Just a heads up, this formula works for molecules that have the following: 1. Molecules with only 1 central atom 2. Molecules that do not contain hydrogen.
@nicholasmoniz7758
4 жыл бұрын
Too anyone who is complaining about how the formula doesn't work with hydrogen, change 8n to 2n in the formula. If the molecule has hydrogen and another element just do (Ve + 8n + 2m)/2 where n is the number of atoms sorrounding the center atom(excluding hydrogen) and m is the number of hydrogen atoms sorrounding the atom.
@commenter8640
2 жыл бұрын
This actually worked for NH3 man ... thank you so much. Why doesn't this comment have more likes 😅
@sifatenoorsahiba1484
2 жыл бұрын
upvoting this comment
@CS-et4fs
2 жыл бұрын
do u mean Ve - 8n - 2m?
@luce9264
Жыл бұрын
He even explained it at 3:57, do people not pay attention to his videos or something?
@joesalter31
Жыл бұрын
would this be formula be applicable to atoms that have two or more central atoms?
@saptaksarkar30468
3 күн бұрын
Holy shit dude. I was struggling so much with VSEPR just because I was having a hard time finding the no. of Lone pairs. Your formula works like magic dude ! It's so easy now to find the no. of Lone pairs ! Thank you
@mx.moonmoo
2 жыл бұрын
Dude you have carried me through senior maths and science thank you 💗🙏
@georgesadler7830
Ай бұрын
Professor Organic Chemistry Tutor, thank you for a short explanation on How to Calculate the number of Lone Pairs using a Formula in AP/General Chemistry. Although I took General Chemistry many years ago , this is the first time I can remember seeing a formula used to calculate lone pairs in Modern Chemistry. This is an error free video/lecture on KZitem TV with the Organic Chemistry Tutor.
@ugliestbagel9966
6 жыл бұрын
I think the formula changes according to the orbital structure so for NH3, for example, the formula in the video would be ((5+3(1))-8(3))/2 = -8 but that wouldn't make any sense so what I do is replace the 8(n) with 2(n) due to the 2 electrons in the s orbital of hydrogen. so the formula is ((5+3(1))-2(3))/2 = 1 and that would mean 1 electron lone pair which is correct. I know this doesn't sound very scientific but I tried it and it works every time even for CH4 where there are 0 lone pairs and HF where there are 3 lone pairs of fluorine.
@funmoments3940
6 жыл бұрын
No man it doesn't work with HCN unfortunately. It says 3 if I work with your strategy, bu the actual is zero.
@vivaansharmavlogs6843
6 жыл бұрын
.
@vivaansharmavlogs6843
6 жыл бұрын
UgliestBagel m
@jennylynosorio556
6 жыл бұрын
coz the sample problems and that formula only works for a molecule with 2 different elements! i supposed!
@lnfernalGamingYT
4 жыл бұрын
@@jennylynosorio556 try NH3 IT HAS TWO DIFFERENT ELEMENTS
@theultimatekaiokenkiller17
3 жыл бұрын
Oh my god!!!! This helped a lot.....thank you
@jenniferamankwah5353
5 жыл бұрын
Thank you ... organic chemistry tutor.Your videos are always helpful...I recommend organic chemistry tutor's videos to every chemistry beginner.
@VictoriaSarfo-tl9zz
11 ай бұрын
You are the best tutor on KZitem
@danagage7009
3 жыл бұрын
Your videos are super clear and helpful. Anytime I need help with something I see if you have a video about it. Keep up the good work! Thank you!
@123dpr
2 жыл бұрын
This is sooo simple..woww!!! I understood soooo well.. thankyou sir😃😃😃
@Ali-g6d
8 ай бұрын
This formula works bro I've calculated for XeOF4, XeO2F2, XeF3+,and so many other molecules
I have no word to express that how happy I am right now thanks
@sachinkushwaha4233
5 ай бұрын
Love from India ❤ It is very helpful sir ji thanks ❤️❤️❤️
@rahaeefalotibi1119
5 жыл бұрын
Thank you very much . Your videos are helpful 💓
@user-ho9dh5jj1o
3 жыл бұрын
I think Xe has more electrons than it should have. In your example it was has, 2 (LP)+2+2+2+2 = 12 electrons !!!! Please if there is something wrong from my side let me know.. Thanks a lot this video was helpful.
