This was a very good explanation, thanks to NPTEL and the professor.
@1400740
6 жыл бұрын
I have taken a no. of different XPS courses. But, this course taught me aspects that none of the previous courses did. Thank you.
@akshay6667
Жыл бұрын
Thank you once again 😀 First AES and now XPS really I am enjoying learning.
@ronachem.tricks3493
7 жыл бұрын
within an hour this lecture gave me a sufficient information about xpS
@mohamadalnarabiji2471
9 жыл бұрын
impreeeeeeeeeeesssssiiive ... well done prof... it is really soooooo informative lecture... thank you very much
@manueldeandavilla4959
8 жыл бұрын
When explaining background signal (around minute 25) he draws a graph of Number of photoelectrons vs Binding Energy. I think it should be Number of photoelectrons vs Kinetic Energy
@ubaidahmed3932
8 жыл бұрын
yeah he also confused me there.
@ubaidahmed3932
7 жыл бұрын
Actually binding energy is increasing on left side of the axis.
@dr.santoshkumarhaunsbhavi5518
4 жыл бұрын
Thank you Sir .. for wonderful information about XPS.
@ritage8955
4 жыл бұрын
around 39.28,the binding energy of 2p 1/2 is larger than 2p 3/2.. so you would better draw that the binding energy is increasing to the left. thank you for your video. really helped me a lot
@ShubhamBhoi-qj6dw
11 ай бұрын
Yup that part was little bit confusing
@gladvinv4988
6 жыл бұрын
For Ti +4 the binding energy is increasing, but you are saying it is decreasing. In XPS spectra the BE axis increases towards the left-hand side not the right hand
@pashasayyad7865
Жыл бұрын
Thank you for the wonderful explanation. Would you please let me know what the difference is between binding energy and work function? I would greatly appreciate it if you could clarify the difference.
@sudeepm6484
3 жыл бұрын
simply awesome!! well explained!!
@sivasankar6185
4 жыл бұрын
Good one and informative
@IndusDocumentary
9 жыл бұрын
its very interesting and in details.
@kinshoukchatterjee9430
5 жыл бұрын
Nicely explained
@mudavathravi5895
4 жыл бұрын
Respected Prof. Thank U Very much.
@hariharanchemistrynd8535
2 жыл бұрын
DEGENARCY IS 2J+1
@abhijnanchowdhuri3739
9 жыл бұрын
it helped me a lot.
@rui_santos
6 жыл бұрын
Shouldn't the electrons ejected from second ionizations also appear?
@Ivanbordacchini
8 жыл бұрын
not clear at all
@salilakumarsethy6254
5 жыл бұрын
Thank you Sir
@rahulaher4656
8 жыл бұрын
good for bassic idea !
@shayshama8899
4 жыл бұрын
It s hard to follow with such prononciation :(
@agarguest
8 жыл бұрын
How does this help me make better Chapati?
@Soumikraaay
9 жыл бұрын
that guy cannot teach at all
@1400740
6 жыл бұрын
Well, may be you can try then. Its easier to pass a judgement.
Пікірлер: 28