde5979
Жыл бұрын
You are a Geneous sir...Excellent in making mathematics simple ..very good in explaining
@PrimeNewtons
Жыл бұрын
I want to be a genius. It's just hard 😪 🤣
@digbycrankshaft7572
10 ай бұрын
Because lx+6l
@yohannesyebabe7923
9 ай бұрын
He should replaced by 6. and He should choose delta a min {1, e/6}
@leratomoetinyane
10 ай бұрын
I finally understand this brother thanks a lot
@zeusui4934
10 ай бұрын
Thank you so much for the very clarification🎉❤
@levailiona3399
9 ай бұрын
THANK YOU SO SO SO MUCH YOU HELP ME A LOT A REALLY LOVE YOUR EXPLANATION
@josephmartos
2 ай бұрын
J has to pass my Calculus I course knowing that i will fail in every question of this type. Great explanation!!! Thank you
@tawandadhlakama3187
8 ай бұрын
You're so talented
@biswambarpanda4468
4 ай бұрын
Wonderful sir. You are wonderful..
@fikaduwalie6066
Жыл бұрын
really exciting
@curious_cat505
9 ай бұрын
God bless your soul. Thank you
@PrimeNewtons
9 ай бұрын
Amen
@tahreemrana1125
10 ай бұрын
So helpful sir amazing ❤
@mikeynavarro3195
10 ай бұрын
By far best explained thankyou
@PrimeNewtons
10 ай бұрын
Glad it helped
@bangprob
5 ай бұрын
Great teacher! Thanks...
@punditgi
Жыл бұрын
He does it again! Bam! QED! 😃
@yuxinhe5987
5 ай бұрын
Man u save my life
@krishnashroff657
4 ай бұрын
Best love from India❤
@ramyramy9620
Жыл бұрын
Thanks so much 🙏
@nebaofficial3343
Ай бұрын
Ohh you are so so good❤
@KHAYMYA
4 ай бұрын
AWESOME SIR YOU ARE JUST A GREAT MAN THNX A LOT SIR
@user-qj9sx9jx1b
Жыл бұрын
well taught sir
@cristopherurrutia8591
Жыл бұрын
Thanks man, I finally got it
@PrimeNewtons
Жыл бұрын
Glad it helped
@CatherineYang-hy4ti
2 ай бұрын
Thanks help me a lot
@davy6255
10 ай бұрын
thank you so much!
@yohannesyebabe7923
9 ай бұрын
The proof has fundamental error! The correct proof is as follows Let f(x)=x^2+5x+6 We want to show lim x->1 {(f(x))}=12 For all e>0 whenever |f(x)-12|
@Kittu-uc1yd
Ай бұрын
Thanks a lot buddy! ✌🏻💚 This comment deserves a lot more likes.
@brendawilliams8062
24 күн бұрын
Why would you need this type of math
@yohannesyebabe7923
23 күн бұрын
@@brendawilliams8062 It is the rigorous mathematical analysis called the epsolon delta techniques.
@brendawilliams8062
23 күн бұрын
@@yohannesyebabe7923 thx. , but what can you do with it
@yohannesyebabe7923
23 күн бұрын
@@brendawilliams8062 To prove mathematical theorem.
@trhasamare8865
10 ай бұрын
wow u r great man
@Arkapravo
Ай бұрын
Love that t-shirt!
@bhagirathikashyap6021
9 ай бұрын
Nice explanation
@Udics
3 ай бұрын
Bravissimo. Con te e con Robert Ghrist la matematica è un incanto. Grazie 😊😊
@user-dr9ru2gz6i
5 күн бұрын
what a nice video to watch
@alpmuslu3954
4 ай бұрын
You are great
@hqs9585
6 ай бұрын
Great video! Thanks. It would be nice to add some graphics to bring this concept to clarity.
@kingsterfolokwe651
4 ай бұрын
great job Bosses
@jayrum7303
Жыл бұрын
Great!
@adityabhagoria1374
4 күн бұрын
Thankyou in advance
@user-vu1td8og9t
7 ай бұрын
I love it 🎉
@FenetAbilu
11 ай бұрын
It is good. I am lucky if you add another example.
@OpPhilo03
4 ай бұрын
Love❤ from India
@masoudhabibi700
Жыл бұрын
Thanks for video.... epsilon and delta greater than zero is true
@adityabhagoria1374
4 күн бұрын
If not possible thank for your videos
@josephpagapong2498
10 ай бұрын
thank you so much sir, it really helps me a lot. And now, maybe I can answer our exam tomorrow hhahhaha
@PrimeNewtons
10 ай бұрын
Good luck
@Andalfulfulde
6 ай бұрын
Respect from Cameroon +237, 3:19 🎉🎉🎉
@user-vs2vy4rq6s
18 күн бұрын
U're genius
@arkoghosh6218
7 ай бұрын
Hello Sir, there is a mistake in this proof. You cannot replace |x+6| with 8 and be sure that 8|x-1|< E. We can take 6 instead of 8 but in that case in the last step you wont be able to replace |x+6| with 6, hence we get stuck. Could you please check for this.
@okohsamuel314
5 ай бұрын
That's exactly what I also figured out...👍
@abdu_rehman3806
10 ай бұрын
you"re bestttttttttttttttttttttttttttttttt
@nigarabdullayeva7902
8 ай бұрын
why x-6 cannot be replaced with 7? it is smaller than 8 how we replaced that?