@elijahtenywa3063
2 ай бұрын
Great video. I was getting lost on the valencies and then later figured out that you used the outer electrons in the octate of the surrounding atoms. Coz the valency of oxygen is 2 and you used 6 for example.
@felixkaite8985
6 жыл бұрын
great work!!!!!!!!!!!!!!!!! i have learnt so much.
@SaifAliShugan
2 жыл бұрын
thanks a lot for the vid, any chacne of uploading an easy way to calculate the bond pair? I need it most bro
@richarc2307
6 жыл бұрын
I need more examples idk how this formula would work for CH4 NH3 HF etc
@jennylynosorio556
6 жыл бұрын
it should be Ve-2(n)/2. It is given 2 as a constant since the terminal atoms attached to the centrAL atom Hydrogen cannot have more than 2 electrons on its outermost shell!
@yeny7194
5 жыл бұрын
@@jennylynosorio556 Ohhhhhh so this I can use for like H2O? I was like OMG this is not working for CH4 and NH3 and H2O!! ahhhh thank you so much for clarifying
@hillz00
4 жыл бұрын
You cannot use this formula if there are Hydrogens in your molecule
@Spectrojamz
4 жыл бұрын
@@hillz00 Yeah... The constant you put on "n" depends on the max number of electrons the element can have in its valence shell. Hydrogen cannot have an octet structure so the formula Ve-8n/2 will not work Hydrogen can only attain a duplet structure... You'll use Ve-2n/2 rather... Hope this helps?
@medicaleinstein8268
3 жыл бұрын
Yeah it did ... I was so confused about H2O
@stutishreepandey49
3 жыл бұрын
Try to use this formula on NH3
@controlmold
3 жыл бұрын
I was trying on it too but got 1.5?
@ShahG-hc1cy
3 жыл бұрын
It not worked for nh3
@user-rv9yt2gq6c
Жыл бұрын
CH3 alsoooo
@user-np8ed8tn5b
6 ай бұрын
Thank you so much for the explanation! Would this be still valid to ones like NO3?
@harineepriya
3 жыл бұрын
Thank you very much 💕
@navyasemwal6231
7 ай бұрын
Thank you , great explanation:)
@ericwuluglayjr8446
3 жыл бұрын
U're very great ....... I wish I live somewhere round your HOUSE.
@TypicalSullyEditz
3 ай бұрын
Erm ☠️
@elyriawilliams6767
2 жыл бұрын
🙏 I thought I would Never get this!
@phoebewang4199
4 жыл бұрын
this formula doesn't work for all molecules, you should indicate what types of a compound suit for.
@ahemkhanna2949
3 жыл бұрын
Then what's going to be for H2O?
@vuruvwzlksz
6 жыл бұрын
thank you!!!
@abelbelete2398
4 жыл бұрын
amazing formula for expanded octet
@savageedits8690
2 ай бұрын
What about BrF3 ??
@juansamudio1171
5 жыл бұрын
Wait but this doesn’t work for hydrogen
@ashmitmishra5948
3 жыл бұрын
Hydrogen is not a molecule ok
@PranavRKumar
3 жыл бұрын
@@ashmitmishra5948 ohk if not hydrogen, it doesn't work for H20...
@ap-ni3jc
3 жыл бұрын
@@PranavRKumar it will not work for molecules with hydrogen because hydrogen does not form octet
@shifakhan1793
3 жыл бұрын
For hydrogen = valence electro - 2(n) /2....
@alysmith7825
2 жыл бұрын
One more limitation beside hydrogen presence: it only works for molecules with one central atom (meaning all the other atoms are bonded to the central one)
@ozandenizozdemir7706
8 ай бұрын
you must be a god for making this video thx to your steel balls ❤❤❤
@dineshmahara5731
4 жыл бұрын
For ions?? (Oh3)+
@shreyamurasing2492
4 ай бұрын
Sulphur has six valence electrons so then why does it form bonds with its five electrons only in SO2?
@victoriawang9726
2 жыл бұрын
Does this formula applies to all the structures or there is certain limitation for using this formula?
@w_ahida
2 жыл бұрын
Hi, not too sure but I think it works with all compounds except those with hydrogen in them. Well that’s what’s happened to me for the most part but I know it doesn’t work on ones with hydrogen for sure
@dkwhattowrite.
