Isn't it possible to simplify further? Since there's a division inside the logarithm, it's possible to take out the 2 with the log property. And then we can also write log2 as 1-log5, although this step doesn't change much
@kissszilard4220
14 күн бұрын
4:59 (1-sqrt(5))/2 is less than 0 not greater.
@2sljmath
14 күн бұрын
Thank you for your comment. However, what I meant was that since according to the problem statement, \( t \) is greater than zero, therefore this answer is not our answer. But you are right; it could have been better expressed. Thank you for your attention.
@farhanrejwan
16 күн бұрын
neatly done!
@2sljmath
15 күн бұрын
Thank you 🙏🏼
@timofeysobolev7498
16 күн бұрын
Great video)!
@2sljmath
15 күн бұрын
Thank you 🙏🏼
@timofeysobolev7498
15 күн бұрын
@@2sljmath Thank to you!)
@kacho-rama
16 күн бұрын
Neat,
@orangomango
9 күн бұрын
cool, exactly as I solved it before watching the video
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