It's amazing how I can find free lectures online that are better than the ones I pay for at university. Thank you for posting. Very clear and understandable.
@lrcampos716
9 жыл бұрын
These videos are such a huge help. I love that I can take book notes and then just let your videos play in order and basically make sure I fully understand what I just read. I hope you continue to grow as a youtuber and people continue watching your videos.
@azrabasaruddin5859
10 жыл бұрын
Doc, I gotta say, you rock! If all the lecturers have the same enthusiasm as you when it comes to teaching.. Anyway keep up the awesome videos!
@sapphireblue9209
3 жыл бұрын
I may be 7 years late, but I LOVE your videos! I always prefer them for studying physics. Even if it's something I've already learnt, I still prefer watching your videos because I love the way you teach and your contagious enthusiasm. Definitely recommending you to everyone :)
@DocSchuster
11 жыл бұрын
You gotta wait till I'm dead, man. But I deeply appreciate the sentiment. Rock on!
@dipbhowmik4583
5 жыл бұрын
This video is one of of the best for understanding GAUSS LAW Basics so easily!!
@kenmken
7 жыл бұрын
I wish my professor was as contagiously enthusiastic about the subject as you are
@DocSchuster
11 жыл бұрын
Life rocks because of you! Thanks!
@DocSchuster
11 жыл бұрын
Happy to help. Thanks for letting me know!
@mikes3737
8 жыл бұрын
well done, excellent use of analogy instead of using jargon like everyone else!
@hexacross
11 жыл бұрын
I'm a college Sophomore and you're catching me up on my latest two lectures (you also helped me a good deal in mechanics). Thanks for being a fantastic teacher!
@MrBroseph19
7 жыл бұрын
One of your best Doc!
@nicholasgonzalez
10 жыл бұрын
Amazing explanation! Thank you!
@ananyasampath827
9 жыл бұрын
Beautifully explained!
@prateekgurjar1651
7 жыл бұрын
BEAUTIFUL...DESERVES A COOKIE
@JuiceBoxBoiii
4 жыл бұрын
A beautiful explanation. Thank you.
@foxillicPVP
4 жыл бұрын
This is actually amazing thank you so much
@copychef
9 жыл бұрын
THANKS DOC!
@jhasllanmartins5484
9 жыл бұрын
Nice nice! Well, great video
@Parameswar_Ghosal
9 жыл бұрын
sir i am from india , i really like your video .
@EigenA
4 жыл бұрын
Very good, thank you!
@rishabhpandey4575
8 жыл бұрын
Awesome......😘
@Kenza1996
11 жыл бұрын
Very informative, thanks a lot
@AMIIN2007
4 жыл бұрын
Thank you so much.
@Pierr0tLaLune
6 жыл бұрын
thanks doc
@kumarar745
4 жыл бұрын
Nice explanation
@dillonberger4036
10 жыл бұрын
The proof that I came up with for the E of a parallel plate capacitor is a bit different. What I did, is I treated each plate as if it were an infinitely charged plate and then made a cylindrical G.S. through each. The result was that on, say, the positive plate you get field lines parallel to the area vector (i.e. pointing "out of" each circle at the ends of a cylinder), and, on the negative plate you get the field lines exactly antiparallel to the area vector (i.e. "going into" each circle at the ends of a cylinder). In the former and the latter, the answer came out to be sigma/2epsilon (since, if you keep track of your negatives correctly, the latter case turns out a positive answer). Then I noted that for ALL parallel configurations of the two plates,you always get parallel lines inbetween the plates, and antiparallel lines on the outside. Therefore, by the law of superposition of electric fields, the electric field always cancels on the outside, and always adds on the inside to give you E=sigma/epsilon. QED. P.S. I think that you had this proof in mind when you said that there is ONLY an electric field between the plates, which is by all means correct (as i just proved), but it would be helpful to run through a quick informal proof not unlike the one I just presented to enforce the intuition for why that is the case.
@kyram8315
5 жыл бұрын
'im gonna use rho' *writes a sigma* thanks for the videos tho! I have an exam on electromagnetism tomorrow and watched a few of these that helped me practice:)
@darkyoumemento5307
3 жыл бұрын
Mind blown
@sark9827
8 жыл бұрын
thank you so much!!!
