Others here have suggested "improvements" but I'm glad that you kept it simple. (because this is an introduction) and I'm a beginner. To everyone else, give this guy a break!!! If you're so smart, then make your own KZitem videos.
@electronevice
10 ай бұрын
Thank you for the support! However, I do appreciate the suggestions people are posting in comments - it helps me to improve and see what kinds of things people are looking for regarding op-amp tutorial videos
@inductr
10 ай бұрын
I'm in as well ! May logarithm deities be with you!
@electronevice
10 ай бұрын
Thank you!
@frankg8400
11 ай бұрын
Excellent video.
@electronevice
11 ай бұрын
Thank you very much! I'm glad you liked it!
@yolamontalvan9502
10 ай бұрын
Thank you. It’s very clear to understand.
@electronevice
10 ай бұрын
Thanks!
@phillipzan2005
10 ай бұрын
So the one thing I like for this video for a complete beginner like myself, is the fact that you used a voltmeter and scope. My field is automotive diagnostics and programming. So I use a scope and a voltmeter all the time. I have gotten into circuit board repairs in the last few years. I am also a hobbyist and love electronics. I'm not sure of your target audience. But if you are trying to include beginners you might want to explain why there is a -10 volts on the power supply side of Op-amps and say not just 0 volts. I somewhat know because I have watched a lot of videos on Op-Amps. Other than that great start so far.
@electronevice
10 ай бұрын
Thanks! That's a good suggestion, I'll try to include that when I discuss op--amp power rails later
@paxsevenfour
10 ай бұрын
Really good explanation!
@electronevice
10 ай бұрын
Thank you!
@jessicahorvitz
9 ай бұрын
Awesome video!! Subscribed!
@electronevice
9 ай бұрын
Thanks for the sub!
@msg1956
11 ай бұрын
Excellent..!
@Graham_Wideman
8 ай бұрын
While applauding your initiative to create these tutorials, I am puzzled by the choice of "op" as the subscript to indicate "input", when the letters strongly suggest "OutPut" or possibly "Out, Peak". I checked a bunch of my EE texts but don't see anyone else using that mnemonic, and wonder what it represents or where it comes from?
@electronevice
8 ай бұрын
Thanks! I don't think it comes from anywhere, it's just the way I decided to annotate it. I did it that way primarily because for the inverting amplifier - which I get into in later videos - the input voltage and current for that amplifier circuit is not the same as the input voltage and input currents of the op-amp itself, so i want "Vin" and "Iin" to refer to the input voltage from the signal source. I figured having something like "Vin" be the circuit input and "Vin+" be the op-amp input might be more confusing. I could have used "V+" and "V-" for the op-amp inputs but that sometimes refers to the power rails. I didn't want to call the input voltage "Vs" because I wanted to reserve Vs for cases when the source voltage is not the same as the input voltage (e.g. function generator as source voltage with built-in source resistance) I'm sure there are other ways to do it, but since I label the diagrams, I figured it would be too confusing
@drdengineering819
11 ай бұрын
It's gold Jerry! It's gold!
@Swenser
10 ай бұрын
The op amp is square the circuit board is square . Should be called squareamp.
@ChandrashekarCN
11 ай бұрын
💖💖💖💖
@andrewphi4958
10 ай бұрын
I got confused a bit at the beginning when you started talking about descrete transistor op-amps. Turns out everything was told about op-amp ICs, not just op-amps in general. Otherwise, good presentation.
@electronevice
10 ай бұрын
I was talking about discrete transistor circuits in general like common-emitter, emitter-follower, common-base and their FET analogues, not discrete transistor op-amps specifically though it applies to those as well. In school we often make transistor circuits using resistive biasing networks to make amplifiers. It's a nice educational exercise, but in practice using an op-amp with its integrated biasing will usually generate a much better design so long as the design isn't too high bandwidth or needs to output a lot of current.
@lohikarhu734
11 ай бұрын
Just getting started, I see... only a few minutes into this one, but "lookin' good ” I'll subscribe, hope you get more on board soon... (I'm not quite a beginner 😹, but enjoy good content)
@electronevice
11 ай бұрын
Thank you for the subscription! I'm planning on doing a deeper dive into op-amps once I've covered some of the basics, so maybe that will appeal more to non-beginners like yourself
@petersage5157
10 ай бұрын
I like that you bypassed the [peewoop] out of the regulators and the op amp, but shouldn't you have had two bypass caps on the op amp? One from each of the rails to ground? I thought this was the preferred practice (though you often don't see *any* local bypass in commercial circuits).
