I seem to be missing out on a lot of topics as I'm more confused after watching this.
@lescitrons
5 жыл бұрын
These videos are just what I'm looking for!
@M7medKasem
9 ай бұрын
Very thankful for your effort
@primalmachine7945
6 ай бұрын
hold on! isnt it making things more complicated?! if we know ¬q =T that means that q=F and then we can see p->(q v r) such as: (p->(F v r)) =T (its given that its true) and then p->r = T in order for p->(F v r) to be true as needed, either p=F and r=F meaning F->F=T, or p=T and r=T meaning T->T=T, either way it doesnt.
@crazyhead3347
Жыл бұрын
thank you
@Concert746
2 жыл бұрын
Thank you!
@nathansnead7371
Жыл бұрын
Thanks
@zeaddawode4620
3 жыл бұрын
help please I was asked in my assignment to proof this in two methods.. p→¬q (q∧r)→¬s r∧s ∴¬p and i did use truth table and it is invalid how am i supposed to proof that in rules of inference ?
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