@nicitakhattar1160
8 жыл бұрын
Hey Mr Doc! Great video but I have a question, do we ignore the -ve sign when taking Electric field and Area cross product cause on the right hand side we get -ve charge(so they get cancelled)? And thank you for making such easy to comprehend videos. I would give you a flower pot for that(but with flowers). Your enthusiasm and love for physics is infectious! Keep rocking! :)
@ThousandGigs
11 жыл бұрын
Dude! Doc, you deserve to be sainted like, while you still alive! You're the man!...Is sainted even a word...hmm :3
@kabandajamir9844
Жыл бұрын
So nice
@bahjat1993
10 жыл бұрын
Could someone please explain the Kc in the Epsilon 0. I'm confused to how you would work that out :S And what is the equation for the charge enclosed?
@morganlyttle6137
8 жыл бұрын
Why is the E field not equal to sigma over 2(epsilon0)? Wouldn't you account for the field lines going both out of the positively charged plate and into the negatively charged plate?
@adosar7261
5 жыл бұрын
Would we come to difference result if cylinder was bigger than the plate?
@jamesrbailey
9 жыл бұрын
Unless I missed it, the analysis of the parallel plate capacitor neglects to mention that it assumes charge sheets of infinite area. I think this is important because it's necessary for a proper intuitive understanding, as well as formal correctness - for example, it's not clear why the electric field is zero outside the capacitor otherwise.
@DocSchuster
9 жыл бұрын
***** YES!
@amanbeerkhanduja6490
8 жыл бұрын
Is taking the direction of the area vector outward for a spherical body a convention or a well-defined rule? P.S Love your videos, Doc.
@PrinceThakur-et8ck
9 жыл бұрын
Does your videos cover my 12th class physics cbse syllabus please reply Quickly
@DocSchuster
10 жыл бұрын
And he replied at 6:42...
@didolavox9647
9 жыл бұрын
Why is the flux poiting towards the minus side in the example with the capasitors?
@DocSchuster
9 жыл бұрын
Didola Vox Study electric fields.
@MrHotBagel
7 жыл бұрын
So I've heard that there is electric field outside the parallel plates mentioned in other textbooks. Can you provide your explanation as to why there is no electric field on the outside, considering the plates r thin for an infinite sheet of charge.
@MrHotBagel
7 жыл бұрын
What If? Suppose two infinite planes of charge are parallel to each other, one positively charged and the other negatively charged. Both planes have the same surface charge density. What does the electric field look like in this situation? Answer The electric fields due to the two planes add in the region between the planes, resulting in a uniform field of magnitude s/P0, and cancel elsewhere to give a field of zero. This method is a practical way to achieve uniform electric fields. Taken from "Physics for Scientists and Engineers" by Serway
@shahzadahmad-ly7ru
6 жыл бұрын
If both plates are positively charged then there must be electric field out side of the each plate ,and zero is inside the plates
@FAKEShawn
7 жыл бұрын
idk why, but you remind me of Deadpool but a smarter version
@sadiasiddiqua4945
6 жыл бұрын
FAKEShawn wtf😂
@raiyanreza9764
3 жыл бұрын
lol does this not remind you of a "dream catcher"? Nevertheless, this is awesome
@beeceepedia3784
6 жыл бұрын
Great video. I have a question. Wikipedia lists it as a double integral and I was wondering if there was something I was missing as to why it's a single integral here and a double there. en.wikipedia.org/wiki/Gauss%27s_law
@umaidbhat29
10 жыл бұрын
Where is remaining part
@Teppei9asone
11 жыл бұрын
PHYSICS.
@swaggyp4097
9 жыл бұрын
Sorry if this sounds dumb, but at 10:25 you said that the integral of dA over A is surface area. However in the parallel plate capacitor question you said the integral of dA over A is just area.
@swaggyp4097
9 жыл бұрын
Swaggy P Nevermind, biggest brainfart ever.
@DennyMapleSyrup
8 жыл бұрын
12:46 that's lower case sigma, not rho :P
@ChristianKrause89
10 жыл бұрын
6:36 => "That's what she said"
@leviterande
10 жыл бұрын
Hi! I have an interesting thought/question Eventhough its only the conduction electron that moves to one side in a conductor, am I correct in saying that the PROTONs displacement is also changed? the reason is that the protons should be attracted closest to the higher electrons density on each side, i..e in charged solid sphere:: 1-The excess charge electrons are all at the surface. 2-the protons of the atoms closest to the surface are slightly displaced and attracted to the higher density of electrons. I am really wondering about this.. Could you please if you can help me with this? Thanks for your time reading my post Regards Karl
@DocSchuster
10 жыл бұрын
Hey Karl! I agree that the protons are attracted to those electrons, but remember why the electrons displaced in the first place - there must be an external field. The protons will also respond to the external field. But I don't expect bond length to change, so if any protons move, all of them will have to. Fun question.
