Line AE is 195mm. Divide AE into 4 segments (ABCDE). Construct A’E’ parallel to AE and 60mm above it. Construct angle 135 degrees at point B to cut A’E’ at point F. Construct angle 337½ degrees at F to cut line AE at G. Bisect angle FBG. The bisector cut A’E’ at H. Construct a perpendicular from point H to line AE. The perpendicular meets AE at I. Triangle FBG is an obtuse triangle and triangle BHI is a right-angle triangle. Transfer angle FBG to point D. The angle line cut A’E’ at J. BDJF is a parallelogram.
Division of line into equal parts or proportion
• DIVISION OF LINE in | ...
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Негізгі бет GEOMETRIC PROBLEM 2 in | Technical drawing | Engineering drawing
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