oh my god. That split after multiplication is what most lecture videos/books miss to elucidate. Everything makes sense now, thank you
@spiderjerusalem4009
7 ай бұрын
ye, most math books are outlined such as that unfortunately. It's been running through in the culture, since bourbarki or god knows how long. I'd heavily suggest learning based-proof lin alg(notably axler's lin alg done right) subsequent to whatever this horrid boring computational one.
@jpbstamaria
10 ай бұрын
Thank you for an insightful lecture...Not only helpful to students, but also to those who teach this subject.
@jasonbroadway8027
Жыл бұрын
This video comes in handy as a refresher. I did not understand it upon first viewing. However, I commend you for working concrete examples!
@RobertoCarlos-wk3jh
Ай бұрын
OMG just find this video and helped me so much. Greatings from México.
@shizafatima1272
2 жыл бұрын
You explained it in a very good manner...
@mikhailshkaralevich574
10 ай бұрын
Thank you very much for your video. It made lots of sense to me!
@thatoneguy9287
11 ай бұрын
Your vid came in clutch 😂😂😂😂, my algebra 2 final is tomorrow and i didn't understand this topic
@aris.konstantinidis
2 жыл бұрын
Thank you so much for this thorough explanation!
@geethamonnappa4645
2 жыл бұрын
You explained step by step.thank you so much Sir.please give illustration if k=3,4
@manu40729
2 жыл бұрын
thank you for explaining it fully
@MathematicsMadeSimple1
Жыл бұрын
Great presentation here.
@yb801
3 жыл бұрын
you explained well, thanks
@SLstudio1998
11 ай бұрын
Why don’t you get the eigen vector from lamda=2 to the chain
@azeemgadkari4660
2 жыл бұрын
well explained thank u ..
@jzjMacwolfz
2 жыл бұрын
thank you very much!!!! you are amazing!
@shilinyou6632
Жыл бұрын
God, it explains better than my prof lol
@pradyutmaji1704
Жыл бұрын
Thank you sir
@uzivatel123
2 жыл бұрын
thank you
@nahuu4481
2 жыл бұрын
Great!!! But , Eigenvektor for lamba= 4 is (0,-2,1)
@daniel_an
2 жыл бұрын
Any nonzero multiple of an eigenvector is again an eigenvector. Your vector is -1 times mine. So they are both eigenvectors.
@nahuu4481
2 жыл бұрын
@@daniel_an Oh yess! Correct Sir. Sorry
@thenewdimension9832
2 жыл бұрын
Wow 🥰🥰🥰🥰🥰🥰
@user-kx6jv2ns4m
9 ай бұрын
21:13 directly you written jordan form from where you got didnt explain
@davidbarta9512
Ай бұрын
I think you can do it better this way: A=P*J*P^(-1), thus P^(-1)*A*P=J. So you know A, calculate P, calculate P^(-1) from it and you have J. Makes sense?
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