My neighbours called police because i was loudly watching videos of Dr. Peyam's Show . The police arrested them.
@m.a.4794
5 жыл бұрын
hahahaha
@hofstra7591
3 жыл бұрын
Wow thank you for the explanation, you are the first person who I watched that actually explained it simply and thoroughly.
@SmileyHuN
5 жыл бұрын
Also a linear combination goes to a linear combination, so it can be done with only one step, namely: f(ax + by) = af(x) + bf(y). ^_^
@sugarfrosted2005
5 жыл бұрын
You can even drop that b.
@gigrais
5 жыл бұрын
Yeah, drop the b.
@georgiasonter1842
5 жыл бұрын
Your videos are so helpful, please keep making Linear Algebra videos! :)
@wolframalpha8634
5 жыл бұрын
Omg I was just now watching 3b1b video on linear transformations and your video popped out of no where!! And I got to watch bprp's videos too!!
@jstroner
5 жыл бұрын
Best linear Transformation explanation on KZitem!!! Thank you Dr. Peyam. Genius
@aiupal7490
3 жыл бұрын
thank youu so much, after watching this video I finally can understand. This is the best explanation video about linear transformations I ever watched on youtube
@aniekanumoren6088
3 жыл бұрын
I which I could like this video twice
@dariosilva85
Жыл бұрын
Dr. Peyam, could you please make a new series about operators, which are widely used in Quantum Mechanics? You are very good at explaining complicated and abstract subjects. I am very curious to see where you would classify the topic. Does it belong in linear algebra, metric spaces, vector spaces etc.? It would be awesome.
@frozenmoon998
5 жыл бұрын
Such a colourful transformation. Made my day. You may though want a lesson from bprp in regard to the colour pen switch :).
@mamadetaslimtorabally7363
Жыл бұрын
It rains in Southern California. I like your explanation and great unique sense of humour. Watching T.V. Well T of vector V.
@weinihao3632
5 жыл бұрын
TV time with T and U is best!
@jorgejoeinfantesantacruz4362
5 жыл бұрын
Que bonito Es como estar viendo los simpson pero en una pizarra y ya no hay un Bart, solamente hay un buen profe escribiendo
@mathemitnawid
Жыл бұрын
0:20 namely 😊. I think in German we also use “namely” - nämlich, but not that often
@alissa.abdlrhm
Жыл бұрын
Thanks !
@solvemathematicsproblem947
3 жыл бұрын
Excellent
@vanessakitty8867
5 жыл бұрын
Can't wait for some more. The matrix forms of linear transformations will be nice.
@PackSciences
5 жыл бұрын
I am not sure if that's allowed, but when I was asked to prove something is a linear transformation, I show that T(lambda * x + mu * y) = lambda T(x) + mu T(y) with lambda and mu constants. So you prove both additivité and multiplication par un scalaire. I know some people even shorten it to T(lambda*x + y) = lambda T(x) + T(y). Are there cases in which you can't do that directly? Because it seems so much shorter to do both at once.
@drpeyam
5 жыл бұрын
You can do that, it’s just conceptually it’s better to do it separately
@chiramitterbacher4077
Жыл бұрын
Thank you really much !
@knesskhrawbormarbaniang983
3 жыл бұрын
Best explaination ever......
@KidNamedVashin
5 жыл бұрын
I pity the fool who had an exam about this
@brunogreco1831
5 жыл бұрын
Can you upload a video of these exercise please. T:R^3 to R^3 the linear transformation give by T (x1,x2,x3)=(3x1+x3, x1+x2, -x1). Define if it s possible a linear transformation T1:R^3 a R^3 such as T (T1 (0,2,1))= (-1,1,3); T1 (0,1,0)=(1,0,1) and Nu (T1)≠{0}.
5 жыл бұрын
Wow, BluePenRedPenGreenPen :-O
@MrRyanroberson1
5 жыл бұрын
Is it possible to do something like express x^2 + 4x + 6 +5y + 2y^2 + 3xy as some kind of matrix operation that starts with [(x),(y)]*? What options are there, if not, to do things like this? *I'm trying a new matrix notation where every row gets its own () when typed out, so in this case it represents a vertical vector.