@rituparna7059
7 ай бұрын
Nice❤
@alpmuslu3954
4 ай бұрын
Can someone please explain when 9:04 he writes x+6 as 8 in the inequality. Because he showed that x+6 is less than 8, but when he inserts 8 in the epsilon inequality, he technically increased the left hand side of the inequality without increasing the right hand side (epsilon). Which makes me a little suspect on whether the inequality will hold true. I am no professor and I respect everything he does, but I get delta=epsilon/6. Please feel free to enlighten me. Cheers from Denmark
@okwaraisaac3510
11 ай бұрын
What if you are asked to proof lim X--2 2x² +3 =11 . How can I go about it?
@jihansarhan9392
5 ай бұрын
That is easy and clear , do you do one to one tour ?
@PrimeNewtons
5 ай бұрын
Yes. Please send me an email
@20tejas
Жыл бұрын
in the second part can we not substitute delta = epsilon/8 into |(x-1)|< delta for the proof to be satisfied.
@PrimeNewtons
Жыл бұрын
It depends on what your teacher wants. Some just want you to show there is a delta. But some want you to show that that value you found truly works. So ask the professor what they want.
@20tejas
Жыл бұрын
@@PrimeNewtons thanks professor.
@Mathematics-with-MohsinRaja
9 ай бұрын
Sir which camera are you using
@TheGoatsy
4 ай бұрын
Countless hours of calculus and epsilon delta videos and I still have no clue what is going on
@DarteySelasi-kq6qx
3 күн бұрын
Do you have calculus 1 playlist?
@StuartSimon
10 ай бұрын
In your linear example, you had the process right, but you stated it as “for every delta, there exists epsilon.” It is an easy mistake to make. I actually had to read an epsilon-delta proof in my textbook to understand why it had to be “for every epsilon, there exists delta.” We first find the delta and then prove that it implies the given epsilon.
@PrimeNewtons
10 ай бұрын
Oops, that was an error.
@mathiscool2310
10 ай бұрын
this is the serious issue what am i going to tell you.... if 6 < x+6 < 8 and at the same time |x+6|.|x-1| 6 and now replace x+6 with 6 then it will be not contradict because the product of |x+6|.|x-1|
@mathiscool2310
10 ай бұрын
i dont know you are looking for this or not..... i hv figured out the mistake.. you should not start with lx^2 +5x-6l
@digbycrankshaft7572
10 ай бұрын
Yes you are right. I spotted that straight away.
@ayotundeajamu2720
10 ай бұрын
When you want to show that the left hand side is less than the right hand side, you should always increase the left hand side. So 8 and not 6 was the correct choice.
@mrsimphiwebazzano877
4 ай бұрын
Can you please try this problem Use Epsolon delta Def to show that Lim x-->-1.(2x+3)/(x+2)=1
@user-lg6fq1yt4g
10 ай бұрын
👏👏👏
@user-qj3rv2mo1b
7 ай бұрын
8:58 We substituted 8 because we |x-1
@MusaJamel
Ай бұрын
❤❤❤❤
@pramjitboro5995
8 ай бұрын
Nice dress sir
@gp-ht7ug
3 ай бұрын
Every time I see these videos on delta-epsilon I come to the conclusion that the proof is always a tautology 🤷🏻
@nunes889
3 ай бұрын
I speak portuguese but undertand very well
@nicolascamargo8339
7 ай бұрын
Wow
@chathurangalakmal3066
9 ай бұрын
✌
@solomonKachi7000
10 ай бұрын
my mind asks me "why" I get what your doing but I do not get why this makes sense or how I can remember this because I do not understand its logic
@PrimeNewtons
10 ай бұрын
Your mind is active
@solomonKachi7000
10 ай бұрын
@@PrimeNewtons Yes :(
@renesperb
6 ай бұрын
Here I can't see the value of proving this as a limit , since one can just plug in the value 1 into this continuous function.
@12.lethanhhoai65
Ай бұрын
i think u should choose delta=min{ ep/8, 1 }, this is my idea
@propoop6991
Жыл бұрын
8:40 no i dont get that. Why does that work? Why does replacing |x+6| by 8 as a result of that inequality work?
@PrimeNewtons
Жыл бұрын
It doesn't have to be 8. You could use another constant. Just keep track.
@propoop6991
Жыл бұрын
@@PrimeNewtons I get that part. I'm just wondering how replacing it by 8 keeps the inequality the same!
@propoop6991
Жыл бұрын
nvm im so stupid. If ab
@Labrador.007
Жыл бұрын
Yes
@PrimeNewtons
Жыл бұрын
Correct!
@MindBytes_18
9 ай бұрын
thankssssssssssssssssssssssssssssssssssss a loooooooooooooooottttttttttttttttttttttttt.
@user-nd7th3hy4l
6 ай бұрын
lim(...............)=12 X->1sans parenthèses c est faux. .
@PrimeNewtons
6 ай бұрын
Merci!
@Reivivus
9 ай бұрын
Can’t you just input x = 1 into the function retrieve 12 and there is your proof?
@tomtomspa
4 ай бұрын
With all due respect, i recommend you to learn about limits and all about what they are, before explaining them to unaware people on yb. Because this explanation is all wrong. It's wrongly stated from the start, it's wrongly stated what the goal is, it's wrong in its conclusion. Just as an example it's not true that with delta
@tomtomspa
4 ай бұрын
I must add to that that i appreciate your work so long as it doesn't involve limits.
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