I wasn't good at math. That said, solving this equation was like driving from LA to San Francisco and ending up in Toronto, Canada.
@robertmcdonald3297
2 ай бұрын
6
@robertmcdonald3297
2 ай бұрын
The answer is 3
@StraightJacket5150
3 ай бұрын
Would love to see a everyday real world application of all the math I learned in high school and college. I am in IT and I have never used any of it in 30 years.
@VanOutloud
3 ай бұрын
I know what you mean. I used some in trade school but even that I've never used since.
@alyvarin1106
3 ай бұрын
@@VanOutloud Well, it was more like "a way of thinking"...
@Luke0193
3 ай бұрын
So true. I work in tax and accounting and am still waiting for that to happen
@diogostratega6002
2 ай бұрын
It's more to train your logical reasoning
@oahuhawaii2141
Ай бұрын
@@Luke0193: Compound interest rates use math for geometric series. You probably use a fancy built-in function done by a financial calculator or spreadsheet software.
@StephenC050
4 ай бұрын
That pen writes quite beautifully
@Daimler52
2 ай бұрын
Спасибо за познавательное видео уровнения такого уровня были когда поступал в технический университет в России в 1999 году. Тренировался считал десятками такие. Сейчас уже конечно подзабылись формулы, но с учебником думаю решил бы и сейчас.
@jropar13
Ай бұрын
I don't think that anyone who was worried about the music has the patience for the math. Just my opinion. Thank you so much. That was a lot of work. When you're buried in the math, anything else should fade to oblivion.
@DreamyCheshire-up9rf
4 ай бұрын
17/1/24 ( Wednesday ) 9.15 pm. Sorry, I failed maths in school. I thought it was a primary school algebra. Never thought that in order to find the value of X, you need to create a value of Y with log included, which I could not comprehend. I was wrong to think that the value of X was 3. Instead, after so many steps, the value of X was another equation.....no wonder I failed Maths.
@dak71889
3 ай бұрын
X value will be between 1 and 2. Simple solution. Lets take x value 1 then you will get 10 , let’s take x value as 2 now you will get 64 plus 4 that is 68 . 30 is between 10 and 64 so x value will be between 1 and 2. In India we get such questions as multiple choice answer questions and we get less time to solve.
@jim2376
5 ай бұрын
2^x = u. u^3 + u - 30 = 0. Factor: (u - 3)(u^2 + 3u + 10). Real solution u = 3. Quadratic on the second term for the two complex solutions. Back substitute. Messy problem.
@aimulus
3 ай бұрын
If complex numbers are allowed as solutions, then there are many more solutions, namely x=(log(3)+2*k*π*i)/log(2) and x=(log(10)/2+(i*(±atan(sqrt(31)/3)+(2*k-1)*π)))/log(2) for every integer k.
@marianneoelund2940
3 ай бұрын
Complex numbers are always allowed in my world. However, this isn't a very interesting expansion of the solution set, as it just says that running around a circle an integer number of times will return you to your starting point. Exp[(2×pi×k + c)×i] = Exp(c×i) for any integer k.
@oahuhawaii2141
Ай бұрын
Close, but no cigar. You mixed up the bases for the log functions, if the base for the log function isn't explicitly e. All the real components have a form of log(r)/log(2), regardless of base {such as 2, e, or 10}, as they all yield log₂(r). However, the imaginary component is log₂(e^(i*θ)), which is simplified as ln(e^(i*θ))/ln(2) = i*θ/ln(2) . You wrote the equivalent of i*θ/log(2), but this log function is traditionally base 10.
@aimulus
Ай бұрын
@@oahuhawaii2141Yes. The natural logarithm has to be taken, of course.
@iangray5407
2 ай бұрын
I'm amazed at how many people get an answer of 3 while completely misunderstanding the nature of logs or that x is a power. The right answer for the wrong reason is the wrong answer.
@alexxander6656
3 ай бұрын
This was definitely the long way in my opinion. I definitely forgot the other way tho. Too many things you just have to know like 2^3 is 8 and breaking 30 in to 27 and 3. M.