@electronevice
10 ай бұрын
You are correct, it is the preferred practice because the input signal is ground-referenced and the gain-setting resistors are connected to ground as well. However, this IS a breadboard circuit with a relatively low frequency chip, and I didn't want to go overboard with the precision circuit design since it's generally unnecessary if you're intent is just a low-precision circuit. I also didn't connect the recommended feedback circuits for the 3 unused op-amps, I just left them open because, again, it's not that important for low precision designs that are just breadboarded. If it was a more permanent circuit, I would have probably paid more attention to the bypassing and the unused op-amps
@petersage5157
10 ай бұрын
@@electronevice Well, strapping off the unused op-amps as voltage followers is trivial, especially with a dual rail supply; it would have been only modestly more complicated with a resistive divider providing the ground reference. But I'm probably spoiling your lesson plan - carry on, Teacher.
@sergiosaveas8337
5 күн бұрын
Hello, I have a question: What happens when the two power sources are at significantly different values, let's say +12 VDC and -6VDC.? Will the op amp be destroyed? will it work, but with another gain? If tnis is explained in another video, would you please refer me to it? Thank you in advance for your response. Regards, Sergio
@electronevice
4 күн бұрын
Hi Sergio, In the non-inverting configuration that I used in the video, the op-amp itself does not have a concept of "where" ground is, since ground is not connected anywhere on the op-amp itself, it is only connected indirectly on the bottom of the resistive divider, and so what matters to the op-amp is the difference between VCC and VEE. So long as that difference is not too high (and that VCC is always higher in voltage than VEE), it will work fine. For the LM324 from the video, +12V - -6V = 18V is well within it's acceptable operating range. Apart from that, the power rails still limit the Vin and Vout range as I explain at around 5:33 - you can't put a voltage on the input that is outside the power supplies (or even too close to them) without bad things happening, and if you try to gain-up a signal so that the output would be outside the power rails, it will just be stuck near the maximum or minimum rail. That effect is shown in the brief demonstration around 14:30. Regarding the "bad things happening": If you put a voltage on the input of an op-amp just slightly (maybe 0.1V) outside the acceptable input range, you will first make it stop behaving properly as the transistors won't be able to be biased properly, then if higher voltage is applied (about 0.3V above the positive rail or below the negative rail) it will start drawing additional current through small ESD diodes on the inputs to each rail that will make the input no longer "high impedance". If you drive it with a low impedance source and keep increasing this voltage above 0.3V excess voltage, you can draw so much current that those ESD diodes will be destroyed, along with other circuitry they protect which will probably effectively destroy the op-amp. Setting up the op-amp (gain >1 and a high enough input voltage) so that it tries to output a voltage beyond its rails does NOT damage the op-amp at all, though it won't work like a proper op-amp as long as it is outputting near its rails. There is one further consideration, though it almost never causes much damage, it can perhaps stress the part and make some of the voltages look a little confusing: If you output a "too high signal" so that the op-amp "rails", and you push your input voltage even higher so that the voltage at the + input and - input are not close together as in the ideal configuration, AND if your specific op-amp has a pair of clamp diodes between the input lines (many do) then you can get current flowing through that clamp as it tries to keep the two inputs within around 0.3V of each other. You won't usually damage the op-amp unless your resistive divider resistance is very low, or your voltage input is very high, but it can do weird things to the output and input voltages (if there's source resistance). This effect is a little harder to explain without an example. Hope that helps,
@russcole5685
11 ай бұрын
So umm. Can this be used to piwer a small 12vdc motor frim using a 6vdc source. Eg, im trying to make a 12V servo for RC use. Most servis in market are 5-7.2V. Thinking of just taking the guts out if a cheap 5v servo, using a separate 12v battery and opamp to power a 12V motor for a stronger servo. Hopefully my explanation is readable
@ooltimu
10 ай бұрын
No. Opamps output a very small current. What you need is a boost converter
@russcole5685
10 ай бұрын
@@ooltimu thank you
@y_x2
10 ай бұрын
LM324 is one the worst op-amp on the market. Don't use this old one it is a real piece of sh*t...
@electronevice
10 ай бұрын
I generally agree with two caveats: 1. It's incredibly cheap, so if the design doesn't need to be precise or anything, there's no issue with using one 2. All its various flaws make it a great op-amp to study when looking for non-idealities of op-amps because they're easier to see with the LM324
@MikeU128
9 ай бұрын
It is perfectly adequate for demonstration purposes. It's also ridiculously cheap, and (being bipolar instead of CMOS) relatively insensitive to ESD, both of which make it ideal as a learning tool.
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