Explanation: The room starts containing Patrick (P), itself (A), A clone of itself (Ac), and a second, flipped clone of itself (Acf), as well as its epsilon-level (Aep). Also there's a possessable wall (W) that needs to get used for some of the hijinks. The first movements from 0:14 to 0:19 are basically just to get a wall into position so we can do stuff we couldn't otherwise do. It ends up jutting out from the main wall so that if we push something against it we can pull it back off, and also in position near the exit so we can do the other thing we need later. So first we push the flipclone Acf against W so we can push A into the flipclone, which gets us the _flipped_ copy of A. This means A is now inside a flipped version of itself instead of the regular version. Then we push Acf south of W which is where we'll need it for later. Now we need to get to Aep. To do this we need to _infinitely enter A._ So we position the clone Ac at the exit of the A room we're in, and then the flipped A to the left of it (which is also south of Acf). Then we try to move rightward into the flipped version of A. The move algorithm does the following set of checks at 0:33 resulting in us going to Aep: P tries moving right. That space is occupied by flipped A. P tries pushing A right... ( A tries moving right. That space is occupied by Ac. A tries pushing Ac right... ( Ac tries moving right. That space is out of bounds of the room It's in, so Ac tries exiting. That space (now in flipped coords) is occupied by P. Ac tries pushing P but P (in the flipped version) is pushing left against it. So Ac fails to push P. Ac can't enter P and can't eat P, so Ac fails to move right. )... A fails to push Ac right. A then tries to enter Ac, but it can't (there's a wall). A can't eat Ac either. So A fails to move right. )... P fails to push the flipped A right. P then tries to enter the flipped A. That space is occupied by Ac. So P tries to enter Ac. But Ac is a clone of A. So P tries to enter A. Welp, that's a loop - P trying to enter A causes P to try to enter A, so P would be entering A infinitely many times. So P tries to enter Aep instead. That space is unoccupied, so this succeeds. P succeeds in moving right, by moving directly into Aep (incidentally, leftward, because it got there by infinite-entering a flipped version of A), and nothing else moves. Then P leaves Aep to the north and is back inside A. Now we need to get to the goal. Outside of the room we're in, to the north, there appears to be another clone copy of it we can walk directly into. That clone is actually Acf (but flipped) - because north of the flipped version of A is the flipclone Acf that we put there earlier. And Patrick _can_ walk north directly into Acf at 0:35 (via Transfer) because Acf is stuck against wall W so Acf won't get pushed instead. Thereby we get to the goal.
@M_rld
2 жыл бұрын
very nice explanation!
@dafurious6457
2 жыл бұрын
Very cool level
@syndere6755
2 жыл бұрын
This is certainly a strange way to reach Epsilon.
@darkbrick9098
2 жыл бұрын
funny seeing the whole babacord in the chat here
@hatsukegero
2 жыл бұрын
ho nyo, i came from the infinity 3 video, imagine if you have to reach infinite 3 and £ 3 to get to the goal?
@hexagon8899
2 жыл бұрын
i think in the main game there is a level where you have to do 10x infinity AND 10x epsilon (the infinitely small one)
@Arrow-Pointer
2 жыл бұрын
@@hexagon8899 yeah i remember that one
@nif4345
2 жыл бұрын
Hi
@MrRhombus
2 жыл бұрын
Is this new update?
@sangchoo1201
2 жыл бұрын
custom level. they can be found in Patrick's Parabox discord
@aadenboy
2 жыл бұрын
what the fuck jjust happened
@M_rld
2 жыл бұрын
parabox
@AexisRai
2 жыл бұрын
I posted an explanation but accidentally posted it as a main comment instead of as a reply here, so go read it there because I can't copypaste it here and delete it there or else YT will think I'm spamming
@rybo4663
2 жыл бұрын
@@AexisRai Explanation: The room starts containing Patrick (P), itself (A), A clone of itself (Ac), and a second, flipped clone of itself (Acf), as well as its epsilon-level (Aep). Also there's a possessable wall (W) that needs to get used for some of the hijinks. The first movements from 0:14 to 0:19 are basically just to get a wall into position so we can do stuff we couldn't otherwise do. It ends up jutting out from the main wall so that if we push something against it we can pull it back off, and also in position near the exit so we can do the other thing we need later. So first we push the flipclone Acf against W so we can push A into the flipclone, which gets us the flipped copy of A. This means A is now inside a flipped version of itself instead of the regular version. Then we push Acf south of W which is where we'll need it for later. Now we need to get to Aep. To do this we need to infinitely enter A. So we position the clone Ac at the exit of the A room we're in, and then the flipped A to the left of it (which is also south of Acf). Then we try to move rightward into the flipped version of A. The move algorithm does the following set of checks at 0:33 resulting in us going to Aep: P tries moving right. That space is occupied by flipped A. P tries pushing A right... ( A tries moving right. That space is occupied by Ac. A tries pushing Ac right... ( Ac tries moving right. That space is out of bounds of the room It's in, so Ac tries exiting. That space (now in flipped coords) is occupied by P. Ac tries pushing P but P (in the flipped version) is pushing left against it. So Ac fails to push P. Ac can't enter P and can't eat P, so Ac fails to move right. )... A fails to push Ac right. A then tries to enter Ac, but it can't (there's a wall). A can't eat Ac either. So A fails to move right. )... P fails to push the flipped A right. P then tries to enter the flipped A. That space is occupied by Ac. So P tries to enter Ac. But Ac is a clone of A. So P tries to enter A. Welp, that's a loop - P trying to enter A causes P to try to enter A, so P would be entering A infinitely many times. So P tries to enter Aep instead. That space is unoccupied, so this succeeds. P succeeds in moving right, by moving directly into Aep (incidentally, leftward, because it got there by infinite-entering a flipped version of A), and nothing else moves. Then P leaves Aep to the north and is back inside A. Now we need to get to the goal. Outside of the room we're in, to the north, there appears to be another clone copy of it we can walk directly into. That clone is actually Acf (but flipped) - because north of the flipped version of A is the flipclone Acf that we put there earlier. And Patrick can walk north directly into Acf at 0:35 (via Transfer) because Acf is stuck against wall W so Acf won't get pushed instead. Thereby we get to the goal.
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