Let yc = c1y1 + c2y2, be the homogeneous solution, and yp = u1y1 + u2y2 be the practical
solution. Using variation of parameters helps us to obtain the practical solution yp without
using the methods explaine
solve
𝑦′′−4𝑦′+4𝑦=(𝑥+1)𝑒^2𝑥
𝑦′′+𝑦=𝑠𝑒c(𝑥)𝑡𝑎𝑛(𝑥)
Негізгі бет Nonhomogeneous Diferential Equations -variation of parameter 𝑦′′−4𝑦′+4𝑦=(𝑥+1)𝑒^2𝑥,𝑦′′+𝑦=𝑠𝑒c(𝑥)𝑡𝑎𝑛(𝑥)
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