Want to say goodbye to the ad"what! still searching math help from youtube?" yes, i am still doing that and it is really helpful and free
@adeelali8417
5 жыл бұрын
lmao that ad pissed me off so bad. Oh and Use adblocker.
@jayceinfinitealgharhythmns9814
5 жыл бұрын
Don't use adblocker... it demonetizes his videos. If at possible watch the ads and let them play through and show him some support. Beside I don't mind them spending money on a product I'll never buy to support ones I would pay for.
@pedroafonso8384
5 жыл бұрын
Exactly
@lynettealexandragonzalez7173
5 жыл бұрын
7 months later and I get the same ad
@ilanzatonski8826
4 жыл бұрын
Just got it now..
@zepherinkevinfrancis7539
4 жыл бұрын
Thank you so much, you are a godsent, my Calculus 1 Professor is making me learn this on my own and you just saved my life
@Dap-ri2yh
3 жыл бұрын
relateable
@kinaxx7521
3 жыл бұрын
Fr in that situation rn 😭
@chocoflan9394
3 жыл бұрын
I feel you
@maniksethi551
4 жыл бұрын
DUDE THANK YOU SO MUCH THIS IS ABSOLUTELY CRAZY THIS MAKES SO MUCH SENSE NOW.
@patrickjmt
4 жыл бұрын
Glad it helped!
@Nomul16
5 жыл бұрын
Thankyou so much, my professor didn't do a great job of showing this and now it all makes sense!
@blessinggorengecho3973
8 жыл бұрын
I really don't know what I would do without you sir. Thank you ver much...
@henrycolvin3473
2 жыл бұрын
I don't know what the difference between my textbook and my professor and you is, but something just clicked watching this. Thank you so much, you are saving my grades.
@sgtcojonez
9 жыл бұрын
I feel so bad because I finished all three CALs and now I am in differential equations, but I was never able to master this proof. I just hate the stupid epsilons man.HAHAHAHA. Thank you for the video Patrick.
@Harjindersingh-xv9xu
4 жыл бұрын
Hey. I now understand how this relates to the overall picture of limits definition that is for every epsilon we have a delta, but things would be even better if we approached this problem from a geometric perspective: getting delta from a graph. And thanks for your videos!
@blacktape52black72
3 жыл бұрын
lol it took me a month to figure out derivates means rate of change at point.
@EfeAikpokhio
2 жыл бұрын
@@blacktape52black72 lol XD
@naghmeharmanieh
7 жыл бұрын
so clear! never understand the concept of precise limit but u just cleared that out
@jshringo77
4 жыл бұрын
Thank you so much! Wayyyy better explanation than my professor.
@shancunma6001
3 жыл бұрын
This video explains the precise definition better than the other one you showed. thx ✌️
@GagandeepKaur-km2rj
3 жыл бұрын
thank you so much. I was thinking I'm never gonna get this concept ..but after watching this video, I feel like I got it.
@craigt8432
2 жыл бұрын
This video saved me from poor instruction. Thank you sm
@protestant_mezmur1
Жыл бұрын
I regrettably feel that after finishing and currently studying differential equations, I was never able to fully understand this proof. Thank you to my advisor for pointing me in the right direction.
@HK-ni6cn
Жыл бұрын
oh my god i love u😭i was struggling so hard
@kwirkLA
9 жыл бұрын
Wow, perfect timing to post this...my first calc1 test in a few hours and this proof is the hardest concept of the first section.
@uyujnnqaal
3 жыл бұрын
Yo how did the test go?
@kwirkLA
3 жыл бұрын
@@uyujnnqaal lol I ended up dropping the class, didn't need this level of calc for my major it turned out
@ChefFarisMom3
2 жыл бұрын
I can't express my gratitude 💕💕💕💕
@beegalgo1757
6 жыл бұрын
Thank you very much sir!! Your channel helps and motivates mi in school 😊
@patrickjmt
6 жыл бұрын
happy to help you :)
@danielzambrano7487
7 ай бұрын
Great video thanks man!
@noahmnyenyembe1559
6 жыл бұрын
Thank you very much Mr Patrick. Now am confident enough that i will muster calculus!!!
@t.r.icraftsworld8389
3 жыл бұрын
Super explanation sir I could really understand your lecture
@MtlFT
9 жыл бұрын
If only I had this last week or my calc1 test!
@parsat5567
6 жыл бұрын
Thanks dude, got exam tomorrow and it really helped
@ttviper9t
9 жыл бұрын
i subbed and it was worth it. Thanks Mate!
