In objective questions always try to use some short intuitive checks. Realizing that the domain is [-2,3] , check the value at the end points which is sqrt(5).Hence probably the correct choice is either (b) or (d). Next, equate the two radicals i.e. 3-x=2+x which gives x=0.5 which is a likely inflection point. This may not always be true but worth a check. Value at 0.5 is sqrt(10). Since this is one of the option hence you are pretty sure that's the answer. I use to do these tricks to quickly solve objectives when I cracked JEE in 1998.
@parthasarathirout6286
Ай бұрын
🙏asm....Give some more tips and trick for math
@surendrakverma555
3 ай бұрын
Excellent explanation Sir. Thanks and Regards
@mathematikawizard7787
12 күн бұрын
Sq.rt of ( x - a ) + Sq.rt of ( b - x ) is Minimum at boundaries of domain & Maximum at mid point of domain interval ..
@rohitsharma-uv6og
Ай бұрын
Sum of two square roots cant be a prime number inside square unless one of the roots become zero, so by observation option D is the correct answer. For eg. √x+√y cant be √z where z is a prime number , unless either x is zero or y is zero
@DeepakKumar-sp1ph
Ай бұрын
Sir aapko starting me positive nahi non-negative bolna chahiye
@HarmeetSingh-ou1eh
Ай бұрын
Just squaring both side and min value is when the root term is zero and max when the root term is max check via differentiate
@harsh.mscrm991
3 ай бұрын
thank you
@hvkeee
5 күн бұрын
Super sir explana❤
@aditya-u7s9v
3 ай бұрын
Nice solution,but the question is trivialised by the Cauchy Schwartz inequality
@sanjaypandey3642
3 ай бұрын
Good morning sir , I am Anant dev student of class 12th F I liked your explanation a lot, Thank you sir
@sanjeevsir29077
3 ай бұрын
Thanks
@SakshiShreya-rr2mr
3 ай бұрын
Sir I am in class 10th now, a fiitjee student but I can understand the explaination of the question very well and also able to solve it by 1st method🙏🙏🙏
@Princesingh0004
3 ай бұрын
Bro I am in 10th class, I am not able to join any coaching because financial condition 😞. Can you pls send me modules of your coaching. Pls 🙏
@adityadas5934
3 ай бұрын
@@Princesingh0004 bro I will suggest u best KZitem channel to study 😢 and app to
@mentosgamer1994
Ай бұрын
Bhai mohit tyagi sir ke lectures dekhlo iit pakka h ❤@@Princesingh0004
@preetchauhan1612
Ай бұрын
Which centre....
@dakshgaming1037
3 ай бұрын
Great explanation sir ❤️
@user-cu8vj8lt3g
28 күн бұрын
Sir use differentiation it can solve fast
@hypertejas.p4110
Ай бұрын
Sir in second method differentiation is wrong... You forgot 2 in denominator in 1/√2+x.... But answer is still right how?
@vdisonair3668
Ай бұрын
Yeah….because 2 comes in the denominator but the lcm would be the same and also denominator is playing no role for giving critical points
@LaughingKing40
Ай бұрын
Sir wavy curve mhi laga sakte kya
@Arpd94
3 ай бұрын
Sir aap maths ke eduniti ban jao 😂
@ravisankar8259
3 ай бұрын
How did you arrive at conclusion, sir, that the minimum is only at -2 or 3?
@MaheshKumar-lx1ku
3 ай бұрын
😂😂😂 because function is defined between-2 and 3 only
@MaheshKumar-lx1ku
3 ай бұрын
In Which standard u are
@goodvibez9415
Ай бұрын
Function has the addition of two square roots Square roots can never be negative so therefore we took 3 - x >_ 0 2 + x >_ 0 as the square root can be zero hence functioned is defined between -2 and 3 Im a 11th grader forgive me for any wrong logic
@adityasarraf3843
Ай бұрын
Sir by using AM GM inequality the minima is coming as root 10 what's wrong here?
@sanjeevsir29077
Ай бұрын
@@adityasarraf3843 please keep in mind domain also
@adityasarraf3843
Ай бұрын
@@sanjeevsir29077 sir the minima is coming on x=1/2 (using AM GM inequality) which is right well in domain)
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