Thanks Wizako and Baskar ! This question was very easy for me.
@sparshaggarwal8806
Жыл бұрын
While solving the problem I considered 'x = -0.5' and this gives a yes if x
@Wizako
Жыл бұрын
Hi, Evaluating statement 2, When x = -0.5, we get a "No" as the answer to the given question. (-0.5)^3 is not greater than (-0.5)^2 i.e., (-0.125) is not greater than (+0.25)
@fortune7399
2 жыл бұрын
Genius
@Wizako
2 жыл бұрын
😄
@hriday7233
2 жыл бұрын
Love your teaching sir ♥️
@Wizako
2 жыл бұрын
Glad you liked it! 😄 Best Wishes for your GMAT Prep!
@samarthagarwal8982
2 жыл бұрын
Hi i solved this question by taking different yes and no cases and then my final answer came as c. While reading statement 2 i also considered negative cases that what if x is negative and by combining I got that x will fall in the range of numbers which are from 0 to 1. and on that bases I concluded that c is an answer.
@Wizako
2 жыл бұрын
Hi Samarth, Solving statement 2, all negative values (which are used to evaluate the question statement) will result in a definite NO as the answer to the given question. Request you to re-check once again. For example: x = (-2) (-2)^3 is not greater than (-2)^2
@fatimamalik4385
Жыл бұрын
@@Wizako What about when x = 0, then x^3 = x^2, so isn't statement 2 alone insufficient?
@elyungito8205
Жыл бұрын
Dear sir, when x=0 then x^2 = x^3 so second statement is not sufficient right ?
@Wizako
Жыл бұрын
Hi, When x = 0, we get a "No" as the answer to the given question. For any value of x lesser than 1, we would also be getting a "No" as the answer to the given question. As we are getting a definite answer i.e. a definite "no" - statement 2 alone is sufficient.
@elyungito8205
Жыл бұрын
@@Wizako Yep, thank you very much.
@abdiqadarbareh938
2 жыл бұрын
Where is the join option for this KZitem channel
@Wizako
2 жыл бұрын
Hi Abdiqadar, You can subscribe to our channel to receive regular GMAT-related content and updates. Thanks & Cheers! 🙂
@user-lg1rq1ih9j
Жыл бұрын
I am so confused. I got C as the answer for this question in another channel
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