@FredHandle1
3 ай бұрын
It seems [to me] that this epsilon-delta strategy can only affirm a limit, if the function behaviour is well behaved around the point of discontinuity. Which presupposes prior knowledge of the behaviour of the function. That would make the proof, self serving, in that it aims at proving a property thats already evident. By well behaved, I mean that the function is either sequentially increasing/decreasing on either side of the proposed limit. What about irregular functions that make jumps in F(x) as we get closer to the proposed limits? I really don't know, so I need some coaching. May be it would be helpful if we began with a definition of the types of functions where this approach can work or not. TYSM for the vid
@InnocentErasto-v5b
8 ай бұрын
Thank you buddy❤
@lyricc9
3 жыл бұрын
NOW I UNDERSTAND THANK YOU!
@berylni7806
8 жыл бұрын
Thanks! I love your video!
@navidmafi
2 жыл бұрын
YEAHH NOOWWW I UNDERESTAND IT THANK YOU LETS GOOOOOOOOOOO
@marcushines4172
8 жыл бұрын
Thanks for all the videos bro. Listen, can you do an example where the inequality cannot be solved algebraically, so you have to "enlarge" the function in order to get something that CAN be solved, then from there prove that the enlarged function is less than epsilon, which proves that the original function we started with is ALSO less than epsilon since its smaller than the function we enlarged. I hope I was able to explain what I'm asking.
@argoneus21
3 жыл бұрын
THIS IS GEM! THANKSSSS!
@quiet6740
7 жыл бұрын
i don't understand why E/2 = DELTA. for example: 6
@kagayakuangel5828
4 жыл бұрын
@@bilaltariq7819 you neglect to mention that epsilon is totally arbitrary and delta DEPENDS on epsilon....and how crucially important that is....but still FACTS. Lol for example if you have a function f(x) = 2x 2x = 10 < 11 and 2x = 4 < 11 SURELY, you ain't gonna say 10 = 4 lol.... It's more like f(epsilon) = delta so to speak. So since f(epsilon) = delta we have f(epsilon) = (1/2)E = E/2 = delta. If he didn't work the other way, it would be a prank. lol A complete s c a m.
@batteryjuicy4231
11 ай бұрын
I don't get why this isn't a tautology. You basically did some math, then you did the opposite steps to get back to where you started and somehow that is a proof?
@anzatzi
6 жыл бұрын
Saying ' just reverse the steps' is very confusing--you should focus on the implication issue. great video!
@betterfly7398
3 жыл бұрын
Indeed! This is why I couldn't get it. I was like, why in the hell are we doing the same thing, but in reverse order?! of course we're going to get the same thing!
@XFOYS
5 жыл бұрын
Sangat Membantu, Terima Kasih ( Indonesia) = So helpfull, Thank You this video helps me to pull an all-nighter cause my (smart) lecturer :D
@2Berm1
9 жыл бұрын
Nice explanation.
@azyle2104
4 жыл бұрын
Thank you
@fuatutku
6 жыл бұрын
Patric u are amazing i've learnt things from u in two nights watching u is also enjoyfull.u deserve fucking oscar prize
@nicktokar2459
6 жыл бұрын
I sure love that i'm taking calculus as a biology student. But, this was actually very helpful.
@patrickjmt
6 жыл бұрын
You should be taking Calculus if you are a Biology student though...
@aasthasharma7161
4 жыл бұрын
thank uh so much sir🥰
@patrickjmt
4 жыл бұрын
Most welcome
@aasthasharma7161
4 жыл бұрын
@@patrickjmt can you plz make more vedios on this topic🤗. Love from india
@janerouge5541
6 жыл бұрын
helps a lot!! thanks!
@mrinalchoudhary7525
5 жыл бұрын
Tqsm sir 😍
@myeshafarzanatahi9154
3 жыл бұрын
Thank you a lot lot lot lot lot lotttttt
@edwardkarak2517
4 жыл бұрын
Shouldn't it be 0 < |x-a| < δ, not just |x-a| < δ, to ensure x≠a?
@denisvalentin4258
4 жыл бұрын
Yes, that's true. He probably didn't write it to simplify things.
@taysstudyblog3971
2 жыл бұрын
Im awestruck
@brendanfinnie8233
6 жыл бұрын
makes sense that a left handed person is tutoring calculus XD
@zigooo_5611
5 жыл бұрын
this is beautiful
@yesboss2800
3 жыл бұрын
1st : absolute of function is less than e and prove absolute of points less than a manipulation ( related to e which is dell ) 2nd : now take that absolute of points less than dell (but put manipulated value) will always implies absolute of function is less than e
@diablohorer
3 жыл бұрын
But HOW did you decide that delta=epsilon/2?
