I just want to Give this teacher a hug. Thank you so much for this lecture. This test is now cracked after years of not knowing it. No video has explained it better. ❤
@Samraaa5
Ай бұрын
True
@franklinduru1395
6 ай бұрын
This is the best video for JCC. Thanks for this wonderful lecture❤
@PiyaChoudhari
2 ай бұрын
Exactly 💯
@rP-ff8qq
Жыл бұрын
This was the best video explanation of the JCC procedure. Thankyou for making it in a very easy and digestible way! Love your work!
@drbjn536
2 жыл бұрын
Ma'am thanks for making it simpler to understand and practice. Please make video on binocular balancing/ confirmation of prescription.
@nipohatembo9614
29 күн бұрын
Proper way to explain the jcc❤❤❤ 👏👏 wonderful
@dollon1237
Ай бұрын
The best explanation of jcc ❤ thank you
@Ranjuchaurasia
9 ай бұрын
❤ everything covered in detail and explained so well… thank u
@liliharoon1800
Жыл бұрын
I would like to thank you for this consise yet very informative and helpful video... much appreciated
@stephaniewilliams909
6 ай бұрын
Thank you so much for taking time to make this video on jcc....explained so well❤
@dfrsdav23
Жыл бұрын
Better explanation than others. Thank you veey much
@drsalmaeissa
Жыл бұрын
You are a perfect teacher god bless you
@Samraaa5
Ай бұрын
Thank you so much mam u have explained it so well Respect❤
@manchikantivijayakumari9906
2 жыл бұрын
Excellent madam, it is very clear for me now, 0.5 for power and 0.25 for axis. I will do this way. Thank you.
@ophthalmologypearls
2 жыл бұрын
Thank you You have interchanged the items. It is 0.5 for axis and 0.25 for power.
@Shilnajinesh
Ай бұрын
Best ever video about JCC👍
@daliashehata4839
Жыл бұрын
Thanks a lot ma"am ; Great and simple and to the point 👍👍👍👏👏
@beegumhazana4575
10 ай бұрын
Mam ..this is ok ..but when I do JCC .if the patient with - cyl after flipping JCC , pt reports red line is more clear, then theoretically we add minus power .right? But whether we done it practically it's not confirming the power ..y?
@rakhipal-m7e
Жыл бұрын
Mam jcc me phle axis finding karte h ya power
@anitmariatom7817
Ай бұрын
Thankyou so much ❤
@7777simpleman7777
8 ай бұрын
what an awesome class
@PiyaChoudhari
2 ай бұрын
This is the best video ! Accent and r sound is little irritating but it's so informative that I ignored it mine is also not perfect and sometimes my own accent irritates me and hence I improved upon my accent and pronunciations and still Improving but thanks it's very very informative such practical really useful things we were not taught by our consultants and were taunted,irritated for theoretical non sense and insignificant stuff, useless consultants absolutely useless and irritating ! Thanks for giving us the right accurate information thats actually practically very very significant amd useful ! Awesome video I am gonna share this video link 🔗 🖇️ on my revision part along with elkington audio book I am gonna make on my youtube channel !
@prasannashetty2526
Жыл бұрын
Hii mam while refining the axis of cyl if patient say minus side is better why should we trun around the minus axis .why we can't rotate towards the plus axis .
@ophthalmologypearls
Жыл бұрын
@prasannashetty2526 , In the example given in the video, the cylinder was rotated in the direction of the minus axis of the Jackson cross cylinder becoz the cylinder in the trial frame was a minus cylinder. If the cylinder in the trial frame was a plus cylinder, then it should be rotated towards the plus axis of the Jackson cross cylinder
@XxxxxsilvermistxxxxX
2 жыл бұрын
Single best reference for JCC. Thank you ma'am! I do have a doubt, though, ma'am. At 6:48, If we are adding the SE to the sphere component, why is there a change in the cylindrical value since we have already accounted for that with the SE?
@ophthalmologypearls
2 жыл бұрын
I was trying to explain that if the cylinder change (by using JCC) is greater than or equal to 0.5, then you change the value of the sphere. In the example shown, the original prescription was -2.00 / -1.00 x 180. So the spherical equivalent becomes -2.50. If we add a -0.50 (because of JCC) to the cylinder, we get -2.00 / -1.50 x 180. Now the spherical equivalent is -2.75. so we add half the cylinder change of opposite sign to the sphere - so since we added a cylinder of -0.50, (to -1.00 to make it -1.50), we should add +0.25 to the sphere - so adding this to the sphere of -2.00, we get -1.75 / -1.50 x 180. The spherical equivalent of this is -2.50, which is the same as our original prescription (prior to JCC testing)
@SHARONMUDAU-i3i
5 ай бұрын
well explained thank you sooo much
@patriziopascotto6935
2 жыл бұрын
Ottima spiegazione, potrei sapere che tipo di programma usi per fare queste video lezioni? Thanks
@ophthalmologypearls
2 жыл бұрын
Thank you. I make the presentation in power point along with the animations, and screen record the slide show on my laptop while simultaneously doing the voice recording 🙂
@ophthojooeileyecirclehisha4917
Жыл бұрын
thank you for your teaching thank you
@srisowmithamurugesan2490
2 жыл бұрын
Thankyou mam clear explanation mam
@shetyeechoy3428
5 ай бұрын
Thank you ❤
@deepresearchersbynk
Жыл бұрын
❤❤ nice
@ahmedoptics9905
5 ай бұрын
Best ❤
@ashikakhadka1822
10 ай бұрын
Thank you❤
@hasimkhan5100
Ай бұрын
Hindi me bhi banaye
@issamidrissi5724
Жыл бұрын
THANKS FOR YOU 👍👍👍👍👍👍👍👍
@aswanisidharthan3431
4 ай бұрын
Thank you so much
@dr.zeeshanhameed1868
8 ай бұрын
Thank you so much❤
@Ahmed7oo
Жыл бұрын
Thanks alots
@yousefawad1772
Жыл бұрын
Thank you, that was useful ❤
@SajidhaM-oh2oy
3 ай бұрын
❤
@indiamyland5298
Жыл бұрын
Mam,astigmatic fan test video plz mam
@ophthalmologypearls
Жыл бұрын
Are you an undergraduate or a postgraduate?
@indiamyland5298
Жыл бұрын
@@ophthalmologypearls UG mam
@ophthalmologypearls
Жыл бұрын
Out of curiosity, what is your special interest in this test? It is not required for an undergraduate to know this.
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