time stamps: 1st way 0:43 2nd way 2:17 3rd way 4:15 4th way 7:09 5th way 9:16 I didn't use Heron's formula because all the sides were irrational so it wouldn't be considered "easy". However, here's the proof of the Heron's formula for you guys: kzitem.info/news/bejne/mqeY1qGPqqRlpqQ
@badukalluchan1047
4 жыл бұрын
You really boss You make me a great lover of the mighty math I call math as mighty math
@DynestiGTI
4 жыл бұрын
6th way: Heron's formula (en.m.wikipedia.org/wiki/Heron%27s_formula )
@ndugar8540
4 жыл бұрын
Shoelace formula is eloquent and a simple form of Heron’s formula
@lifeofphyraprun7601
4 жыл бұрын
I thought you would mention the formula that the area of a triangle with vertices (a,b) (c,d) and (e,f) is 1/2 | a(d-f)+c(f-b)+e(b-d) |. I can also give the proof if you want,and if I'm unable to respond,then you can search it up or work it out yourself by constructing trapeziums by drawing lines parallel to the y-axis(pretty simple proof,especially for you).And as always-Nice video!
@legendarysom5605
4 жыл бұрын
Is there any theorem u have not proved
@thedoublehelix5661
4 жыл бұрын
I liked Pick's method the most because I've never heard of it before!
@jakebrowning2373
2 жыл бұрын
How does picks method work if the area of a triangle isn't a rational number?
@thedoublehelix5661
2 жыл бұрын
@@jakebrowning2373 If the points are on the lattice, then the triangle always have rational area.
@jakebrowning2373
2 жыл бұрын
@@thedoublehelix5661 oh I didn't realize that was one of the constraints of the problem, thanks
@jamirimaj6880
2 жыл бұрын
@@thedoublehelix5661 lattice means points right?
@sigma7208
4 жыл бұрын
Goes to youtube to take a break from studying. *accidentaly learns even more*
@blackpenredpen
4 жыл бұрын
Sufyan Khan loll nice!!!
@megauser8512
4 жыл бұрын
lol
@mr.cauliflower3536
3 жыл бұрын
I came to this video to get a way of solving a problem.
@robertvanderleeuw182
4 жыл бұрын
Wow, this is what I thought of on the spot: 1. Use Pythagoras' theorem to calculate the lengths of the sides. 2. Use the Cosine rule to calculate the angles. 3. Flip the triangle so 1 line is horizontal. 4. Draw a vertical line from the highest point of the triangle to the base. 5. Use the Sine rule to get the length of that vertical line. 6. Base * Height / 2. I have a very convoluted mind...
@AlgyCuber
4 жыл бұрын
I thought of the shoelace on the spot but i couldn't remember how it worked so i did the 1st way
@44hwxyz90
4 жыл бұрын
With the sides you could just use heron
@generic8891
4 жыл бұрын
Once you have the angles you can just do 1/2 ab sinC
@fedem8229
4 жыл бұрын
You can also use the semiperimeter formula A=√((s)(s-a)(s-b)(s-c)) Where s=Perimeter/2 and a, b and c are the distances between the points
@imperialrecker7111
4 жыл бұрын
legends you integration for this
@backyard282
4 жыл бұрын
As soon as he started to draw the box in the first method I was like: "oh lol how did i not think of this?
@jamesmantooth4323
4 жыл бұрын
My first thought was to convert the lines into functions and do two integrals
@陈明年
4 жыл бұрын
wtf
@generic8891
4 жыл бұрын
Hardik Bhatia that really isn't an /r/iamverysmart lol. James seems to have forgotten that he'll need to compute the third integral too, but the principle is perfectly reasonable. You can find all of the line equations trivially, and integrating 3 linear equations is about as easy as it gets. Hell, given the diagram you could literally just look at the image and work out the values of the integrals yourself.
@JamilKhan-hk1wl
4 жыл бұрын
@@generic8891 3 equations, but 2 integral only, one for X=2 to X=3 and X=3 to X=7
@Schpeeedy
4 жыл бұрын
@@generic8891 it is an "/r/iamverysmart tho cause this method is just completely inefficient and the comment's only purpose is to try to sound smart.
