The MERSENNE PRIMES formula is part of the following formula 1. Let a, b, n be natural numbers with a>b - {[a^(a-b)]-[b^(a-b)]}/[(a-b)^2] is always a natural number. If {[a^(a-b)]-[b^(a-b)]}/[(a-b)^2] is prime then a-b is prime. If a-b is composite, then {[a^(a-b)]-[b^(a-b)]}/[(a-b)^2] is composite. - If [(a^n)-(b^n)]/(a-b) is prime, then n is prime. If n is composite then [(a^n)-(b^n)]/(a-b) is composite. 2. Let a, b, n be natural numbers where n is odd - With a+b being odd, {[a^(a+b)]+[b^(a+b)]}/[(a+b)^2] is always a natural number. If {[a^(a+b)]+[b^(a+b)]}/[(a+b)^2] is prime then a+b is prime. If a+b is composite then {[a^(a+b)]+[b^(a+b)]}/[(a+b)^2] is composite. - If [(a^n)+(b^n)]/(a+b) is prime, then n is prime. If n is composite, then [(a^n)+(b^n)]/(a+b) is composite.
@ubiss8487
3 жыл бұрын
Other than be a prime number, what other conditions must n satisfy in order for 2^n -1 to be prime ? ( as you stated at 2:44 )
@TheDicesayssix
3 жыл бұрын
15 is not prime.
@ProfessorDBehrman
2 жыл бұрын
Neither is 63. But he did not claim that 1, 3, 7, 15, 31, 63, 127 were all prime.
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