What's the name of the formula for your radius(r)?
@MATHStorya
Ай бұрын
No name…just the process…
@dv.1krim
22 күн бұрын
It is similar to "Point to Line Distance Formula"
@yanjemie
Ай бұрын
how about the center is not given then the tangent line is x+y=2?????
@MATHStorya
Ай бұрын
Give me the problem?
@rogemmarkperez1892
Жыл бұрын
Did you forget to get the square root of the denominator; numerator shouldn't even be squared? Equation should be Ah + Bk + C / the square root of A squared + B squared.
@rogemmarkperez1892
Жыл бұрын
The answer should be negative square root of 13; or -3.61
@MATHStorya
Жыл бұрын
Hello…i am using r² formula so that easy to find the value… that formula you said if you’re solving for r.
@dv.1krim
22 күн бұрын
@@MATHStoryasir, is this formula is for General use? Or you've just made it yourself? Because, in my whole life of reading Geometry, Algebra and any other kinds of book, I've never seen this. It looks like similar to "Point to Line distance formula".I mean, I'm not saying that you're wrong, I'm just asking with all due respect.
@grantdeguzman5142
Ай бұрын
what if only 0ne center? and given the center of tangent?
@MATHStorya
Ай бұрын
Whats the problem?
@emilandreisantosislag924
Ай бұрын
pano po pag may coordinate points na hinahanap
@MATHStorya
Ай бұрын
What are the unknowns po ba?
@sheinamandapiton
Жыл бұрын
hello sir, may i ask if my answer is right
@sheinamandapiton
Жыл бұрын
Find the equation of the circle with the center at (-4,2) and tangent line to the line 2x-y+2=0 h= -4 k= 2 2x-y+2=0 A= 2 B= 1 C= 2 r² (Ah+Bk+C)² over A²+B² = (2(-4)+(1)(2)+2)² over 2²+1 = (-8+2+1)² over 4+1 = (-11)² over 5 = 125 over 5 => r² = 24.2 (x+4)²+(y-2)² = 24.2
@sheinamandapiton
Жыл бұрын
paki correct po ako hehe needed lang po
@MATHStorya
Жыл бұрын
Whats problem?
@sheinamandapiton
Жыл бұрын
hello sir, may you check sir if my answer was right hehehe, nasa taas po
@sheinamandapiton
Жыл бұрын
Given : Find the equation of the circle with the center at (-4,2) and tangent line to the line 2x-y+2=0
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