@yoavshati
4 жыл бұрын
People say you're a showoff, but really, if you like integrals and you're currently working with them a lot it might be the first thought This question was also set up a bit like a shaded area problem where it might be a lot more difficult to get the answer in any other way, and integrals get you to the solution right away
@mastershooter64
4 жыл бұрын
3:13 area of a paralorigram? yea man those paralorigrams are poppin' up everywhere these days
@AthyXrayGD
4 жыл бұрын
blackpointerredpointer is back :o
@blackpenredpen
4 жыл бұрын
AthyXray GD long time no see!
@AthyXrayGD
4 жыл бұрын
indeed :)
@KasabianFan44
4 жыл бұрын
This entire video I was screaming “USE PICK’S THEOREM!!!”
@blackpenredpen
4 жыл бұрын
Nice!!! And I did!!
@KasabianFan44
4 жыл бұрын
blackpenredpen Saved the best until last 😂
@strikerstone
2 жыл бұрын
4:02 really helped me with that counterclockwise thing , ty
@heisenberg4703
4 жыл бұрын
A less elegant and more a brute force approach would be using Heron's formula. Let s be equal to (a+b+c)/2, where a, b and c are the side lengths, then the area of this triangle is: A = sqrt(s*(s-a)*(s-b)*(s-c)) Then find the side lengths with distance formula: a = sqrt(4^2+5^2)=sqrt(41) b = sqrt(4^2+2^2)=sqrt(20) c = sqrt((-1)^2+(-6)^2)=sqrt(37) so s ≈ 8,4790... Pluggin all in(I'm not writing s out, as i have to use the exact value) gives us: sqrt(s*(s-sqrt(41)*(s-sqrt(20)*(s-sqrt(37)) Which is equal to 13
@ranymattar185
2 жыл бұрын
this is how I did it 1. I found the equation for the line from point A(2,1) to B(7,5) which is y=⅘x-⅗ 2. find the perpendicular line that falls down on line AB from point C.(call the point of running into each other point L) we know that the slope for the perpendicular line is the negative reciprocal of the slope of the AB line ==> m(CL)=-5/4 CL eq==> y= -5/4x+b we know the line passes through point C(3,7): 7=-5/4*3+b b=10¾ ==>CL eq : -5/4x+10¾ 3. we need to know where it runs into line AB -5/4x+10¾=⅘x-⅗ 11.35=2.05x x≈5.537==>L(5.537,3.829) 4. using the distance formula we get that CL≈4.06 5. distance formula again but on line AB we get AB≈6.4 6. Area ABC= ½*4.06*6.4=12.996≈13 if I were to type all the numbers after the decimal it would have said 13. ty for following along :)
@VaradMahashabde
4 жыл бұрын
Integrate the line cyclically! A = int(Y_AB dx, A → B) + int(Y_BC dx, B → C) + int(Y_CA dx, C → A) Take modulus for the unsigned area
@CaradhrasAiguo49
2 жыл бұрын
Heron's formula actually worked out nicely here since it reduces to 1/4 * sqrt[(b+c+a)(b+c-a)(a+b-c)(a-b+c)], and two differences of squares, the second being 1/4 * sqrt[(16+4 * sqrt 185) * (-16 + 4 * sqrt 185)] = 1/4 * sqrt[16 * (4 + sqrt 185) * (-4 + sqrt 185)] = 1/4 * 4 sqrt(185 - 16) = sqrt(169) = 13
@Sam_on_YouTube
4 жыл бұрын
Here's how I would do this (paused at the start): 5×6=30=area of rectangle 5×4/2=10=area of lower right corner 4×2/2=4=area of upper right corner 6×1/2=3=area of upper left corner 30-10-4-3=13=area of triangle
@Apollorion
4 жыл бұрын
I just did the same.
@akzo5715
2 жыл бұрын
You can also solve this problem by doing (1/2)IIABII⋅distance between C and AB. IIABII is simply sqrt(4^2+(-2)^2) and the distance between C and AB is IICA projected on n(from AB)II
@robbechristiaens6384
Жыл бұрын
Pythagorean theorem + Heron's formula works And with a lot of detour, you can also use (1/2)*b*c*sin(alpha)
@kaylaklimas6058
4 жыл бұрын
I calculated the length of every side with Pythagoras, used the law of cosines to find an angle then did 1/2 a b sin C. This process involved literally drawing a box around the triangle. Yet somehow I was still mad when "it's just a box" was revealed.
