We used directed angles modulo 180. This means angle(SCB) =180-angle(BPS)=-angle(BPS)=angle(SPB). The last equality follows, because swapping B and S changes the direction and therefore, the - sign turns to a +. If you want to have a more detailed description, you can have a look on our wiki entry on our website about directed angles. calimath.org/wiki/directed-angles
@hungcuang2019
Жыл бұрын
I think it would be impossible for me to solve this problem until I see this video. What a nice solution!
@thomasneal7126
Жыл бұрын
I could not have explained any better myself
@muhamedbabe8924
Жыл бұрын
Very nice solution 👌👌
@farmonov_piima
Жыл бұрын
Hello uzb🇺🇿
@epimaths
9 ай бұрын
Hay lắm❤❤❤❤
@carryminati-mk7wv
9 ай бұрын
Nice explanation 😊
@mohamedleminekhayar3713
Жыл бұрын
Think you ❤
@Alexander-oh6ps
3 ай бұрын
i used a different approach (using only second grade knowledge aka no Pascal) by proving that XZ=XA=XP, then proving that LZX is a right angle, therefore XZ and XP are tangents of (BLD)
@calimath6701
3 ай бұрын
Sounds like a cool approach
@mohamedleminekhayar3713
Жыл бұрын
But why tou don’t prove ppzBDY > cone for use the theorem de pascal you need to prouve that
@calimath6701
Жыл бұрын
That's what I did in the first three steps. I proved that P, Z, B, D, and Y lie on one circle, which is a cone.
@mohamedleminekhayar3713
Жыл бұрын
@@calimath6701 what about pp(tangent) ? Do you prove pp are in the same cone with pzbdy?
@cyborgeatsfood8028
Жыл бұрын
W solution
@mrebu-vu8on
3 ай бұрын
A lot of respect to you for this handsome solution 🇧🇩🇧🇩
@fahim-o2q7n
Ай бұрын
কোন ক্লাসে ও ক্যাটাগরিতে তুমি ? IMO তে পার্টিসিপেট করেছিলে ?
@NoNameAtAll2
Жыл бұрын
1:55 it should be 180-spb, right?
@calimath6701
Жыл бұрын
We use directed angles modulo 180°. So, SPB = 180° + SPB = 180° - BPS are all correct.
@AdminAdminilka
7 ай бұрын
l will never be able to solve any İMO problem
@BigMotion1
5 ай бұрын
I can't even solve AIME problems...but if we keep learning, we will be able to
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