Жыл бұрын
@@w_ahidaI know that I am late but you should change the 8n to 2n for compounds containg hydrogen
@nankingafusta1831
3 жыл бұрын
Oh my this is so good
@NothingSpecial-7
3 жыл бұрын
You are legend
@xtronic5289
2 жыл бұрын
Hi could you help me understand how you can know if it has a double bond or not like you know for oxygen
@ramonaalbitar-dw5mo
Жыл бұрын
do you teach private online sessions math and chemistry ?
@noblealaiyus278
4 жыл бұрын
Thank you
@rohils7195
3 жыл бұрын
It does not work with compounds containing H (hydrogen )
@marcib6767
3 жыл бұрын
Thanks for saying this because I was trying to use this calculation for H2O and wound up with -4; and I’m here like what is wrong why doesn’t it work🥴😩😩😩. I will have to keep this in mind
@SeanyKrabs
3 жыл бұрын
This is why I have a 25 in Chemistry
@debabrataroy345
3 жыл бұрын
what you mean ?
@sebastiancurry3714
3 жыл бұрын
@@debabrataroy345 he had a 25 percent in chemistry lol thats what he means. Some people are slower learners cant blame them
@Dash-Humble
2 жыл бұрын
Why is sulphur the center atom?
@mdmujib5965
2 ай бұрын
What about bonds with more than one central atom? It doesn't works for them.
@user-ew3pd6no8v
4 жыл бұрын
5:27 Why we didnt place(n) by 4 why you filled it by 3 only where is the atom of N?
@sabihamukrim5119
4 жыл бұрын
I think it's cuse nitrogen is the central atom . We have to take the number of those attached to the central atom.
@advaitzambre6549
3 жыл бұрын
@@sabihamukrim5119 YEP U RIGHT BRO, [IDK WHY I AM MSGGING TO YEAR OLD COMMENT]
@nelsonatavwoda4330
2 жыл бұрын
Yea cool formulae. But can I get the formulae that works for organic compounds to determine the lone pair. It does not work for organic compound especially when the centre atom is not one.
@nissanzenkiboy
Жыл бұрын
I hate chemistry with a passion.
@RakeshAdak-hy2mp
4 ай бұрын
Uss
@ayinlabukola4576
4 ай бұрын
Why it's damn interesting
@elijahtenywa3063
2 ай бұрын
😂 😂 😂 😂 that nice perfume you use is because of chemistry.
@kanijfatemakoli1347
6 ай бұрын
Thanks 😊
@chrisprilloisebola
4 жыл бұрын
Doesn't work for hydrogens or duets
@Leonestudy12
25 күн бұрын
i don't understand when you said that you want to put one lone pair but you put two can you please explain??
@Leonestudy12
25 күн бұрын
I am not sure but i think i understand those 1 lone pair mean you add 2 electrons on the sulfur atom
@yeny7194
5 жыл бұрын
Why doesn't this work for the H2O molecule? I got -4. which I'm assuming is 4 lone pairs but H2O molecule only has 2 lone pairs
@phoebewang4199
4 жыл бұрын
he talks about the covalent bond in this video only. H2O is hydrogen bond, some other compounds start with H should be acids so that is why this formula doesn't work for all types of molecules.
@hemasrivarshini1187
Жыл бұрын
Thank uu ❤️❤️😭
@cartisabrown6301
6 жыл бұрын
great work by a great teacher
@SM-qn7sr
Жыл бұрын
Regarding Br3-, is it possible to form double bonds with the two bromine atoms? Or would that be too many bonds?
@SM-qn7sr
Жыл бұрын
@@Childish_Eli what exactly is wrong with you?
@giorgioscolari9959
Жыл бұрын
No, it's just... Not like this. Every atom that bonds to another has only 1 possible configuration, unless specific circumstances, and there's physics and chemical reasons for that. However, this may not be too obvious for you, so there you are. If you got Br3-, there's only one configuration possible. The bonds are determinated by the valence atoms. So, here you got 2 atoms of Br with 7 valnece electrons and anothrr ion with 6 valence electrons. Keep in mind that every atom has to reach, usually, the 8 electrons configuration. Covalent bonds, as the ones that bromine creates, make sure that an atom shares one, two or three electrons with another. In this case, the central atom shares his 2 electrons with the ones that are on the side, meanwhile the ones on the side shares their electrons to the central atom. So we got 8 electrons per atom, with a total of 4 electrons shared. So yeah, when an atom shares an electron to another, it forms one single bond. If you got two electrons shared, you got a double bond. Same with the triple bond. The central molecule is determinated by the elctronegativity. The less electronegative molecule (with less atoms), goes in to the center. In this case, the central atom is the bromine atom with 1 electron in less. I hope you understood. Have a great day
@Theoyinkansola01
8 ай бұрын
What about the bond pair?