@Queenside_Rook
4 жыл бұрын
I did exactly what you said not to do at the beginning and got 12.9989 I found the length of the longest side with Pythagorean theorem and got sqrt(41), then found the slope of that side to be 0.8 and found the y-intercept of the line it lies on to be -0.6. From there, I found the formula of the line with the negative reciprocal of that slope (perpendicular to that side, y=-1.25x + 10.75) that passes through the point (3, 7), then set it equal to the line the bottom side lies on to find their intersection (5.53658 all repeating, 3.82926 all repeating) then found the distance between that point and (3, 7) with Pythagoras again (4.0601940101). This is where the rounding errors start to set in, but I assumed since my answer was so close to 13 that it was probably equal to 13.
@dannyphantom0073
4 жыл бұрын
6th and 7th way Calculate the point of the altitude from any vertex to the base using straight lines equations Then use 1/2*base*height 7th way Use heron's formula By calculating the semiperimeter of the triangle and then use √s(s-a)(s-b)(s-c)
@sheppsu7353
4 жыл бұрын
The only methods that I know, are making a bunch of calculations with trigonometric functions, or simply using Heron's formula, so I went for the second option. So, for the sides, the top one will be a, the right one, b, and left, c. a = 2*sqrt(5), b=sqrt(41), c=sqrt(37). S=sqrt(5)+sqrt(41)/2+sqrt(37)/2. sqrt(S(S-a)(S-b)(S-c)). I'm too lazy to write all that out find what the area is so I used desmos and got a nice answer of 13.
@lauroneto3360
4 жыл бұрын
You forgot to use the integer of each line from point a to point b. That's the coolest way to do it. Of course you need to use subtraction and summatiom of the trapeziums.
@El-Mikey
4 жыл бұрын
Man, i love this channel
@holyshit922
4 жыл бұрын
I prefer to use determinant to calculate area Double of this area can be useful for convex hull Fun fact Determinant of 2x2 matrix gives us area of parallelogram Determinant of 3x3 matrix gives us volume of parallelepiped Definite integral gives us area under a curve Double integral gives us volume
@idrisShiningTimes
3 жыл бұрын
Thank you so much sir. This showed me not one, not two but FIVE ways of finding area of a triangle with the given vertices. This is really cleared all my doubts regarding this. Thank you sooo much sir!!!
@burk314
4 жыл бұрын
In the second method, you said the order of the vectors doesn't matter. Technically it does because the other order will give you a negative. The formula is the absolute value of the determinant (it would be nice if our notation for determinant didn't look like it already involved taking the absolute value).
@nathanbeer3338
2 жыл бұрын
Haven't learnt Matrices nor Pick's Theorem, I solved it using only with vectors. I used this function to find one of the angles: cos(x) = (u * v) / (|u| * |v|) And from there just used A = (d1 * d2 * sin(x)) / 2
@nmmm2000
4 жыл бұрын
6th method - use Protagoras and calculate each side length. then by Heron formula, calculate the area. :) I saw your comment, but it puts square roots in the mix and makes method extra difficult...
@InfinityExt
6 ай бұрын
you forgot the find the altitude by making a perpendicular to one of the sides which is just negative reciprocal that passes through the opposite vertex and then finding where it intersects the side it is perpendicular to then finding the length with distance formula or pythag thereom and finding length of side and doing base times height devidied by two. way easier than matrix
@JeremyBarrett1
4 жыл бұрын
Thank you for this interesting video! I’m wondering... what software/hardware did you use as you were drawing on the screen?
@marmikpatel9261
4 жыл бұрын
Thank you for working on geometry😀
@nigeldavis
4 жыл бұрын
you could choose a side and make a linear function to represent it then just find the perpendicular bisector connecting it to the opposite point finding where they intersect and then you can easily just find the lengths using Pythagorean theorem to find base length and height and simply do b*h/2
@johnrodonis4186
4 жыл бұрын
How about the semi-perimeter formula? Granted, the distances of the sides is needed. (Too much distance formula!!). But it is yet another option.
@mmg952
4 жыл бұрын
You can also divide the triangle into a right-angled triangle and two other triangles
@mmg952
2 жыл бұрын
connect 3 vertices to (3,5) there you split 1 into 3
@trueriver1950
4 жыл бұрын
Area of trapezium/trapezoid is (separation of // sides) × (mean length of // sides). Drop verticals to axis from each vertex to the axis. Add the areas of the trap. below the upper lines, subtract the area of the trap below the lower line. =13. You can also draw horizontals to the y axis and do the same sideways. =13 again :)
@John-hz8xy
Жыл бұрын
Believe in triangles, not calcutors Me, an engineer: I will (I believe in calculators' ability to make our lives easier, but we do have to learn the fundamentals and basics first).