@drpeyam
5 жыл бұрын
Yes, see the video on quadratic forms
@aleksanderaksenov1363
3 жыл бұрын
But why linear tranaformation has exect correspondence to tensor(1,1)
@mustafahasan5878
5 жыл бұрын
Can you tell me please what's the derivative of X! ???
@Goku17yen
5 жыл бұрын
1
@Goku17yen
5 жыл бұрын
oops, im stupid i thouhght that was just an exclamation point not a factorial lol. You cant really fiure it out with elementry functions, but you can extend the definition of a factorial into the gamma function, and u can just take derivatives from there, Γ(x)=(x−1)!, where Γ(x)=∫, from 0 to inf, of x^te^−tdt
@mustafahasan5878
5 жыл бұрын
Yeah , I've tried it recently.....
@jaydeeppatel5238
4 жыл бұрын
Can you drag your camera atleast at second part of your bord.... because we cant see what is written on your right hand side...lol
@jaydeeppatel5238
4 жыл бұрын
But your vidio is really helpful... I want to advise you to add more funny dialogue in your vidio to attract more students 🔥🔥🔥
@garrytalaroc
5 жыл бұрын
I was having a linear algebra class too. We we're on the topic Invariance. I was having a hard time understanding it. Do you have your version of teaching Invariance?
@drpeyam
5 жыл бұрын
Probably in 3 months or so
@davidwright8432
5 жыл бұрын
Thanks,,Dr P! Very helpful, as usual. Slight problem with the viewing angle, tho, for the right half of the whiteboard. You're using a wide angle camera, so what you write farthest from the camera is a bit to compressed for easy reading. maybe position the camera so it's equidistant from L & R sides of the whiteboard? You still get away without having someone moving the camerato track you! Your handwriting is fine; just the viewing angle causes difficulty..
@drpeyam
5 жыл бұрын
I’ve tried that, but then I cover up what I write. I’m experimenting with this a bit
@ElifArslan-l9g
2 жыл бұрын
thanks a lot
@MrRyanroberson1
5 жыл бұрын
Isn't the second property you mentioned just the same as saying "a number can be added and also it can be multiplied" except multiplication can be proven through addition, right? T(2u) = T(u+u) = T(u)+T(u) = 2T(u), and so on
@drpeyam
5 жыл бұрын
What about T(sqrt(2)u) ?
@MrRyanroberson1
5 жыл бұрын
@@drpeyam provable by a summation series, sum 1+.4+.02... Fractions can be proven to obey the property that for 10U = K, that 10T(U) = T(10U) = T(K), and therefore T(0.1)=T(1)/10
@drpeyam
5 жыл бұрын
For Rn it’s fine, but in general you don’t have limits of vectors
@MrRyanroberson1
5 жыл бұрын
@@drpeyam this does lead into another idea I had: matrices with matrices as elements. By all of the checks, you can have another matrix of matrices and apply them together all the same (vectors being 1-wide matrices)
@ELECTRONICAFISICA-UIB-
2 жыл бұрын
Anyone can put an example of function such that T(A+B)=T(A)+T(B), but T(aB) is not equal to aT(B) ?
@faithamani4187
2 жыл бұрын
Thank you sooo much
@doria_bolognese
5 жыл бұрын
Will Dr. Peyam make videos of second course level linear algebra?✌🏻
@drpeyam
5 жыл бұрын
Yeah, in 3 months or so!
@neilgerace355
5 жыл бұрын
Who is Steve? :)
@joebrinson5040
5 жыл бұрын
Good one, Dr. Peyam
@drpeyam
5 жыл бұрын
:)
@GhostyOcean
5 жыл бұрын
Can't wait for you to get to change of basis because that's what still bothers me
@djJhaybee23
5 жыл бұрын
buti pa to yung teacher namin pucha hindi marunong magexplain
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