@MrHotlipsholohan
2 ай бұрын
You are a person with a good knowledge of the laws of indices , and logs, loved all this at secondary school 45 years ago bit have forgotton some of the rules so get lost near the end , lol, it pays to know these rules and got me out of many a problem in my engineering career , esp algebraic rules
@miguelorobitg2040
17 күн бұрын
One in top righ of eight, another one in top right of number two. I found two of them! Genius!
@troubledsole9104
3 ай бұрын
Knowing the theorems was essential to solving for X.
@praiseYAHalways
2 ай бұрын
soooo X = 3 as in 8x3 (24) plus 2x3(6) equals 30???? ....... at least that's how I did it in my head....took about 5 seconds maybe less 🤔 unless I'm reading the problem wrong...
@user-yl3rv2mk7z
3 ай бұрын
Тот случай, когда ответ, состоящий из логарифмов, оказался сложнее, чем изначальный пример.
@pmacgowan
3 ай бұрын
Well now I know why I just did applied maths, not pure !!, well done
@IrinaI5
6 күн бұрын
Как я любила их решать в школе!
@BarrieHughes
4 ай бұрын
You could apply the log formula right at the start.
@marianneoelund2940
3 ай бұрын
log(x + y) = ?
@luckyuliveHI
3 ай бұрын
Wow, I'm in finance and have used algebra in many situations. I don't think I'd have any use for this one. I wasn't expecting the solution to be this long.
@oahuhawaii2141
Ай бұрын
Howzit! Monthly mortgage computations are messy, and often require high-precision, iterative calculations and adjustments due rounding to the nearest cent or penny, and lots of decimal places for simple or compound interest. The calculations are messy because the idea value doesn't fit to a perfect dollars and cents value. This introduces errors that must be dealt with in an empirical manner. I wrote a program to find the monthly mortgage payment. It finds the idea value, then rounds that and recalculates every monthly balance so that the final payment for each year takes into account the accrued errors. The math we use in these videos don't have these empirical aspects, and are "cleaner" to calculate.
@luckyuliveHI
Ай бұрын
@@oahuhawaii2141 hmmm. sorry brah, have to disagree with "high-precision, iterative calculations". Any online loan calculator will get you close enough, +/- $50 or so. Excel's native loan ss will also do the job... entered the basic loan figures from mortgage brokers and I'm always within $10 of their proposed payment.
@paulssamuel
4 ай бұрын
let y=2^x then y^3 + y = 3^3 + 3 => y=3 => x = log3/log2
@jeffrobuck6338
4 ай бұрын
Simplification??
@MounikaMix
3 ай бұрын
Can we not directly apply log to the main equation and solve
@debkantadas7682
2 ай бұрын
But how can you get a 14 minutes video?
@iangray5407
2 ай бұрын
Simple answer: no. You'd still have to solve log(8^x+2^x) = log(30)
@stephenremo9200
5 ай бұрын
Like you can solve in 5 seconds in your head ... Or 10 pages of math
@ezrapotter4631
4 ай бұрын
Right off the bat, x
@oahuhawaii2141
Ай бұрын
What about a lower bound? Can x be negative or zero? Perhaps you can plot y = 8^x + 2^x - 30 to find the zero crossing(s).
@jcolivie
4 ай бұрын
Is this the easiest way? So I prefer to study integral calculus, differential calculus, theoretical physics because they are much easier than that (contains irony).
@KeithDCanada
3 ай бұрын
I'm sorry, but the answer is obviously "pizza"
@wizard105able
5 ай бұрын
At 4.28 where is 1 come from? I lost it there.