@rociomrpt851
4 жыл бұрын
The last one is amazing!!!
@nidhiagrawal3354
4 жыл бұрын
5th one - lovely
@MarceloSilva-lh9mh
4 жыл бұрын
The area in question is equal to a sum of two definite integrals: the integral from 2 to 3 of 26x/5-52/5 (with respect to x), and the integral from 3 to 7 of -13x/10+91/10 (with respect to x).
@shubhammygt37
3 жыл бұрын
I liked the pick's method to solve this problem.
@rrr1304
4 жыл бұрын
2nd is best for me
@dimitrijejelic5492
3 жыл бұрын
I would use the Pythagora's theorem to calculate all 3 sides of the triangle and then use Heron's formula to calculate the area.
@qingyangzhang887
4 жыл бұрын
You can also use tangents to find the angle between two lines, and then use sine rule to find the area. I'm guessing you won't like it cos it involves finding length using pythagoras
@rasheedmohammed2227
4 жыл бұрын
You can use heron's formula to solve as well as, so there are 6 ways!
@ranjankumarmahapatra8598
4 жыл бұрын
The 2nd way is very easy to use.... But plz upload the proof ...👍👍
@blockthrower3947
4 жыл бұрын
i got another easy way to calculate. count the amount of squares you can make as the parts which arent a whole square add with other parts to make a full square
@timol94
4 жыл бұрын
why does the third way work? the scalar triple product gives us the volume of a parallelotop, but this parallelotop does not have a hight of 1. And it´s base is not the triangle (parallelogram) from the beginning. Sorry for my bad english.
@paulhaso
4 жыл бұрын
I'm studying geometry right now, couldn't have come at a better time. Think of a box!
@connerp6878
4 жыл бұрын
Please upload more trig / geometry related videos. THANKS!!!
@einsteingonzalez4336
4 жыл бұрын
Bane Neusis construction?
@mrmimeisfunny
4 жыл бұрын
I was just going to calculate the side lengths and plug them into Heron's Formula. and get twisted around by all the square roots Yknow... the 0 thought method.
@iyer2001in
4 жыл бұрын
Liked the 2nd method. But isn't that also the cross product of 2 vectors?
@davidgould9431
4 жыл бұрын
Love it! Some of them were surprises; some were vaguely familiar but forgotten (my memory's not what it was - at least I don't think so). Being a Bear of Little Brain, my first thought was the "rectangle minus 3 triangles" one, which reminds me of one of the proofs of the theorem of Pythagoras. If I were an engineer (I'm not, any more than I'm a mathematician), I might have got some paper of known weight (the units are a sort of planar density, typically g/m²); picked¹ a scale; drawn and cut out the triangle; weighed it; and (finally) the area would be the weight of the triangle divided by the paper's weight/area suitably scaled back down (or up, I suppose). The error bars would be huge, but you could mitigate that by weighing a lot of them and dividing by how many you weighed. ¹ Not that Pick, but I was intrigued to see that method. I vaguely think I've seen something like it before but had forgotten it.
@flix7280
4 жыл бұрын
Area of a triangle in coordinates=1/2(X1(y2-y3)+X2(y3-y1)+X3(y1-y2)
@pacifir-e4375
4 жыл бұрын
does the pick Pick's theorem work for any shape on a grid
@ZackSussmanMusic
4 жыл бұрын
Very cool! Would have been nice to see some double integrals 😎
@DefenderTerrarian
2 жыл бұрын
I personally prefer calculating the edge lengths with Pythagoras' Theorem. Then use the Heron's formula for my Triangles.
@habibrahman-qj9nn
2 жыл бұрын
Yes.at first calculating the length of the triangle we can use herons theorem
@Emma-rw8yo
4 жыл бұрын
Pick's Theorem is really cool! I've never seen it before at it was really interesting That or the box would probably be my defaults
@micronalpha
4 жыл бұрын
(5:15) Shouldn't the height be 0 instead of 1 if that's the explanation is really the volume of a prism with null height? By the way, I prefered the Pick's Theorem. If I had to come up with a way to solve it, I would use Heron's Formulae, where A = sqrt(s.(s-a).(s-b).(s-c)) where a,b,c are the lenghts of the sides (using the distance formulae betwween points) and s= (a+b+c)/2. This is a most interesting video, BpRp. :)
@blackpenredpen
4 жыл бұрын
Oh I was saying that the numerical value of the area and it’s volume if h=1 would be the same. And thank you!! : )
@adityarupda1795
4 жыл бұрын
Hi Steve chow I have done this problem by calculating the distance between each line by distance formula I got the distance between (3,7) and (7,5) is 3√5 the distance between (7,5) and (2,1) is √41 and the distance between (2,1) and (3,7) is √37 after finding the distance between each line I find the altitude by Pythagoras theorom and after that by formula of area A=1/2× base×altitude and I got approx answer 13.4 is it correct ????????????????
