If log (base 2) k = 1/2 and csc θ = k, where 90° ≤ θ ≤ 270°, then the value of ≤, to the nearest degree, is ______°
Негізгі бет Pre-Calculus
No video
If log (base 2) k = 1/2 and csc θ = k, where 90° ≤ θ ≤ 270°, then the value of ≤, to the nearest degree, is ______°
Пікірлер