@dev56raj51
5 жыл бұрын
Pf5 solution nikal kr btana step vise
@ZidanGaredew-ni5hz
7 ай бұрын
thanks 🙏🙏🙏🙏🙏
@vuruvwzlksz
6 жыл бұрын
i get a negative 3 for HCN
@Sara-bg8yt
5 жыл бұрын
H = 1 ve- C = 4 ve- N = 5 ve- 1 + 4 + 5 = 10 ve- LP = (ve - 8n)/2 = (10 - 8(2))/2 = 10 - 8 (multiply by 2 and divide by 2 cancel) = 2 LP
@user-kc4tj4um7f
5 жыл бұрын
@@Sara-bg8yt what a Idiot calculation
@gtALIEN
5 жыл бұрын
@@Sara-bg8yt dude when I divided by 2 the 10 should've become 5...simple math brother
@ShivamYadav-gj1de
3 жыл бұрын
What we can do in case of methane
@MJ-zv1wo
3 жыл бұрын
If we use this formula to calculate the lone pairs for NH3 , it won't be right. lone pairs =( 8 - 8)/ 2= 0 . infact, the strructure have 2 lone pairs. Please help to explain
@cricup3835
Жыл бұрын
No it has 1 lone pair
@asemmohamed36
4 жыл бұрын
It doesn't work on all compounds. For example, H2O the number of lone pairs using this formula is negative 4 !!!
@Abby_e
4 жыл бұрын
in lone pair formula use 2 instead of 8 you will get the answer.
@mayaharari7709
2 жыл бұрын
What if there are a few central atoms?
@MarjaanAmin
16 сағат бұрын
It doesn't work on ccl4
@kushagrakolte4610
5 жыл бұрын
This formula doesn't work for Every compound Plz say the proof
@MarjaanAmin
16 сағат бұрын
Just it's for only elements doesn't attached with hydrogen and molecules with only one central atom.
@venicetan7173
4 жыл бұрын
can use for C2O ??
@portersspeedshop2779
2 жыл бұрын
Thank you so much love I wish I had money to give you. I will make a statue in your honor and remember you to my dying breath.
@petertan9156
5 жыл бұрын
Try: Lone Pairs=(Number of Valence electrons - Nearest multiple of 8 to the number of valence electrons) divided by 2. For Example: - NH3. ((3+5)- 8(The nearest multiple of 8 to Ve)) divided by 2 =8-8=0 - S02 (see answer at 2:10) ((6+2(6))- 16(The nearest multiple of 8 to Ve)) divided by 2=(18-16) divided by 2 = 2/1 =1 Works for every one i have tried so far
@addy1154
5 жыл бұрын
Mate nh3 has 1 lone pair
@HaniBouhraoua09
2 жыл бұрын
thnx
@mercyangel4626
2 жыл бұрын
How to do with H3O
@lnfernalGamingYT
4 жыл бұрын
why would anyone dislike this
@sabnurmolla8338
3 жыл бұрын
Sir N2o , doesn't match the formula
@comfortumoren5661
3 жыл бұрын
This was helpful but I discovered that it doesn't work for some compounds. Like CO, that is carbon monoxide
@Denji-xc3cy
3 жыл бұрын
Q - Bpe( single bonds or sigma bonds only) = Lpe Lpe can be used to make pi bonds until every atoms octet is completed and central atom is in maximum covalency . Fo eg CO Q - BPE = 10 -2 =8=LPE :C-O ::: Where Q = V e of all atom +(-ve charge on molecule if any ) - ( + charge on molecule if any)
@MzwandileHarmans
8 ай бұрын
And what would be number of lone pairs for NH3. Am getting -8
@TheOrganicChemistryTutor
8 ай бұрын
That formula works for molecules that don't contain hydrogen atoms since hydrogen can only hold 2 electrons and not 8. For molecules that contain all outer hydrogen atoms with the exception of the central atom, the formula needs to change from (Ve - 8n)/2 to (Ve - 2n)/2. N = 5, H = 1 Ve = N + 3H = 5 + 3(1) = 8 n = 3 for the 3 outer hydrogen atoms (Ve - 2n)/2 = (8 - 2*3)/2 = (8 - 6)/2 = 2/2 = 1 This make sense since Nitrogen only has 1 valence electron
@MzwandileHarmans
8 ай бұрын
@@TheOrganicChemistryTutor thank you 🙏
@TwahirMohammed-n9f
10 ай бұрын
Doesn't work on hydronium ion
@desmondvishala1657
2 жыл бұрын
please incease your volume
@ruvarashechiweshe3110
2 жыл бұрын
Does this formula apply to ions
@TheOrganicChemistryTutor
8 ай бұрын
Yes, if you adjust the number of valence electrons based on the charge of the ion.