@ilias-4252
4 жыл бұрын
Shouldn't the determenant be an absolute value on way 3?
@theodorepanagos402
4 жыл бұрын
2*A=(3-2)*(7+1)+(7-3)*(7+5)-(7--2)*(5+1)=26 .A=13
@_Mk_ultra
4 жыл бұрын
Very interesting. Thanks. What about the area of a triangle in different ways with a 3-dimensional coordinate-system?
@TheHatkeHaryanvi
4 жыл бұрын
Can You solve area of a triangle whose angles are 43,36,101
@adityaagarwal636
2 жыл бұрын
10:54 3Blue1Brown is your patreon😳😳
@danielchowdhury1008
Жыл бұрын
I believe I have other method that doesen t apear in the video, ( I haven't tested yet), but I think it works. Firstly, let's assign letters to the given points: A(3,7), B(7,5), and C(2,1). Next, we can calculate the vectors BC and CA. Then, by taking the dot product of these vectors using their coordinates, we can determine the angle CBA. After that, we can draw a perpendicular line to divide the triangle into two right triangles. Utilizing trigonometric formulas, we can calculate the area of each right triangle and simply add them together
@danielchowdhury1008
Жыл бұрын
That was my first thought
@sheshij64
4 жыл бұрын
I liked shoelace and picks theorom .😀
@thrashes6208
4 жыл бұрын
wth, never woulda guessed anything like Picks theorem coulda worked. Such a simple equationand actually using the points? I woulda just done the first one to be honest. Trigonometry is my favorite by far! Calculus is pretty fun too though (although the setup is the most boring thing imaginable!).
@johnhumberstone9674
4 жыл бұрын
I hope this style is not going to replace the whiteboard, the pens, the microphone and your handsome face!
@blackpenredpen
4 жыл бұрын
John Humberstone Unfortunately that won’t happen for a while bc of the current issue. I only have a few more pre recorded videos that are to be published later.
@abhinavshah2734
4 жыл бұрын
i will use the determinant method
@ccdsah
4 жыл бұрын
I knew The 3rd and I like it most.
@Ben-wael
4 жыл бұрын
I have one that 1/2 × rib ×rib × the angle which was on this ribs
@coontzy1
4 жыл бұрын
Someone explain what the determinate thing was?
@laurenlofton9039
4 жыл бұрын
I can’t give you the easiest, but you can form right triangles and use the Pythagorean Theorem to find the length of each side. Than you can use Heron’s Theorem to find the area.
@adrien5568
4 жыл бұрын
The same method that the first one but using integrals to compute the areas.
@Artur_Stoll
4 жыл бұрын
So, what about integration?
@viralgandhi8829
4 жыл бұрын
Picks theorem....Is it applicable for all triangles...
@technoultimategaming2999
4 жыл бұрын
what I would do is subtract 2,1 so (3-2,7-1),(2-2,1-1),(7-2,5-1) (1,6),(0,0)(5,4) I forgot the next steps
@dhruvthakur1036
4 жыл бұрын
*WE CAN ALSO* Find out equation of each line and find out the limits as x coordinate and find out the area by *integration* !!
@Ninjamaster222333
4 жыл бұрын
but is it easy? might be but also time consuming
@einsteingonzalez4336
4 жыл бұрын
Greetings, blackpenredpen. Have you ever used a geometric compass? And yes, there’s one available that’s suitable for the whiteboard and the markers.
@blackpenredpen
4 жыл бұрын
Yea. I don't use it often anymore tho.
@einsteingonzalez4336
4 жыл бұрын
blackpenredpen Then what about constructing the cube root of any number other than compass and straightedge?
@erikkonstas
4 жыл бұрын
@@einsteingonzalez4336 That might be possible if you allow sci-fi stuff... and the Delian problem can also be solved like that.
