you are right. But it is limit. not vertex. It is a parabola.
@MyGroo
3 ай бұрын
@@user-xf7lj6zo2t If you get first derivative and solve for y'=0, you get x = -b/2a
@ntard
3 ай бұрын
What if it is a rightward opening parabola(y² = +- 4ax)
@gregnixon1296
3 ай бұрын
@@ntard LOL, but it isn’t.
@vaibhav_shashwat2219
3 ай бұрын
@@ntard we take dx/dy instead of dy/dx
@MacClintock
3 ай бұрын
Another approach is to factor and rewrite it as y = 3(x+2)^2 - 7 I like how the answer can be immediately seen in this form. The vertex occurs at x+2=0 and y=-7
@OPNURISYDER
3 ай бұрын
Fantastic! Thank you, Professor!
@Quissayilen
Ай бұрын
Learned more from you than my college professor❤ thanks for making it easy to understand I really appreciate this🌸
@MatthewVivanco
3 ай бұрын
Instead of plugging in you can use synthetic division, whatever the remainder is that’s ur min/max.
@user-xf7lj6zo2t
3 ай бұрын
yeah, you can get the tangent of the equation, and you get also, another form of vertex of a parabola.
@gedeontita6036
3 ай бұрын
Thank you
@zahariastoianovici8590
3 ай бұрын
Excellent, so easy to learn , thank you! Wish I had math presented this way 45 years ago when in school! Learning again and enjoying this logic now is such a refreshing exercise for depression
@marianondrejkovic2084
3 ай бұрын
Derivation Still seems to be much easier to Remember
@captainkibbles3502
3 ай бұрын
What? This has to be satire lol, derivation is years more advanced. Although I'd use derivation for anything of larger degree then that of a quadratic
@marianondrejkovic2084
3 ай бұрын
@@captainkibbles3502 Yes. Thanks derivation I do not have to Remember any formulas about polynoms
@user-xf7lj6zo2t
3 ай бұрын
you are on track. but it is acceleration within the parabolic distance vs. change in motion. Physics! and or Calculus.
@avisibleparadox
3 ай бұрын
or take the first derivative of the given parabola and set it equal to zero and evaluate (this works because of the minima of the parabola that is the vertex)
@seekingCK
3 ай бұрын
works everytime??? would be so much eazier
@seekingCK
3 ай бұрын
wait, derivative is 6x+12 we equal to 0 means x=2. not -2 as in the video
@carultch
3 ай бұрын
@@seekingCK 6*x + 12 = 0, solves for x as x = -2. The 12 becomes negative, when you shuffle it to the opposite side.
@seekingCK
3 ай бұрын
@@carultch damn. Im sorry i was way to tired i think. Shame on me sry. Thx for the tipp tho, way faster that way
@jamesharmon4994
3 ай бұрын
@@seekingCK I made the same mistake. LOL
@jjm1835
3 ай бұрын
Thank you so much worlds best teacher
@user-ue4mt6ii7d
3 ай бұрын
In the next video, show a figure that represents the result, this helps a lot with understanding.
@chiragtulsani
3 ай бұрын
Since this is a parabola that opens upwards or downwards, you can also take the first derivative and the slope at the point where the vertex is will be zero. y= 3x²+12+5 Differentiate w.r.t x dy/dx = 6x+12 = 0 (the derivative is the slope of a function) 6x + 12 = 0 x= -2 Put the value of x back in the original equation y= 3(-2)² + 12(-2) + 5 y= -7 Hence the vertex is (-2,-7)
@yan8433
3 ай бұрын
That surely is the easiest way to get the solution. Great work !
@harrymatabal8448
3 ай бұрын
Great work
@patriciaceli1536
3 ай бұрын
Wow! Than you!
@user_drs0105
3 ай бұрын
Those who are watching mrhtutoring shorts from India 👇
@leviwright9493
3 ай бұрын
Another way to find the y of a vertex is using the equation c - (b^2 /4a).