@tik4toks260
2 жыл бұрын
But how do you find lone pairs for something like N2H2?
@TheOrganicChemistryTutor
8 ай бұрын
It won't work for that molecule since it has more than 1 central atom.
@brandondurland9712
4 жыл бұрын
Uh yeah this formula definitely does not work. A for effort though.
@HiezeHieda
6 жыл бұрын
i hope u r my lecture. 😄
@yeah-qi2nx
Жыл бұрын
What if its NH2CONH2(Urea)?
@TheOrganicChemistryTutor
8 ай бұрын
The formula works well for molecules with 1 central atom. For molecules with multiple central atoms, it's a different story.
@dammybankz6398
2 жыл бұрын
Somebody help me do the lone pair of CO
@b0lie
Жыл бұрын
What does that n mean ?
@asher6379
Жыл бұрын
No of atoms attached
@logann6858
4 жыл бұрын
Ur formula doesn't work on many molecules
@Tag_Gw
10 ай бұрын
Is that true?
@-neda-n
9 ай бұрын
@@Tag_Gwthere are exceptions when Hydrogen is present, which the chemistry tutor mentioned
@rujalbapat1055
8 ай бұрын
If hydrogen is there then instead of 8n use 2n
@DanteGabriel-lx9bq
7 ай бұрын
Hydrogen can only hold 2 electrons in its valance shell! Not 8, so don't divide by 8 when Hydrogen is present.
@josephtsegen2076
4 жыл бұрын
It works even for organic compounds
@yaotako5352
6 жыл бұрын
Do all have lone pairs?
@padmajakollu3762
3 жыл бұрын
No
@mwansakayula34
4 жыл бұрын
The formula couldn’t work for H2O and HCN , why
@rohils7195
3 жыл бұрын
It does not work for molecules having hydrogen in it . He himself tells this in this video👇 kzitem.info/news/bejne/mnhrrHuGfamJkno
@cupcake9079
3 жыл бұрын
This doesn't works for ammonia the answer comes negative
@manivardhan6094
5 жыл бұрын
It is not working for HClO3 and others compound
@lnfernalGamingYT
4 жыл бұрын
I think it's only used for diatomic molecules
@yaaliniii
4 жыл бұрын
What about XEOF4
@padmajakollu3762
3 жыл бұрын
I got 1lonepair for that.
@durojaiyedaniel9914
10 ай бұрын
It doesn't work for BeCl2
@TheOrganicChemistryTutor
8 ай бұрын
For BeCl2, Be = 2, Cl = 7. Ve = Be + 2Cl = 2 + 2(7) = 16 n = 2 for the 2 outer chlorine atoms (Ve - 8n)/2 = (16 - 8*2)/2 = (16-16)/2 = 0/2 = 0 This make sense since BeCl2 doesn't have any lone pairs on the central Be atom.
@cartisabrown6301
6 жыл бұрын
i have learnt the structure of SO2
@amberfatima6159
5 жыл бұрын
for water.....this formula is wrong to calculate the lone pairs
@mattk02981
4 жыл бұрын
why doesnt school fkn teach me this
@arkashumm
10 ай бұрын
it doesnt work for h2o
@TheOrganicChemistryTutor
8 ай бұрын
See my response to the comment below.
@nochute
4 жыл бұрын
Hey, you made a little mistake with the SO2 example. Each oxygen atom has a double bond with the sulfur atom, otherwise it doesn't make sense
@Denji-xc3cy
3 жыл бұрын
No it's right
@nochute
3 жыл бұрын
@@Denji-xc3cy Good to know
@Denji-xc3cy
3 жыл бұрын
Lewis dot structure is the easiest topic in chemical bonding lol
@pfeliciano4062
5 жыл бұрын
What about N2F2? You would get 2 Lp as your answer but with this method it gives you 0 LP? Why is that?
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