@wizard105able
5 ай бұрын
Ok nevermind after watching another video I understand it now
@cornerboytep
4 ай бұрын
Where? I am confused
@tomref4001
4 ай бұрын
I lost it there too-whats the explanation for the 1, or would be grateful for the other video URL please?@@wizard105able
@kintagrama
6 күн бұрын
@@cornerboytepWhen he converts y-3 into a 1
@hasanhumayun9600
2 ай бұрын
Make in math octal
@rusirius4370
3 күн бұрын
Bro lost me when he turned 8x into 23
@perry3928
3 ай бұрын
How about 8 Sq by 2, 2 Sq by 7. 16 +14 =30
@TaharOubagha
13 күн бұрын
Esuatt start oddition.after result free Master combine
@Gizmo9707
2 ай бұрын
That's the real solution, but there are also complex solutions
@oahuhawaii2141
Ай бұрын
Yes, an infinite number of them.
@siddharth.246
3 ай бұрын
Dude you could've just applied the remainder theorem when you had the equation y^3 + y = 30 or y^3 + y - 30 could only happen when y=3 and then applied the logs.
@irina4447
3 ай бұрын
(8 +2)*=30 10 *=30 30:10=3
@JakubSK
4 ай бұрын
Did it faster in my head without all the extra work.
@parandersson6541
4 ай бұрын
It took me 5 sec in the head
@The_Urchin13
3 ай бұрын
That's a claim you will never be able to prove,
@grqb_tg2478
4 ай бұрын
X = logaritmo de 3 en base 2
@TaharOubagha
13 күн бұрын
Its a nice sweetch lieder number for churche master.29+(9)XYC=23(8)+2(/29)__3#CH>133IPS=122+(N14)+S128
@DonaldKim33
3 ай бұрын
When I asked Chatgpt, x is about 1.65.
@user-yr6uk3qg7x
2 ай бұрын
Меня всегда интересовал вопрос : "а нахер это всё надо?: Километр бумаги истратили
@mauriziograndi1750
4 ай бұрын
X=1.585 by inspection without writing anything, a couple of approximations were enough in about 3 minutes. Anyway congrats for all your effort.
@oahuhawaii2141
Ай бұрын
x = log₂(3) = log(3)/log(2) ≈ 1.5849625007211561814537389439478 Note the "approximately equal to" symbol vs. the "equal to" symbol.
@wrippley103
2 ай бұрын
It's right there above 8 and 2.
@oahuhawaii2141
Ай бұрын
They raise those bases to the power of x.
@PapaPoohBear962
3 ай бұрын
It's simple. Take the x's out, and you get 10.
@ianclarke4945
3 ай бұрын
Y are you pointing at the rabbit? Because we are now going to follow it all the way down!
@neo3373
4 ай бұрын
Rien que la deuxième ligne...? C'est quoi tout ces a, m, etc....?
@misterenter-iz7rz
4 ай бұрын
2^x=3, x=log 3/log 2.
@romeowhiskey1146
2 ай бұрын
CoPilot answer below: CORRECT!
@neiladdison4457
3 ай бұрын
Totally didn't understand a line of that🤣
@flyingmonkey5787
3 ай бұрын
This seems like a very complicated way instead of using log. How many identities did the op use? This feels like an algebra 2 video
@johnnyo5993
3 ай бұрын
The judges say yes the answer is 3 they roll big joints too
@ronaldnoll3247
5 ай бұрын
OK... I don't have a pure math degree. I'm not happy with the result, because X is a number and the result is still an equation. I'm really confused.
@FuriousMaximum
5 ай бұрын
Thats because (-3 +- sqrt(31)i) / 2 Cannot be solved, thus it can't be simplified.
@stephenremo9200
5 ай бұрын
Doing some quick math in my head the answer is just under 1.6.. So it probably doesn't have an answer really 1.55 isn't enough 1.6 is too much
@marianneoelund2940
3 ай бұрын
The result equation contains only constants, thus it is final, even if it appears messy.
@oahuhawaii2141
Ай бұрын
The expression on the right hand side can be evaluated, but it's an irrational number: x = log₂(3) = log(3)/log(2) ≈ 1.5849625007211561814537389439478
@phishmastermike
2 ай бұрын
Simple 8 plus 2 is 10 10 times 3 equals 30 so x equals 3 To check it 8 times 3 is 24 2 times 3 is 6 24 plus 6 is 30
@kintagrama
6 күн бұрын
Also a²+b²≠(a+b)²
@vincenthalas7055
4 ай бұрын
I have a solution for cake failing to rise.