@leviterande
10 жыл бұрын
Doc Schuster Thanks Doc! hmm, I am not sure if I got it. Lets have a solid sphere, put on it some () charge for example and just leave it there. Now, please bear with me , Besides these cute extra electrons that are all now resting evenly on the surface, arent all the protons aswell somewhat a little displaced from their original orbit/cloud/center compared to where they were before there was a() charge? In other words, arent the protons situated now more "outwards" towards the excess () surface charge ?. Furthermore If this is the case , and because of equal pull of the excess () the only protons that are basically almost undisplaced are the protons in the perfect and absolute center of the solid sphere, theoretically ( although I know there is no such thing as perfect proton in the perfect center but you get my idea).
@DocSchuster
10 жыл бұрын
If we're considering a charged spherical shell, there is NO electric field anywhere within it. The same is true inside any perfect conductor. So the protons that are not on the surface don't even know that you've put charge on the outside of the sphere. Consider a free proton about 2 cm from the center of an 8 cm diameter sphere of electrons (nevermind how I made it!). It will be quite attracted to the (few) electrons near it but also quite attracted to the (LOTS) of electrons that are the opposite direction. The symmetry of the sphere makes these two pulls identical.
@leviterande
10 жыл бұрын
Doc Schuster Good Doc! we are the same track now! To get to the point clearer lets continue on the 8cm solid ball example. and let that proton be 2cm to the right from center. when the ball is not charged, this proton is attracted to the sea of electrons all around and the proton is in balance and has a specific location roughly in some measurable point in space. Now!. After the ball gets those extra electrons on its surface here is what I thought should happen: The proton as usual will be still attracted to the sea of electrons in the"right" and the"left" of the proton. However since now you have a more negative charge on the surface uniformly, and thus the field is increased on the right of the proton and since most importantly "the proton is to the right" of the solid ball´s center, the proton now should feel a more attraction force from its right than its left. If our little proton however were to be in the theoretical dead center of the same CHARGED solid ball then I would agree that the proton doesnt displace at all. I am not in argument that I am correct , I just want to understand why the above is or is not the case. I really hope I can understand this to me very interesting and puzzling situation, Thanks a lot for your help
@DocSchuster
10 жыл бұрын
I guess I want to encourage you to agree with two things: 1) the ball will have all its charge on its surface, and 2) there is no electric field at all inside a spherically symmetric charge distribution. If you'll give me those two points, then the proton will feel no force due to the charge on the outside as long as it is within the ball. Outside the ball, of course, symmetry allows the charge on the ball to act like it is concentrated at the center of the ball (assuming it can remain spherically symmetric).
@roflpenguin
10 жыл бұрын
Why is it that we don't also add the equal electric field caused by the negative plate? (otherwise I love this video)
@DocSchuster
10 жыл бұрын
The beauty of Gauss's Law is that we HAVE included the field from both plates. You can show easily using the same process that the field from just one plate would be sigma/(2 epsilon naught). Try it!
@misterfancykins9377
9 жыл бұрын
Doc Schuster I thought that the reason that the electric field inside of a parallel plate capacitor is constant was that electric field is inversely proportional to distance, so the farther away from one plate you get the weaker the electric field due to that plate but the stronger the field due to the other. If there was only one plate, wouldn't the electric field vary with distance?
@deependraverma4382
7 жыл бұрын
why can't we take the charge present on "FLUX CATCHER" along with the charge inside it because it says " The TOTAL charge enclosed'?
@DocSchuster
7 жыл бұрын
The Gaussian surface is not real. It can't hold charge.
@deependraverma4382
7 жыл бұрын
Oh man! thanks, Now I understand that
@PeterMilanovski
3 жыл бұрын
It might as well have been written by an alien! How is that supposed to be intuitive LoL. Not sure if I was learning something scientific or learning another language?
@Yebyaew
10 жыл бұрын
flower pot.
@DocSchuster
10 жыл бұрын
YES! Finally someone understands me!!! Thank you!
@shrimpboyho
8 жыл бұрын
I hate how so many people write the integral of flux through a surface as a single integral...that's merely flux through a boundary...
@DocSchuster
8 жыл бұрын
+New J Indeed, it's sloppy.
@shrimpboyho
8 жыл бұрын
+Doc Schuster But other than that, the video is awesome.
@sebidsouza4029
3 жыл бұрын
No need of sub tittles ,it is blocking what u r trying to explain on the page
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