@nurizyannabilah5580
4 жыл бұрын
Thank sir
@r.sorker2590
3 жыл бұрын
very nice
@kleodavelajarca7479
6 жыл бұрын
Thank You! :)
@faighashimli1452
9 жыл бұрын
Thx Man :)
@belaladeb5818
3 жыл бұрын
Hi,What are u study?
@rodolfowehrhahn569
8 жыл бұрын
amazing .....but did you choose delta to = epsiolon/2 becaue you knew it would work or would it still have worked if say you chose delta to = epsilon/3
@amirullahkhan11
8 жыл бұрын
It will work with ε/3 suppose delta = ε/3 |x-4| < ε/3 2|x-4| < 2ε/3 |2x-8| < 2ε/3 but 2ε/3 is less then ε (2ε/3 < ε) so.. |2x-8| < ε see he choose it as ε/2 just to make it easy.
@sudheerthunga2155
4 жыл бұрын
If it works for anything why specifically epsilon/2?
@cadu7698
4 жыл бұрын
@@sudheerthunga2155 Because epsilon/2 kind of encapsulates all the other cases. Taking from the example above, if you directly deduce that |2x-8|
@sudheerthunga2155
4 жыл бұрын
@@cadu7698 Epsilon /2 is the minimum distance,right??
@cadu7698
4 жыл бұрын
@@sudheerthunga2155 That would imply that x can be as far as you want it to be from 4, as long as it's E/2 "units" from it, which is a wrong assumption.
@seadric6372
5 жыл бұрын
When I look through my textbook, they randomly get values for delta and then I get confused because idk how they did it
@blacktape52black72
3 жыл бұрын
and now you know?
@cbranalli
6 жыл бұрын
it would help if you could show a case where the limit DOES NOT exist - eg at a step discontinuity.
@vatitopatitopotitopolitopo4918
3 жыл бұрын
thx
@BangMaster96
4 жыл бұрын
Don't get confused by all the technical terms guys. The simple intuition behind limit is the value approached by a function as the input approaches a certain value. That's all, the epsilon and delta definition is stating the same thing. As long as you understand the meaning of what a limit is, you don't need to know the technical confusing terminology.
@gauthampracharya9592
3 жыл бұрын
Give a smart guy a sharpie and a camera, and he will do wonders!
@juan3141
4 жыл бұрын
the only part im confused on is why youre allowed to say L = E / 2 ?
@sophita_
9 жыл бұрын
Thank yooouuu!
@erickfranciscogudinoperez7327
5 жыл бұрын
Cool thank you
@_ohamachi
Жыл бұрын
Hello can you reverse |x-a|
@davidhou4256
6 жыл бұрын
thx bro, IM FROM TUCKER.
@ledah8165
5 жыл бұрын
Did you use Differential and Integral Calculus by Love & Rainville as a reference for this video?
@BrickTavernFilms
6 жыл бұрын
The philosophizing is necessary
@prestonjensen6172
9 жыл бұрын
Hey Patrick! Just curious, is this your main job, or do you have a day job?
@dskchari9469
4 жыл бұрын
Here what is meant by Delta and epsilon exactly .can we take any other letter instead of them as which means small +ve number
@rushel4608
3 жыл бұрын
My professor did it by getting a inequality for f(x) - L from the delta and then he chosed a ephsilent for that delta is it correct? Sorry for my english
@fluffycharizard8835
6 жыл бұрын
plz can you show how to prove lim 1/(1-x)^2 = infinity x tends to 1
@Mr.X-qu1lw
5 ай бұрын
Why epsilon over 3 over 4 and all will work....???please help
@dantecastillodelasfuentes1026
5 жыл бұрын
In what part of the limit definition it´s said that the point can´t be L? or a ?
@vedinmuratovic2274
4 жыл бұрын
I am confused about the part where we let delta = epsilon/2. Why does this work because wouldn't substituting ABS x-4 make it so that delta is less than epsilon/2
@blacktape52black72
3 жыл бұрын
becase abs x-4 = delta.
@josuedelatorre35
6 жыл бұрын
What if you get a problem where a is a negative number?
@miso-ge1gz
Жыл бұрын
what do you mean prove it just does
@yesboss2800
3 жыл бұрын
Watch from 3:40
@zacharyddrzipac
7 жыл бұрын
What I learned: if 1+1=2, then subtract 1 from both sides: 1=2-1 1=1, then let 1 equal to 1, 1=1 add one to both sides: 1+1=1+1 which is also equal to 1+1=2 BOOM here you go, enjoy your accomplishments, you've proved absolutely nothing.
