@physicsmathwarrior1998RFA
this video is about
maximum height acheived by object thrown with speed v at angle to horizantal is h=v^2sin(theta)^2/2g v=10,12,14,16,18,20 theta=50,60,70,80
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Негізгі бет maximum height achieved by object is h=v^2sin(theta)^2/2g for v=10,12,14,16,18,20 theta=50,60,70,80
Пікірлер: 2