6:40 Only one 4 bit adder is sufficient ... bit[1:0] is added with 2'b00, so no adder is required, for the rest of bits, only one 4-bit adder is sufficient!!
@RakeshPrabhakara
11 ай бұрын
Simple answer is : We must analyze based on worst case scenario and worst case would be when A is 4'b1111 and the product would be 75 (1001011) which is 7-bits wide. two 4-bit adders can accommodate max of 8 bits which would make sense for outputting 1001011 including carry-forward. Even if A was 5-bits input, two 4-bit Adders would suffice since largest 5-bit number: 31 (5'11111) multiplied by 5 would give 155 or 8'b10011011. Seeing this, from an optimization point of view, we are hardly utilizing two 4-bit adders fully which is wastage of resource and at the same time, an inevitable option given the specification.
@Golukumar-vj6kk
Жыл бұрын
Nice explanation maaam ❤❤
@sohamdas7775
3 жыл бұрын
Great job brother
@mrigendrasingh4072
3 жыл бұрын
Wouldn't u need AND gates (or multipliers) too if u want to multiply 101 and A first then add them...........in the first question. But, extra gates or devices are not allowed here.
@amitmishra7003
3 жыл бұрын
Four 4 bit adder is required in cascade
@Golukumar-vj6kk
Жыл бұрын
In ring counter if you starts with 0001 then next three states will be 1000,0100,0010. Correct me if am wrong. If I am right then your written order for ring counter is mistakenly wrong.
@saileshsaileshreddy3347
2 жыл бұрын
Implement all Morris Manu even cc and seq circuits nothing more is there
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