@chestermarcol3831
2 ай бұрын
Why wouldnt it be: x= log10(30)? which is x=30
@ahmedberi
3 ай бұрын
Soruyu çözerken onluk log yerine ln de kullanılabilirdin daha şık estetik bir çözüm olurdu
@marcosindici5994
3 ай бұрын
Better than ASMR
@Lemb6
2 ай бұрын
Я не математик но (8*3 = 24) + (2*3 = 6) = 30, я не понял огромной формулы но ответ верно высчитал
@hijirikawa-chan7449
2 ай бұрын
Это студенческий пример, ты не вытянешь. Ты не отличаешь степень от произведения. И "x" равен не "три", а вот этому 7:03 Логарифм называется.
@Panya11001
3 ай бұрын
เก่งมาก😊
@jacekplacek8274
5 ай бұрын
y^3+y=30 3 is ok so (y-3)*Q=0 and then easy to the end
@kintagrama
6 күн бұрын
What?😊
@janetedossantoscardoso8444
4 ай бұрын
Muito bom
@MathEducation100M
3 ай бұрын
Nice trick
@hanisitsobarna4897
28 күн бұрын
tease with cross ... 🤞 😅
@MENSA.lady2
2 ай бұрын
Why make life hard. Let x=2 then it is obvious that x must have a fractional value somewhere between 1 and 2.
@johnballock9280
3 ай бұрын
Did I see a word 'simplification' , yet the final answer is ' not possible ' ....... Oh me, oh my... How dumb I am
@oahuhawaii2141
Ай бұрын
There are 3 principal solutions for x. One is real, which is shown, and two are complex conjugates, which were discarded. In truth, there are an infinite number of solutions, and all but one are complex numbers. 8^x + 2^x = 30 (2^x)^3 + 2^x - 30 = 0 Let y = 2^x: y^3 + y - 30 = 0 (y - 3)*(y² + 3*y + 10) = 0 y = 3, (-3 ± i*√31)/2 For y = 3: 2^x = 3 x = log₂(3) = log(3)/log(2) ≈ 1.5849625007211561814537389439478 --- Actually, e^(i*π*2*k) = 1, for integer k, so we can generalize: 2^x = 3*e^(i*π*2*k) ln(2^x) = ln(3*e^(i*π*2*k)) x*ln(2) = ln(3) + i*π*2*k x = (ln(3) + i*π*2*k)/ln(2) x = log₂(3) + i*π*2*k/ln(2), k integer For y = (-3 ± i*√31)/2: 2^x = (-3 ± i*√31)/2 = r*e^(i*θ) { polar form } r = √((-3)² + (√31)²)/2 = √10 θ = π*(2*k+1) ± atan(√31/3), k integer ln(2^x) = ln(r*e^(i*θ)) x*ln(2) = ln(r) + i*θ x = ln(r)/ln(2) + i*θ/ln(2) x = ln(√10)/ln(2) + i*[π*(2*k+1) ± atan(√31/3)]/ln(2) x = log₂(10)/2 + i*[π*(2*k+1) ± atan(√31/3)]/ln(2), k integer
@colinmccarthy7921
4 ай бұрын
There must have been at least 15 steps to follow to find the solution. If that is simplification,I am quite astounded. Surely there is another way.
@mauriziograndi1750
4 ай бұрын
Yes there is another way
@CamerondeGrey
3 ай бұрын
I have to watch an ad to see a math video?
@mdmu_vjogdand
2 ай бұрын
So, what is log 2(3) ???? Can't we have a straight answer in numbers??? 😋
@nickmacdx
2 ай бұрын
Off course its the long way. Thr algorithm pays by the hour
@kintagrama
6 күн бұрын
What?
@carlw
3 ай бұрын
I get it except for how (y-3) became 1 at 4:27
@marianneoelund2940
3 ай бұрын
(y - 3) is a common multiplier and is being factored out to the left. Reverse distributive law.