@einsteingonzalez4336
4 жыл бұрын
@@erikkonstas So this Wikipedia article is sci-fi? en.wikipedia.org/wiki/Doubling_the_cube#Solutions_via_means_other_than_compass_and_straightedge
@splodinatekabloominate846
4 жыл бұрын
Distance formula into heron's formula
@xXJ4FARGAMERXx
Жыл бұрын
Isn't it half base times height? We can calculate the distance since we have the coordinates and bam. The answer pops out. Edit: oh wait, I didn't think about the height...
@AditYa-sv1nz
4 жыл бұрын
Shoe lace
@NonTwinBrothers
4 жыл бұрын
I liked learning about the matrix way, haha
@fswaan5624
4 жыл бұрын
Don’t forget Heron’s formula!
@mokouf3
2 жыл бұрын
Shoelace theorem seems exactly equal to 3x3 det one. I will prefer 3x3 det.
@vangrails
Ай бұрын
Shoelace formula also works for polygons, not only triangles.
@mokouf3
Ай бұрын
@@vangrails With determinant you can write NxN. Maybe the shoelace theorem can save some time if the number of vertices is large.
@Random12260
4 жыл бұрын
My head just went to finding the area via crunching a few linear integrals.
@ansonaroza
4 жыл бұрын
Yo I just found half the modulus of the cross product of the 2 vectors
@hari8568
4 жыл бұрын
Use double integration.Split it into 2 double integrals and it's easy to solve
@soianso0723
4 жыл бұрын
I am impressed😂🤪, I used the first method😂
@sldimaf
4 жыл бұрын
trapezium1 + trapezium2 - trapezium3
@pablourra6672
4 жыл бұрын
Pick's
@aadityabhetuwal5990
4 жыл бұрын
I thought we would be using definite integrals
@JamilKhan-hk1wl
4 жыл бұрын
school never teach pick's theorem because its too easy
@MrPooh1998
4 жыл бұрын
I mess myself after the first way was completed.
@FaranAiki
4 жыл бұрын
Use Heron's formula?
@blackpenredpen
4 жыл бұрын
All the sides are irrational tho. Cool profile picture btw.
@elijahliu1669
4 жыл бұрын
The virgin Shoelace Theorem vs. The Chad Heron's Formula
@agfd5659
4 жыл бұрын
And then the Stacy Pick's theorem
@skulliam4
4 жыл бұрын
The A S C E N D E D Integral[2-3](6x-11)dx + Integral[3-7](-(1/2)x+(17/2))dx - Integral[2-7]((4/5)x-(3/5))dx
@andrewchin3601
4 жыл бұрын
3:11 para-LORY-gram :o
@沈博智-x5y
4 жыл бұрын
What I did: calculate distance from (2,1) and (7,5) Distance = sqrt((7-2)^2 + (5-1)^2) = sqrt(41) {this will be the base of our triangle} find the equation of the line connecting (2,1) and (7,5) y - 1 = m(x-2) find the gradient of the line m m = (5-1)/(7-2) = 4/5 y - 1 = 4(x-2)/5 => 5y - 5 = 4(x-2) => 5y - 5 = 4x-8 => 4x - 5y - 3 = 0 Use the perpendicular distance from a line to a point formula: Perpendicular distance formula: |ax1 + by1 + c|/sqrt(a^2+b^2) where (x1,y1) = (3,7), a = 4, b = -5, c = -3 Let the line connecting (2,1) and (7,5) be the base. => Perpendicular height = |4(3) -5(7) -3|/sqrt(4^2 + (-5)^2) = 26/sqrt(41) => Area of triangle = bh/2 = (26/sqrt(41)) * (sqrt(41)/2) units^2 = 13 u^2 Got 13 in the end.
@blackpenredpen
4 жыл бұрын
Very nice!!!
@gardening_vibes
4 жыл бұрын
I also thought the exact same way but never calculated😂
@Adomas_B
4 жыл бұрын
I thought the same thing right about until calculating the height, I gave up
@anandsuralkar2947
4 жыл бұрын
Lol
@lopkobor6916
4 жыл бұрын
Btw, the music in the background is called “The Entertainer.” I forgot the composer but the title should be correct.
@blackpenredpen
4 жыл бұрын
Yes! I forgot the composer too. I got it from the YT audio library
@einsteingonzalez4336
4 жыл бұрын
blackpenredpen *Scott Joplin.
@einsteingonzalez4336
4 жыл бұрын
If you’re wondering, that is Scott Joplin.
@dr.mikelitoris
4 жыл бұрын
Scott Joplin
@lopkobor6916
4 жыл бұрын
@@einsteingonzalez4336 Thanks for the information!
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