See more videos at: talkboard.com.au/ In this video, we look at how to find Hooke's constant in a bungee jumping example. Hooke's constant is also known as the spring constant or k-value.
Thank you so much whoever made this! I really appreciate it as i'm having extreme troubles in physics class!
@danieljensen1223
2 жыл бұрын
thanks! your teaching is really good. :D
@fahadnaif3519
4 жыл бұрын
Can not thank you enough. speechless
@sashrikgupta9708
3 жыл бұрын
Thank you sir helped me a lot
@CreaminItClean
4 жыл бұрын
my equation does not have the length of the bungee or the size of the person. It only has the mass of the person and the max stretch. How do I get the elastic potential energy?
@calseynez
7 жыл бұрын
is this similar to differential equation falling bodies of Newton's 1st and 2nd law of motion. if not, then is it similar to the spring constant as well. i'm curious.
@ekowbentsi-enchill2479
5 жыл бұрын
Thank you for the video! How is the gravitational potential energy decreasing? Isn't the person still at a height above ground?
@josephjparsons
2 жыл бұрын
At the lowest point of the fall where the bungee is at maximum extension, all the gravitational potential energy has been converted into elastic energy and stored in the bungee (the person cannot fall while the spring/bungee is attached). As the bungee contracts and pulls the person back up, that elastic energy is converted back into gravitational potential energy. Ek = Eg.
@ArcticZombie
2 жыл бұрын
@@josephjparsons ah ty that makes sense
@rishanthi
2 жыл бұрын
Can you send the answer for this Other end of an elastic cord attached to the ankles of a man with mass m is tied to a tall bridge. Man falls through a maximum distance H and get momentary rest then bounces back up. Maximum tension in the cord is four times the weight of the man. If the original length of the cord is L. force constant equals to,
@ninoengel7869
5 жыл бұрын
Which two factors would you think define the "amount of bounciness"?
@robbekemps1565
2 жыл бұрын
stress and strain
@erickkang6385
2 жыл бұрын
it extended 28m not 8m right??? why is it 8m and not 28 for the extension
@gunnertoor5172
7 жыл бұрын
what was the point of finding the kinetic and gravitaional PE at the start, why not go to 80*10*30 straight away?
@atriagotler
2 жыл бұрын
How can I find the rest of the videos?
@atriagotler
2 жыл бұрын
from here kzitem.info/door/PLPb_42dxitOJeegSHT6LXOfe3uvglViXw
@atriagotler
2 жыл бұрын
Thx!
@colepargiter-walker1190
2 жыл бұрын
@@atriagotler did u answer yourself then say thank you to yourself
@attucksbolasie909
9 жыл бұрын
I understand everything but one part. How is the change in kinetic energy 17600J, it went from 0 to -17600J so shouldn't it be -17600.
@sebastianjovancic9814
7 жыл бұрын
Kinetic energy is a magnitude and thus the calculation should involve the absolute value. The sign of the direction travel is arbitrarily chosen, it could be both negative or positive, but energy is always a positive magnitude in these cases. The positive or negative sign would only really imply the direction that the energy flows, say for example heat exchange, and not negative energy! Late reply but for sake of posterity I thought I'd answer it hehe
@zzzvhztzdzgeidifvjvb
3 жыл бұрын
what is this whitebord program called?
@thentoxd
Ай бұрын
You’ve got a hard disk problem mate
@xXsakkelaoXx
5 жыл бұрын
9:03 you say he is slowing down, but he wont be slowing down before the tension in the rope is greater than his weight? He is still speeding up?
@TheLeontheking
2 жыл бұрын
Yes, but his acceleration is decreasing, I guess that's what he meant.
@nbundza1084
Жыл бұрын
The jumper is gonna die. Practically speaking the bungee is too short and he would bounce back into the platform. A “workable” jump has way longer ropes so you ignore the hight of the jumper, just like you ignore the weight of the chord, air resistance etc 😜
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