Domain cannot be a>0 and b>0. The solution (x=63/32) itself is making a=0.
@StaR-uw3dc
4 ай бұрын
Yes, the domain is a≥0 and b≥0 and 2-x≥0 (x≤2). Consequently p≥0 and q≥0. The equation 6p²+8q²+15pq=0 has the solution p=q=0 what implies a=b=0 but a and b cannot be =0 simultaneously (65-32x cannot be equal to 63-32x).
@offrampc
4 ай бұрын
@@StaR-uw3dc Makes perfect sense.
@mohammadazadi4535
2 ай бұрын
Hi, you suppose a AND b should be positive that means both of them are posetive , so, how explain about a*b=0 conclude a=0 Or b=0
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