@carlw
3 ай бұрын
@@marianneoelund2940@marianneoelund2940 Thanks, I understand that, but no other (y-3) on the left is factored/cancelled. I get the 9+ 1 afterwards but.......
@marianneoelund2940
3 ай бұрын
@@carlw It's straightforward distributive law: (y-3)*z + (y-3) = (y-3)*(z+1) Just factor out (y-3). Nothing is being canceled.
@carlw
3 ай бұрын
@@marianneoelund2940 Yes, it's been 40 years since doing that, forgot that. And to think I was doing integral calculus now forgetting stupid things like that. Thanks.
@danieloliveira5005
4 ай бұрын
Very good
@Ninjaknight81
3 ай бұрын
Find X? There's two of them on the right side of the eight and the two😂 always remember it's usually better to be a smartass than a dumbass😂
@oahuhawaii2141
Ай бұрын
After grading, you'll find another one covering your answer sheet.
@khurshidchaudhry2227
4 ай бұрын
It's very complicated maths can't get my head around. Doesn't follow any particular rule.
@j.carloshernandezpacheco142
3 ай бұрын
“Simplificación” 😂😂😂😂😂
@MacTaipan
3 ай бұрын
Hm. I think after substituting y, splitting 30 into 27+3 will only occur to you if you already know the solution.
@VaNSaNT85
3 ай бұрын
Not really, actually that simple trick is a tool you use lot in calculus
@rajinibommagani6314
3 ай бұрын
I have major doubt atleast 8 square chesina 64: 64+some number=30 How is it possible
@user-dj6ni3nm6y
2 ай бұрын
По-моему 30=27+3
@jeremyfogt6798
4 ай бұрын
Well you didn't get the -2 for not showing all your work.
@KenraMan-iw4ti
2 ай бұрын
I found two X’s. One next to the 8 and the other next to the 2..
@oahuhawaii2141
Ай бұрын
After grading, you'll have another one that's easier to find -- it covers your whole answer sheet.
@mirjanabjelajac8859
4 ай бұрын
X je 3 Čudna mi čuda ,prosto
@user-qu9iu7tc2b
3 ай бұрын
I wouldn’t take a math class from if you payed me.
@oahuhawaii2141
Ай бұрын
Perhaps a grammar class instead?
@ScorpioHR
2 ай бұрын
This is 3x longer as it should be. And I guess the goal was to make it over 10 minutes mark. At one point she wrote exactly the same line as the one before, not a single thing was changed... 4:00 mark So,yeah, it's just milking the algorithm at this point. Despicable!
@kintagrama
6 күн бұрын
What? Is not the same
@laurier3405
2 ай бұрын
I got a 99 on my algebra regions but couldn't add anything today. 😅
@troyjackson3164
4 ай бұрын
i would of been out of paper after that equation. Unless you are a scientist developing theories of flux capacitors majority of people will not need this kind of math.
@DeZ007
2 ай бұрын
Complicated version. Surely you don't expect to make math interesting with your extended method?
@user-dq3uh6ee5w
2 ай бұрын
Oтв. lg3/lg2.
@tomasmarquezhaynes3893
14 күн бұрын
30 entre 10 igual a 3
@kintagrama
6 күн бұрын
No tiene nada que ver ya que la X es en potencia, mentecate
@YouTickTech
2 ай бұрын
(2^x)+(8^x) +(7^x) =30 what is x
@ryanchiang9587
5 ай бұрын
i don;t know...
@albertabashev9563
9 күн бұрын
5 seconds
@Z-Bart
2 ай бұрын
X = 2.5
@thomascuddy6439
4 ай бұрын
Answer is 2
@samirraydan1712
4 ай бұрын
please. do quadratic (x-7) =3, tks
@marianneoelund2940
3 ай бұрын
Where do you want the square? It's missing from your expression.
@Abram_Israel_4235
4 ай бұрын
5:40 А зачем так сложно? Если 2^x=3. То x=log2(3). Это следует из определения логарифма. P. S Я не пользовался логарифмами больше 20 лет. 😅
@tz8811
4 ай бұрын
Вручную, подобрал сразу. Чего вола катает...