@Patyx42
3 ай бұрын
-Δ/4a
@Slerdus
3 ай бұрын
Thank you sir!
@hustledog
2 ай бұрын
Someone please find this man. I want to thank him
@AndrewPhillips-fs3lo
2 ай бұрын
Thank you so much
@tentenchu8140
3 ай бұрын
You switched from two different markers, a white board, and being silent, to using a chalkboard and talking!
@carultch
3 ай бұрын
Hahaaha!
@MrHBox
3 ай бұрын
I think it’s better to either differentiate or factorise. These methods are much easier to remember than a formula and apply to other situations.
@user-km2fh5zi7p
3 ай бұрын
Nice trick 😊😊
@carultch
3 ай бұрын
It also works to find the inflection point of a cubic, y=a*x^3 + b*x^2 + c*x + d. -b/(3*a) gives the x-position of the inflection point. In general, -b/(n*a) gives the x-position of the central point of a polynomial of degree n.
@user-km2fh5zi7p
3 ай бұрын
Happy April Fools Day. 😅😅
@anestismoutafidis4575
3 ай бұрын
y=ax^2+bx+c Xs=-b/2a y=3x^2+12x+5 Xs= -12/(2•3) Xs=-2 (put in the first equation) y=3•(-2)^2+12•(-2)+5y=-7 The vertex of the parabola is v=(-2/-7)
@nilsalmgren4492
3 ай бұрын
Ti 84 with a min or max function is even easier.
@Abhinandvijayan2006
3 ай бұрын
Thanku sir
@user-xf7lj6zo2t
3 ай бұрын
Professor, I figured it out differently, x = -b / 2ac , sos, x= -12/ (2*3*5) , x = -12/ 30, x incinclitude -2/ 5. incentitude, uclide, -.4. y=-b(a) + c where c is the inetitude of y sound value. y= -12 (3) + 5; y = -36 + 7, y= -37 + 7 + 1, -30 + 1, -29. x= -.4, y = -29, the x and y value for the vertex of eq.
@dougr.2398
3 ай бұрын
This is rote memorization. Something we were not supposed to do, years ago. This only works because a) calculus says dy/dx = 0 gives a minimum or maximum value for a parabola WHEN and ONLY WHEN the parabola is not oriented on a skewed axis and there is an axis of symmetry parallel to the y axis. How to obtain the vertex of a SKEWED axis of symmetry parabola?
@samc4531
3 ай бұрын
You used a lot of words to say "when y is a function of x".
@ashenafigirma9219
3 ай бұрын
(-b/2a,4ac-b^2/4a)
@Potencyfunction
3 ай бұрын
I think he mean inflection ( not vertex)
@ProjectPro2
2 ай бұрын
How did he get y = -7?
@cliffordabrahamonyedikachi8175
3 ай бұрын
-2,-7
@Little_Gamer00
3 ай бұрын
why do you have no comments
@MKashifMathematics-vs8wc
3 ай бұрын
❤
@formulanova12
3 ай бұрын
Not anymore
@MKashifMathematics-vs8wc
3 ай бұрын
Subscribe us for Mathematics
@mircoceccarelli6689
3 ай бұрын
😁🤪👍👋
@jonathonharris8753
3 ай бұрын
I set the 1st order derivative to 0
@saiedahmed5289
3 ай бұрын
dy/dx = 0 6x + 12 =0 x = -2 y = -7
@thomasjefferson6225
3 ай бұрын
First dervative?????
@mrhtutoring
3 ай бұрын
Yes, however it may require more steps
@thomasjefferson6225
3 ай бұрын
@@mrhtutoring both methods are nice. To be honest, I've been doing so much with measure theory and functional analysis that seeing things like this is nice again. I kinda miss this type of math honestly
@thomasjefferson6225
3 ай бұрын
@@mrhtutoring actually, doesn't this only work with parabolas? A dervative is more generalized method I would assert. Still I'll teach your method to my kids when they get to algebra:)
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