@abdoxd2911
3 жыл бұрын
Are you still there? Well just wanted to say that you are the only comment that made me laugh in this horror movie Thx for it
@dantaemartin7326
9 жыл бұрын
AMAZING
@dantaemartin7326
9 жыл бұрын
😄😄😄😄😄😄😄
@paulpassiglia9997
7 жыл бұрын
Praise
@xXxilovecatsxXx
5 жыл бұрын
can't even watch this with his hand in the way of everything written had to pause like 125 times ... leftys
@Tiktok-hk8vg
9 жыл бұрын
nice but can you please make a video to help me do better in algebra one thank you
@SkyMine911
6 жыл бұрын
what about the pre-proof?
@r.sorker2590
3 жыл бұрын
i want to get solution of the end
@chrislliatsos
5 жыл бұрын
im confused, how is it mathematically proven that "delta" is equal to "epsilon dived by 2?" thanks guys
@garrettnicolay6310
4 жыл бұрын
I know its been awhile since you posted this but the reason delta = epsilon divided by 2 is simply that we are letting delta = epsilon divided by 2. We wanted to find out what we needed to set our delta value equal to so that we could get | 2x + 3 - 11|. If you ever take Calc 3 this will still be useful to know when taking limits in multiple variables.
@garrettnicolay6310
4 жыл бұрын
It just makes it easier to solve
@Aa_1220_
2 жыл бұрын
thank you for the explanation. Please use a normal pen or pencil while writing on a paper
@oguztizlak2699
5 жыл бұрын
Güzel anlatım 👍
@vahsibatljohnny6682
2 жыл бұрын
Bizim yarak kafalı hocalardan bin kat iyi
@oguztizlak2699
2 жыл бұрын
@@vahsibatljohnny6682 😂
@rohandandi5999
5 жыл бұрын
bro can you tell me express this definition of limit using quantifiers
@SinaHeidari522
4 жыл бұрын
god bless
@Abdullah-nc2vd
6 жыл бұрын
This epic
@erickgaray463
6 жыл бұрын
can epsilon be negative? i ended up with -E/3 on one problem.
@patrickjmt
6 жыл бұрын
epsilon is defined to be a small positive number
@erickgaray463
6 жыл бұрын
i found that out the hardway lol, thanks!
@milastevanoska536
2 жыл бұрын
a?
@rima7286
4 жыл бұрын
DUUUUUUUUUDEEEEEEEEEEEEEE
@the-dan-signal3595
6 жыл бұрын
I understood everything except for the part where you said we could use epsilon/3 or epsilon/4 and it would still work. At that one moment you completely lost me
@SupaThePink
6 жыл бұрын
To prove that this limit exists and satisfy the definition, we need to establish a relationship between δ and ε such that, if x is within δ of a, f(x) is within ε of L. For example, say we find that δ is ε/2 for a particular limit, and say we arbitrarily pick 4 for ε. This means that, in order for f(x) to be no more than 4 away from L, x must be no more than 2 from a. If we change δ to ε/4, this definition is still satisfied because for an ε of 4, we have a δ of 1, and an x no more than 1 away from a still produces an f(x) no more than 4 from L. We can make δ whatever we want as long as it is not more than ε/2. Basically, we can make the tolerances for δ as strict as we like, but we cannot make them more lenient. If δ is greater than ε/2 in this example, f(x) will no longer be within the desired distance of L, and the definition cannot be satisfied.
@win4cambo
5 жыл бұрын
delta = 0.00000000000000001 and epsilon = 0.000000000000000002 make a tiny difference.
@arumteguh2762
5 жыл бұрын
quentin tarantino?
@Jyotikumari-hq1ut
6 жыл бұрын
You are reading from thomas calculas
@StephaniePennings
11 ай бұрын
So hard to see anything with your hand in the way. I had to keep rewinding to see what was under your hand. What should have been around a 7 minute video took me nearly 30 minutes to watch. Also, there's only one example and more are needed to fully understand this topic.
@comfycozyarewe388
5 жыл бұрын
😸
@DanT-iu6oc
5 жыл бұрын
god this is never going to make any sense to me. i give up on precise definition of a limit. this is just totally beyond my INTELLIGENCE.
@cadu7698
4 жыл бұрын
Well, I kind of started getting it just now, and I've attended around four Calculus courses... so keep trying and someday it will make sense (that's not supposed to sound pessimistic).
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