Can't stop laughing at those classical engineering crazy approximations like t^2 = 0
@ranadebray5440
Жыл бұрын
How to check the Pressure vessel integrity for the ‘full vacuum’ condition of 1 bar external pressure? May you please answer this question.
@inspectioncorrosion
2 жыл бұрын
Very well explained
@PrabaKaran-cq5bt
2 жыл бұрын
Can you please create videos for valve design and calculations
@aleksandrsnaumovs4277
7 жыл бұрын
ok....longitudinal stress is 1/2 of the hoop stress. Clearly that is the case since pressure vessels rupture along the axis of symmetry. Ok got that...now why exactly a sphere is a better engineering solution? For given pressure it induces 2x as much stress in the hoop direction than the axial direction. If anything the conclusion should be: a cylinder is a great variation of sphere and the axial stress is less than the hoop stress, which is quite fortunate. BTW...wouldn't you ant to calculate a combined Von Messes stress? I mean...you are stretched in Y and -Y and also X and -X (only 50% less). Still...shouldn't that add up to a resulting means tress which is a sum of the two directions?
@EngineeringandDesignSolutions
6 жыл бұрын
A sphere is better because it has no hoop stress, thus it will be twice as strong for the same pressure AND it is the most efficient shape in terms of surface area:volume. A Von Mises stress calcaluation would be a great next step. However, that's not covered in this particular course. I'd love to, but I run out of time! Thanks for watching and commenting!
@lst1012nyc
6 жыл бұрын
I'm probably wrong, but isn't the surface area of a sphere = 4*π * r2 and the area of each 1/2 sphere = 2πr2?
@EngineeringandDesignSolutions
6 жыл бұрын
Nope, you're right, but to find the force for the stress *normal to the plane of the cross-section of the tube*, one only needs to calculate the area of the fluid in the plane of the cross-section of the tube, not the force on the entire half-sphere. The forces on the entire half-sphere a) are in a variety of directions and b) the ones that aren't along the axis (any in y or z) all cancel each other out, leaving only those in x, and those are only normal to that x-sectional plane. I hope that helps. Thanks for watching and commenting!
@allanbancroft4692
7 жыл бұрын
id like to make a rectangular pressure vessel to hold 60 PSI measuring L=8.25 ' W=4.5' H=1' but am uncertain if this concept is possible. This vessel will not have heat applied and is for casting purposes. any thoughts?
@EngineeringandDesignSolutions
6 жыл бұрын
ep5tv is pretty much dead-on. If you're still set on it, research all the rectangular pressure vessels you can find. You may decide to change your strategy.
@avid0g
4 жыл бұрын
Can you place the rectangular mold inside a standard spherical/tubular pressure vessel?
@youngseobwon6621
6 жыл бұрын
Can anybody tell me about the program in 5:25?
@ukdave472
6 жыл бұрын
can't say the name of software, but it is easy to write in any ordinary program like word or even mspaint
@ukdave472
6 жыл бұрын
looks like MATH CAD PTC
@ggpopa1319
6 жыл бұрын
SolidWorks
@EngineeringandDesignSolutions
6 жыл бұрын
Yes, it is SolidWorks, also using the stress calculator that can come with it. I highly recommend SolidWorks, but it can be a bit pricey.
@vishank7
4 жыл бұрын
Hello! Can you please explain how the area in hoop stress equal Di*length and not Pi*r*l? Thanks already!
@avid0g
4 жыл бұрын
kzitem.info/news/bejne/q5dmmX5ni4Nke6w
@FuseConductor
4 жыл бұрын
we are taking at that strip not at all over semi sphere
Пікірлер: 23