@user-fk5zn3lv3h
3 ай бұрын
Тоже хотел написать. Волосы дыбом от таких "полезных" манипуляций.
@_-Yan-_
3 ай бұрын
@@tz8811 сразу видно что 3=x про логорифмы уже не помню, с этим перегнул!)
@lizwirtz5968
3 ай бұрын
Is that supposed to be a 'simplification'? How does 'y' come into an equation that has no 'y' to start with?
@robbie330
2 ай бұрын
The y is only a symbol, just like x. It’s easier to work with one variable (y) than to work with 2^x.
@lizwirtz5968
2 ай бұрын
@@robbie330 what is 2 ^?
@josecabrera6923
Ай бұрын
3
@kintagrama
6 күн бұрын
?
@twinmomsurvival5744
3 ай бұрын
X equals 3, did it it 15 seconds. Love being a math geek :)
@marianneoelund2940
3 ай бұрын
I think you meant 2 raised to the power X is 3. But you missed the complex valued solutions.
@Senectus
3 ай бұрын
I looked at the first page and intuitively made the same conclusions as @twinmomsurvival5744 can you explain how your answer is correct?
@marianneoelund2940
3 ай бұрын
@@Senectus The equation left side is 8 raised to the power of X plus 2 raised to the power of X. It is not 8 times X plus 2 times X. Read carefully. The X is superscript.
@iseeyou8781
3 ай бұрын
Nope.
@praiseYAHalways
2 ай бұрын
@@marianneoelund2940 oh, are you saying that is 8 to the power of x plus 2 to the power of x....is that how it is written?
@maurindenouden8245
4 ай бұрын
3x 8 = 24, 3x 2 = 6. 6+24 = 30
@pichenism
4 ай бұрын
8x3 + 2x3=30 ( value X is 3 )
@wargrunt42
3 ай бұрын
You would be correct if the question were 8x + 2x = 30 8(3) + 2(3) = 30 24 + 6 = 30 x = 3 That's not the question being asked here though, rather it's 8^x + 2^x = 30 Let's see what happens when we plug-in 3 8^(3) + 2^(3) = 30 512 + 8 = 30 X obviously does not equal 3 It's deceptively a much harder problem than it looks. The only thing I knew going into this was x > 1 8 + 2 = 10 x < 2. 64 + 4 = 68 After having watched this video, that's still pretty much all I know, so don't feel bad if this went over your head because I'm right there with ya.
@oahuhawaii2141
Ай бұрын
@@wargrunt42: Here's the full answer, including all the complex solutions. 8^x + 2^x = 30 (2^x)^3 + 2^x - 30 = 0 Let y = 2^x: y^3 + y - 30 = 0 (y - 3)*(y² + 3*y + 10) = 0 y = 3, (-3 ± i*√31)/2 For y = 3: 2^x = 3 x = log₂(3) = log(3)/log(2) ≈ 1.5849625007211561814537389439478 Actually, e^(i*π*2*k) = 1, for integer k, so we can generalize: 2^x = 3*e^(i*π*2*k) ln(2^x) = ln(3*e^(i*π*2*k)) x*ln(2) = ln(3) + i*π*2*k x = (ln(3) + i*π*2*k)/ln(2) x = log₂(3) + i*π*2*k/ln(2), k integer For y = (-3 ± i*√31)/2: 2^x = (-3 ± i*√31)/2 = r*e^(i*θ) { polar form } r = √((-3)² + (√31)²)/2 = √10 θ = π*(2*k+1) ± atan(√31/3), k integer ln(2^x) = ln(r*e^(i*θ)) x*ln(2) = ln(r) + i*θ x = ln(r)/ln(2) + i*θ/ln(2) x = ln(√10)/ln(2) + i*[π*(2*k+1) ± atan(√31/3)]/ln(2) x = log₂(10)/2 + i*[π*(2*k+1) ± atan(√31/3)]/ln(2), k integer
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